laravel LARAVEL5 自定义登录

LARAVEL5 Custom login

提问by devnull

I'm working in application which requires a custom login.

我正在使用需要自定义登录的应用程序。

I've to follow this flow.

我必须遵循这个流程。

1. User will enter login page.
2. User submit login page.
3. Application will check if the user is in database 3.1 (If user not in database | it will send a request to a third-party and check if login succeeded) 3.2 If user is in database verify password.

1. 用户将进入登录页面。
2. 用户提交登录页面。
3. 应用程序将检查用户是否在数据库中 3.1（如果用户不在数据库中|它将向第三方发送请求并检查登录是否成功） 3.2 如果用户在数据库中验证密码。

Now i've done class for the third-party and the code will work as this

现在我已经为第三方完成了课程，代码将像这样工作

$third = new Libraries\ThirdParty();
$third->login($username, $password);

$third->loginwill return true if login succeeded.

$third->login如果登录成功，将返回 true。

Now the question is how to link this logic. with the laravel pre-defined function Auth::check()

现在的问题是如何链接这个逻辑。使用 Laravel 预定义函数Auth::check()

回答by Carlos Herrera Plata

When you install laravel, it comes with a default login, that uses a trait:

当您安装 laravel 时，它带有一个默认登录名，它使用了一个特征：

class AuthController extends Controller {

    use AuthenticatesAndRegistersUsers;

    /**
     * Create a new authentication controller instance.
     *
     * @param  \Illuminate\Contracts\Auth\Guard  $auth
     * @param  \Illuminate\Contracts\Auth\Registrar  $registrar
     * @return void
     */
    public function __construct(Guard $auth, Registrar $registrar)
    {
        $this->auth = $auth;
        $this->registrar = $registrar;

        $this->middleware('guest', ['except' => 'getLogout']);
    }

}

this class use the trait for login stored in: vendor\laravel\framework\src\Illuminate\Foundation\Auth\AuthenticatesAndRegistersUsers.php

此类使用存储在以下位置的登录特征： vendor\laravel\framework\src\Illuminate\Foundation\Auth\AuthenticatesAndRegistersUsers.php

you can overwrite the methods from this class to put your own logic, for example in the class AuthControlleryou can define a new:

您可以覆盖此类中的方法以放置您自己的逻辑，例如在类中AuthController您可以定义一个新的：

function postLogin(){
   //your new logic for login
}

and it gonna respect your function instead the trait funcion. anyway, the logic behind the postLoginfrom auth traitis:

它会尊重你的功能而不是特质功能。无论如何，postLoginfrom背后的逻辑auth trait是：

public function postLogin(Request $request)
    {
        $this->validate($request, [
            'email' => 'required|email', 'password' => 'required',
        ]);

        $credentials = $request->only('email', 'password');

        if ($this->auth->attempt($credentials, $request->has('remember')))
        { //this if validate if the user is on the database line 1
            return redirect()->intended($this->redirectPath());
            //this redirect if user is the db line 2
        }

        return redirect($this->loginPath())
                    ->withInput($request->only('email', 'remember'))
                    ->withErrors([
                        'email' => $this->getFailedLoginMessage(),
                    ]);
          //redirect again to login view with some errors line 3
    }

you can do two things:

你可以做两件事：

1. edit the trait itself (bad practice)to put your own logic
2. define your own postLoginfunction in AuthControllerand copy the logic but edit it with your own custom logic.

1. 编辑特征本身（不好的做法）以放置您自己的逻辑
2. 定义您自己的postLogin函数AuthController并复制逻辑，但使用您自己的自定义逻辑对其进行编辑。

Editto be more conrete with your points:

编辑以更符合您的观点：

1. User will enter login page: you can use the default login page that laravel gives you, or you can overwrite getLoginfunction and redircet to your own view.

2. User submit login page: the form action needs to be: {{ url('/auth/login') }}or whatever route you put to postLogin()

3. Application will check if the user is in database: in the code line 1

   3.1 (If user not in database | it will send a request to a third-party and check if login succeeded): in the code line 3

1. 用户将进入登录页面：您可以使用laravel 给您的默认登录页面，或者您可以覆盖getLogin函数并重定向到您自己的视图。

2. 用户提交登录页面：表单操作需要是：{{ url('/auth/login') }}或您放置的任何路由postLogin()

3. 应用程序将检查用户是否在数据库中：在代码行 1

   3.1（如果用户不在数据库中|它会向第三方发送请求并检查是否登录成功）：在代码第3行

3.2 If user is in database verify password: in the code line 2

3.2 如果用户在数据库中验证密码：在代码第2行