javascript jQuery ajax 请求错误：未调用回调
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时间：2020-10-27 02:42:05 来源:igfitidea点击:
jQuery ajax request error: callback not called
提问by mike44
window.MyCallback = function (data) {
console.log(data);
};
$(document).ready(function () {
$.ajax({
type: 'GET',
url: 'http://xxx.xxx.xxx.xx/MyService/Service.svc/MyMethod',
contentType: 'application/jsonp',
crossdomain: true,
dataType: "jsonp",
data: { 'username': 'Hyman' },
crossDomain: true,
jsonpCallback: 'MyCallback',
success: function (txt) {
console.log(txt);
},
error: function (xhr, status, err) {
console.log(status, err);
}
});
});
I always get the error: MyCallback was not called.
我总是收到错误： MyCallback was not called.
采纳答案by benjamin54
$.ajax({
type: "GET",
dataType: "jsonp",
contentType: "application/javascript",
data: { 'username': 'Hyman' },
async: false,
url: 'http://xxx.xxx.xxx.xx/MyService/Service.svc/MyMethod',
success: function (jsonData) {
console.log(jsonData);
},
error: function (request, textStatus, errorThrown) {
console.log(request.responseText);
console.log(textStatus);
console.log(errorThrown);
}
});
回答by Sagish
Why not like this?
为什么不喜欢这个？
var mycallback = function (data) {
console.log("callback", data);
};
$(document).ready(function () {
$.ajax({
type: 'GET',
url: 'https://graph.facebook.com/sagish',
contentType: 'application/jsonp',
dataType: "jsonp",
data: { 'username': 'Hyman' },
crossDomain: true,
success: mycallback,
error: function (xhr, status, err) {
console.log(status, err);
}
});
});
回答by benjamin54
For calling the "MyCallback" function, your url should be,
要调用“MyCallback”函数，您的网址应该是，
url: 'http://xxx.xxx.xxx.xx/MyService/Service.svc/MyMethod?callback=?
And server should return the ajax response like
并且服务器应该返回像这样的ajax响应
return "MyCallback(your data here)"
