Javascript 正则表达式匹配标签之间的文本
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Regex match text between tags
提问by wong2
I have this string:
我有这个字符串：
My name is <b>Bob</b>, I'm <b>20</b> years old, I like <b>programming</b>.
I'd like to get the text between btags to an array, that is:
我想将b标签之间的文本放到一个数组中，即：
['Bob', '20', 'programming']
I tried this /<b>(.*?)<\/b>/.exec(str)but it will only get the first text.
我试过这个，/<b>(.*?)<\/b>/.exec(str)但它只会得到第一个文本。
回答by Engineer
/<b>(.*?)<\/b>/g
Add g(global) flag after:
在以下位置添加g( global) 标志：
/<b>(.*?)<\/b>/g.exec(str)
//^-----here it is
However if you want to get all matched elements, then you need something like this:
但是，如果你想获得所有匹配的元素，那么你需要这样的东西：
var str = "<b>Bob</b>, I'm <b>20</b> years old, I like <b>programming</b>.";
var result = str.match(/<b>(.*?)<\/b>/g).map(function(val){
return val.replace(/<\/?b>/g,'');
});
//result -> ["Bob", "20", "programming"]
If an element has attributes, regexp will be:
如果元素具有属性，则 regexp 将是：
/<b [^>]+>(.*?)<\/b>/g.exec(str)
回答by Esailija
var root = document.createElement("div");
root.innerHTML = "My name is <b>Bob</b>, I'm <b>20</b> years old, I like <b>programming</b>.";
var texts = [].map.call( root.querySelectorAll("b"), function(v){
return v.textContent || v.innerText || "";
});
//["Bob", "20", "programming"]
回答by Bali Balo
Use matchinstead, and the g flag.
使用match和 g 标志。
str.match(/<b>(.*?)<\/b>/g);
回答by xdazz
Try
尝试
str.match(/<b>(.*?)<\/b>/g);
