windows IOError: [Errno url error] http: 'xxx.xxx.xxx.xxx' 的代理无效
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IOError: [Errno url error] invalid proxy for http: 'xxx.xxx.xxx.xxx'
提问by Bruno 'Shady'
I'm having some trouble with my script. It's supposed to open a website trough a proxy but I get, always, this error, with several proxies that I'm trying to...
我的脚本有问题。它应该通过代理打开一个网站，但我总是收到这个错误，我正在尝试使用几个代理......
What could it be?
会是什么呢？
Traceback (most recent call last):
File "C:\Users\Shady\Desktop\ptzplace.3.0 - Copy.py", line 43, in <module>
h = urllib.urlopen(website, proxies = {'http': proxy})
File "C:\Python26\lib\urllib.py", line 86, in urlopen
return opener.open(url)
File "C:\Python26\lib\urllib.py", line 200, in open
return self.open_unknown_proxy(proxy, fullurl, data)
File "C:\Python26\lib\urllib.py", line 219, in open_unknown_proxy
raise IOError, ('url error', 'invalid proxy for %s' % type, proxy)
IOError: [Errno url error] invalid proxy for http: 'xxx.xxx.xxx.xxx'
The script is this
剧本是这样的
proxylist = ['79.174.195.84:80',
'79.174.195.82:80',
'80.233.184.227:8080',
'79.174.195.80:80',
'80.233.184.226:8080',
'79.174.33.95:3128']
for proxy in proxylist:
h = urllib.urlopen(website, proxies = {'http': proxy})
回答by shroud
Try urllib2.urlopeninstead of urllib.urlopen. I've had situations where urllib.urlopenchokes on my proxy server but urllib2.urlopenopens it fine.
尝试urllib2.urlopen代替urllib.urlopen. 我遇到过urllib.urlopen代理服务器阻塞但urllib2.urlopen打开正常的情况。
回答by chryss
I believe you need the http schema identifier before each proxy:
我相信您在每个代理之前都需要 http 架构标识符：
proxylist = ['http://79.174.195.84:80',... 'http://79.174.33.95:3128']
回答by razpeitia
I try the next code with your proxylist but it tooks so long, so I got other proxies :P
我用你的代理列表尝试下一个代码，但它花了很长时间，所以我得到了其他代理：P
import urllib
website = 'http://www.google.com/'
proxylist = ('http://75.101.215.123:9090', 'http://94.198.47.6:3128')
connlist = (urllib.urlopen(website, proxies = {'http': proxy}) for proxy in proxylist)
for conn in connlist:
print conn.read()
conn.close()
