wpf 如何复制可观察集合
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How to copy observable collection
提问by Relativity
I have
我有
Observablecollection<A> aRef = new Observablecollection<A>();
bRef = aRef();
In this case both point to same ObservableCollection... How do I make a different copy?
在这种情况下，两者都指向相同的ObservableCollection...如何制作不同的副本？
回答by Aliostad
Do this:
做这个：
// aRef being an Observablecollection
Observablecollection<Entity> bRef = new Observablecollection<Entity>(aRef);
This will create an observable collection but the items are still pointing to the original items. If you need the items to point a clone rather than the original items, you need to implement and then call a cloning method.
这将创建一个可观察的集合，但项目仍然指向原始项目。如果需要项目指向克隆而不是原始项目，则需要实现然后调用克隆方法。
UPDATE
更新
If you try to add to a list and then the observable collection have the original list, just create the Observablecollection by passing the original list:
如果您尝试添加到列表中，然后 observable 集合具有原始列表，只需通过传递原始列表来创建 Observablecollection：
List<Entity> originalEnityList = GetThatOriginalEnityListFromSomewhere();
Observablecollection<Entity> bRef = new Observablecollection<Entity>(originalEnityList);
回答by Jaime Marín
You could implement ICloneableinterface in you entity definition and then make a copy of the ObservableCollectionwith a internal cast. As a result you will have a cloned Listwithout any reference to old items. Then you could create your new ObservableCollectionwhit the cloned List
您可以ICloneable在实体定义中实现接口，然后ObservableCollection使用内部转换制作 的副本。因此，您将拥有一个List没有任何参考旧项目的克隆。然后你可以创建你的新ObservableCollection丝毫克隆 List
public class YourEntity : ICloneable {
public AnyType Property { get; set; }
....
public object Clone()
{
return MemberwiseClone();
}
}
The implementation would be
实施将是
var clonedList = originalObservableCollection.Select(objEntity => (YourEntity) objEntity.Clone()).ToList();
ObservableCollection<YourEntity> clonedCollection = new ObservableCollection<YourEntity>(clonedList);
