Linux脚本检查进程是否正在运行并根据结果采取行动
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Linux Script to check if process is running and act on the result
提问by linuxnoob
I have a process that fails regularly & sometimes starts duplicate instances..
我有一个经常失败的过程，有时会启动重复的实例..
When I run:
ps x |grep -v grep |grep -c "processname"I will get:
2This is normal as the process runs with a recovery process..
当我运行时：
ps x |grep -v grep |grep -c "processname"我会得到：
2这是正常的，因为该进程在一个恢复进程中运行..
If I get
0I will want to start the process
if I get:
4I will want to stop & restart the process
如果我得到
0我想开始这个过程如果我得到：
4我想停止并重新启动这个过程
What I need is a way of taking the result of ps x |grep -v grep |grep -c "processname"
我需要的是一种获取结果的方法 ps x |grep -v grep |grep -c "processname"
Then setup a simple 3 option function
然后设置一个简单的 3 选项功能
ps x |grep -v grep |grep -c "processname"
if answer = 0 (start process & write NOK & Time to log /var/processlog/check)
if answer = 2 (Do nothing & write OK & time to log /var/processlog/check)
if answer = 4 (stot & restart the process & write NOK & Time to log /var/processlog/check)
The process is stopped with
killall -9 processThe process is started with
process -b -c /usr/local/etc
进程停止于
killall -9 process进程启动于
process -b -c /usr/local/etc
My main problem is finding a way to act on the result of ps x |grep -v grep |grep -c "processname".
我的主要问题是找到一种对ps x |grep -v grep |grep -c "processname".
Ideally, I would like to make the result of that grep a variable within the script with something like this:
理想情况下，我想让 grep 的结果成为脚本中的一个变量，如下所示：
process=$(ps x |grep -v grep |grep -c "processname")
process=$(ps x |grep -v grep |grep -c "processname")
If possible.
如果可能的话。
采纳答案by Jotne
Programs to monitor if a process on a system is running.
用于监视系统上的进程是否正在运行的程序。
Script is stored in crontaband runs once every minute.
脚本存储crontab并每分钟运行一次。
This works with not running process an to many process:
这适用于不运行进程和多个进程：
#! /bin/bash
case "$(pidof amadeus.x86 | wc -w)" in
0) echo "Restarting Amadeus: $(date)" >> /var/log/amadeus.txt
/etc/amadeus/amadeus.x86 &
;;
1) # all ok
;;
*) echo "Removed double Amadeus: $(date)" >> /var/log/amadeus.txt
kill $(pidof amadeus.x86 | awk '{print }')
;;
esac
0If process is not found, restart it.1If process is found, all ok.*If process running 2 or more, kill the last.
0如果找不到进程，请重新启动它。1如果找到进程，则一切正常。*如果进程运行 2 个或更多，则杀死最后一个。
A simpler version. This just test if process is running, and if not restart it.
一个更简单的版本。这只是测试进程是否正在运行，如果没有重新启动它。
It just tests the exit flag $?from the pidofprogram. It will be 0of process is running and 1if not.
它只是测试出口标志$?从pidof程序。它将是0进程正在运行，1如果没有。
#!/bin/bash
pidof amadeus.x86 >/dev/null
if [[ $? -ne 0 ]] ; then
echo "Restarting Amadeus: $(date)" >> /var/log/amadeus.txt
/etc/amadeus/amadeus.x86 &
fi
And at last, a one liner
最后，一个单班轮
pidof amadeus.x86 >/dev/null ; [[ $? -ne 0 ]] && echo "Restarting Amadeus: $(date)" >> /var/log/amadeus.txt && /etc/amadeus/amadeus.x86 &
cccam oscam
cccam oscam
回答by linuxnoob
I have adopted your script for my situation Jotne.
我已经根据我的情况采用了你的脚本 Jotne。
#! /bin/bash
logfile="/var/oscamlog/oscam1check.log"
case "$(pidof oscam1 | wc -w)" in
0) echo "oscam1 not running, restarting oscam1: $(date)" >> $logfile
/usr/local/bin/oscam1 -b -c /usr/local/etc/oscam1 -t /usr/local/tmp.oscam1 &
;;
2) echo "oscam1 running, all OK: $(date)" >> $logfile
;;
*) echo "multiple instances of oscam1 running. Stopping & restarting oscam1: $(date)" >> $logfile
kill $(pidof oscam1 | awk '{print }')
;;
esac
While I was testing, I ran into a problem..
I started 3 extra process's of oscam1 with this line:
/usr/local/bin/oscam1 -b -c /usr/local/etc/oscam1 -t /usr/local/tmp.oscam1which left me with 8 process for oscam1. the problem is this..
When I run the script, It only kills 2 process's at a time, so I would have to run it 3 times to get it down to 2 process..
在我测试时，我遇到了一个问题。我用这一行启动了 oscam1 的 3 个额外进程：
/usr/local/bin/oscam1 -b -c /usr/local/etc/oscam1 -t /usr/local/tmp.oscam1这给我留下了 8 个 oscam1 进程。问题是这样的..当我运行脚本时，它一次只杀死 2 个进程，所以我必须运行 3 次才能将它降到 2 个进程。
Other than killall -9 oscam1followed by /usr/local/bin/oscam1 -b -c /usr/local/etc/oscam1 -t /usr/local/tmp.oscam1, in *)is there any better way to killall apart from the original process? So there would be zero downtime?
除了killall -9 oscam1其次/usr/local/bin/oscam1 -b -c /usr/local/etc/oscam1 -t /usr/local/tmp.oscam1，在*)有没有更好的办法从原来的进程killall分开？那么会有零停机时间吗？
回答by Tirias
I adopted the @Jotne solution and works perfectly! For example for mongodb server in my NAS
我采用了@Jotne 解决方案并且完美运行！例如我的 NAS 中的 mongodb 服务器
#! /bin/bash
case "$(pidof mongod | wc -w)" in
0) echo "Restarting mongod:"
mongod --config mongodb.conf
;;
1) echo "mongod already running"
;;
esac
回答by Kris Long
If you changed awk '{print $1}' to '{ $1=""; print $0}' you will get all processes except for the first as a result. It will start with the field separator (a space generally) but I don't recall killall caring. So:
如果您将 awk '{print $1}' 更改为 '{ $1=""; 打印 $0}' 您将获得除第一个之外的所有进程作为结果。它将以字段分隔符（通常为空格）开头，但我不记得 killall 关心。所以：
#! /bin/bash
logfile="/var/oscamlog/oscam1check.log"
case "$(pidof oscam1 | wc -w)" in
0) echo "oscam1 not running, restarting oscam1: $(date)" >> $logfile
/usr/local/bin/oscam1 -b -c /usr/local/etc/oscam1 -t /usr/local/tmp.oscam1 &
;;
2) echo "oscam1 running, all OK: $(date)" >> $logfile
;;
*) echo "multiple instances of oscam1 running. Stopping & restarting oscam1: $(date)" >> $logfile
kill $(pidof oscam1 | awk '{ =""; print ##代码##}')
;;
esac
It is worth noting that the pidof route seems to work fine for commands that have no spaces, but you would probably want to go back to a ps-based string if you were looking for, say, a python script named myscript that showed up under ps like
值得注意的是，pidof 路由似乎适用于没有空格的命令，但如果您正在寻找一个名为 myscript 的 python 脚本，您可能希望返回到基于 ps 的字符串，该脚本出现在ps 喜欢
root 22415 54.0 0.4 89116 79076 pts/1 S 16:40 0:00 /usr/bin/python /usr/bin/myscript
根 22415 54.0 0.4 89116 79076 pts/1 S 16:40 0:00 /usr/bin/python /usr/bin/myscript
Just an FYI
仅供参考
