如何将 TypeScript 对象转换为普通对象？
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How can I convert a TypeScript object to a plain object?
提问by self.
I'm using a JS library, specifically select2that acts a tad differently than I'd like if the objects I'm passing it aren't plain objects. This is all checked by using jQuery's isPlainObjectfunction.
我正在使用一个 JS 库，特别select2是如果我传递的对象不是普通对象，它的行为与我想要的有点不同。这都是通过使用 jQuery 的isPlainObject函数来检查的。
Does TypeScript have a cast I'm unaware of that would achieve this without resorting to writing my own?
TypeScript 是否有一个我不知道的演员阵容，可以在不诉诸自己编写的情况下实现这一目标？
class Opt {
constructor(public id, public text) {
}
toPlainObj(): Object {
return {
id: this.id,
text: this.text
}
}
}
let opts = [
new Opt(0, 'foo'),
new Opt(1, 'bar')
];
console.clear()
console.log('both should be false')
$.map(opts, opt => {
console.log($.isPlainObject(opt))
})
console.log('both should be true')
$.map(opts, opt => {
console.log($.isPlainObject(opt.toPlainObj()))
})
回答by Nitzan Tomer
You can use Object.assign():
您可以使用Object.assign()：
class Point {
private x: number;
private y: number;
constructor(x: number, y: number) {
this.x = x;
this.y = y;
}
getX(): number {
return this.x;
}
getY(): number {
return this.y;
}
}
let p1 = new Point(4, 5);
let p2 = Object.assign({}, p1);
p1is the class instance, and p2is just { x: 4, y: 5 }.
p1是类实例，并且p2只是{ x: 4, y: 5 }.
And with the toPlainObjmethod:
并使用toPlainObj方法：
class Point {
private x: number;
private y: number;
constructor(x: number, y: number) {
this.x = x;
this.y = y;
}
getX(): number {
return this.x;
}
getY(): number {
return this.y;
}
toPlainObj(): { x: number, y: number } {
return Object.assign({}, this);
}
}
If this is something you need in more classes then you can have a base class which has this method:
如果这是您在更多类中需要的东西，那么您可以拥有一个具有此方法的基类：
class BaseClass<T> {
toPlainObj(): T {
return Object.assign({}, this);
}
}
class Point extends BaseClass<{ x: number, y: number }> {
private x: number;
private y: number;
constructor(x: number, y: number) {
super();
this.x = x;
this.y = y;
}
getX(): number {
return this.x;
}
getY(): number {
return this.y;
}
}
回答by Alain Beauvois
Something like this is simple and it works :
像这样的事情很简单，而且很有效：
let plainObj;
try {
plainObj = JSON.parse(JSON.stringify(obj));
} catch(e) {
console.error(e)
}
