Android 如何从xml中定义的drawable获取位图?

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时间:2020-08-20 02:31:10  来源:igfitidea点击:

How to get a Bitmap from a drawable defined in a xml?

android

提问by kaneda

How can I get the bitmap from a xml shape drawable. What am I doing wrong?

如何从可绘制的 xml 形状中获取位图。我究竟做错了什么?

shadow.xml

影子文件

<shape xmlns:android="http://schemas.android.com/apk/res/android"
    android:shape="rectangle" >

    <gradient
        android:angle="270.0"
        android:endColor="@android:color/transparent"
        android:startColor="#33000000"
        android:type="linear" />

    <size android:height="7.0dip" />

</shape>

My method to retrieve the bitmap from drawable:

我从drawable中检索位图的方法:

private Bitmap getBitmap(int id) {
    return BitmapFactory.decodeResource(getContext().getResources(), id);
}

getBitmap() is returning null when the id passed in is the shadow.xmldrawable id.

当传入的 id 是shadow.xml可绘制 id时,getBitmap() 返回 null 。

采纳答案by JRaymond

a ShapeDrawable doesn't have a bitmap associated with it - its sole purpose is to be drawn on a canvas. Until its draw method is called, it has no image. If you can get a canvas element at the place where you need to draw the shadow, you can draw it as a shapeDrawable, otherwise you might need a separate, empty view in your layout with the shadow as a background.

ShapeDrawable 没有与之关联的位图 - 它的唯一目的是在画布上绘制。在调用它的 draw 方法之前,它没有图像。如果你能在需要绘制阴影的地方得到一个canvas元素,你可以将它绘制为shapeDrawable,否则你可能需要在你的布局中一个单独的空视图,以阴影为背景。

回答by vovahost

This is a fully working solution:

这是一个完全有效的解决方案

private Bitmap getBitmap(int drawableRes) {
    Drawable drawable = getResources().getDrawable(drawableRes);
    Canvas canvas = new Canvas();
    Bitmap bitmap = Bitmap.createBitmap(drawable.getIntrinsicWidth(), drawable.getIntrinsicHeight(), Bitmap.Config.ARGB_8888);
    canvas.setBitmap(bitmap);
    drawable.setBounds(0, 0, drawable.getIntrinsicWidth(), drawable.getIntrinsicHeight());
    drawable.draw(canvas);

    return bitmap;
}

And here is an example:

这是一个例子:

Bitmap drawableBitmap = getBitmap(R.drawable.circle_shape);

circle_shape.xml

circle_shape.xml

<?xml version="1.0" encoding="utf-8"?>
<shape
    xmlns:android="http://schemas.android.com/apk/res/android"
    android:shape="oval">
    <size
        android:width="15dp"
        android:height="15dp" />
    <solid
        android:color="#94f5b6" />
    <stroke
        android:width="2dp"
        android:color="#487b5a"/>
</shape>

回答by Selcan

You should add size attribute to your shape drawable for preventing "java.lang.IllegalArgumentException: width and height must be > 0".

您应该向可绘制的形状添加 size 属性,以防止“java.lang.IllegalArgumentException: width and height must be > 0”。

<shape xmlns:android="http://schemas.android.com/apk/res/android"
       android:shape="oval">
       <solid android:color="@color/colorAccent" />
       <stroke
           android:width="1.3dp"
           android:color="@color/white" />

       <size android:height="24dp" android:width="24dp"/>
</shape>