xml 根据 xslt 中的条件将字符串分配给变量
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Assigning a string to a variable depending on condition in xslt
提问by harsh
I want to assign a value to a variable if a particular attribute returns a particular value. In here I want to assign the value "young" to vaiable "person" if pr:all/[@pr:name=current()/@cx:name]/pr:properties/(@ls:middlename) is "cengie". Is that possible?
如果特定属性返回特定值，我想为变量赋值。在这里，如果 pr:all/[@pr:name=current()/@cx:name]/pr:properties/(@ls:middlename) 是“cengie ”。那可能吗？
<xsl:variable
name='person' select='pr:all/[@pr:name=current()/@cx:name]/pr:properties/(@ls:middlename)'>
</xsl:variable>
回答by Tim C
You can put any xslt code within an xsl:variableand the result will be assigned to the variable. In this case you could make use of an xsl:ifto check your condition
您可以将任何 xslt 代码放在xsl:variable 中，结果将分配给该变量。在这种情况下，您可以使用xsl:if来检查您的情况
<xsl:variable name="person">
<xsl:if test="pr:all[@pr:name=current()/@cx:name]/pr:properties[@ls:middlename='cengie']">
<xsl:text>young</xsl:text>
</xsl:if>
</xsl:variable>
If you wanted an 'else' case here, you would use xsl:chooseinstead.
如果您想要这里的“else”案例，您可以使用xsl:choose代替。
回答by Ondra ?i?ka
Check this: https://github.com/wildfly/wildfly/blob/master/testsuite/integration/src/test/xslt/enableTrace.xsl
检查这个：https: //github.com/wildfly/wildfly/blob/master/testsuite/integration/src/test/xslt/enableTrace.xsl
<xsl:template match="//l:subsystem/l:periodic-rotating-file-handler" use-when="$trace">
<xsl:choose>
<xsl:when test="$trace='none'">
...
</xsl:when>
<xsl:otherwise>
...
</xsl:otherwise>
</xsl:choose>
</xsl:template>
Apply that to your code...
将其应用于您的代码...
回答by Dimitre Novatchev
<xsl:variable name='person' select='pr:all/[@pr:name=current()/@cx:name]/pr:properties/(@ls:middlename)'> </xsl:variable>
<xsl:variable name='person' select='pr:all/[@pr:name=current()/@cx:name]/pr:properties/(@ls:middlename)'> </xsl:variable>
This is syntactically illegal XPath -- both 1.0 and 2.0. A location step cannot start with a predicate. The offending substring is: /[.
这是语法上非法的 XPath - 1.0 和 2.0。位置步骤不能以谓词开头。有问题的子串是：/[。
Another syntax error(this time XML-well-formedness one) is that the <xsl:variable>element quoted above is not closed.
另一个语法错误（这次是 XML 格式错误）是<xsl:variable>上面引用的元素没有关闭。
You need to correct this.
你需要纠正这个。
Besides this, here is an XSLT 2.0 solution (with the syntax of XPath expression quoted above and of the <xsl:variable>corrected:
除此之外，这里是一个 XSLT 2.0 解决方案（使用上面引用的 XPath 表达式的语法和<xsl:variable>更正的：
In XSLT 2.0:
在 XSLT 2.0 中：
<xsl:variable name="person" as="xs:string?" select=
"'young'[current()/pr:all[@pr:name=current()/@cx:name]
/pr:properties
[@ls:middlename='cengie']
]"/>
