ios 在 Swift 中格式化电话号码

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时间:2020-08-31 07:30:56  来源:igfitidea点击:

Formatting Phone number in Swift

iosstringswiftuitextfieldstring-formatting

提问by CAN

I'm formatting my textfiled text once the user start typing the phone number into this format type 0 (555) 444 66 77and it is working fine but once I get the number from the server I get it like this 05554446677So please could you tell me how I can edit it in the same format once I get it fro the server?

一旦用户开始将电话号码输入到这种格式类型中0 (555) 444 66 77,我就会格式化我的文本文件,并且它工作正常,但是一旦我从服务器获取号码,我就会像这样05554446677所以请你告诉我如何编辑它一旦我从服务器得到相同的格式?

My code once I start typing:

一旦我开始输入我的代码:

func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool {

    if textField == phoneNumberTextField{
        var newString = (textField.text as NSString).stringByReplacingCharactersInRange(range, withString: string)
        var components = newString.componentsSeparatedByCharactersInSet(NSCharacterSet.decimalDigitCharacterSet().invertedSet)

        var decimalString = "".join(components) as NSString
        var length = decimalString.length
        var hasLeadingOne = length > 0 && decimalString.characterAtIndex(0) == (1 as unichar)

        if length == 0 || (length > 11 && !hasLeadingOne) || length > 12{
            var newLength = (textField.text as NSString).length + (string as NSString).length - range.length as Int

            return (newLength > 11) ? false : true
        }
        var index = 0 as Int
        var formattedString = NSMutableString()

        if hasLeadingOne{
            formattedString.appendString("1 ")
            index += 1
        }

        if (length - index) > 1{
            var zeroNumber = decimalString.substringWithRange(NSMakeRange(index, 1))
            formattedString.appendFormat("%@ ", zeroNumber)
            index += 1
        }
        if (length - index) > 3{
            var areaCode = decimalString.substringWithRange(NSMakeRange(index, 3))
            formattedString.appendFormat("(%@) ", areaCode)
            index += 3
        }
        if (length - index) > 3{
            var prefix = decimalString.substringWithRange(NSMakeRange(index, 3))
            formattedString.appendFormat("%@ ", prefix)
            index += 3
        }
        if (length - index) > 3{
            var prefix = decimalString.substringWithRange(NSMakeRange(index, 2))
            formattedString.appendFormat("%@ ", prefix)
            index += 2
        }

        var remainder = decimalString.substringFromIndex(index)
        formattedString.appendString(remainder)
        textField.text = formattedString as String
        return false
    }else{
        return true
    }
}

采纳答案by Avt

Manipulations with characters in String are not very straightforward. You need following:

对 String 中的字符进行操作并不是很简单。您需要以下内容:

Swift 2.1

斯威夫特 2.1

let s = "05554446677"
let s2 = String(format: "%@ (%@) %@ %@ %@", s.substringToIndex(s.startIndex.advancedBy(1)),
    s.substringWithRange(s.startIndex.advancedBy(1) ... s.startIndex.advancedBy(3)),
    s.substringWithRange(s.startIndex.advancedBy(4) ... s.startIndex.advancedBy(6)),
    s.substringWithRange(s.startIndex.advancedBy(7) ... s.startIndex.advancedBy(8)),
    s.substringWithRange(s.startIndex.advancedBy(9) ... s.startIndex.advancedBy(10))
)

Swift 2.0

斯威夫特 2.0

let s = "05554446677"
let s2 = String(format: "%@ (%@) %@ %@ %@", s.substringToIndex(advance(s.startIndex, 1)),
    s.substringWithRange(advance(s.startIndex, 1) ... advance(s.startIndex, 3)),
    s.substringWithRange(advance(s.startIndex, 4) ... advance(s.startIndex, 6)),
    s.substringWithRange(advance(s.startIndex, 7) ... advance(s.startIndex, 8)),
    s.substringWithRange(advance(s.startIndex, 9) ... advance(s.startIndex, 10))
)

Code will print 0 (555) 444 66 77

代码将打印 0 (555) 444 66 77

回答by Roman Filippov

Masked number typing

掩码输入

func formattedNumber(number: String) -> String {
    let cleanPhoneNumber = number.components(separatedBy: CharacterSet.decimalDigits.inverted).joined()
    let mask = "+X (XXX) XXX-XXXX"

    var result = ""
    var index = cleanPhoneNumber.startIndex
    for ch in mask where index < cleanPhoneNumber.endIndex {
        if ch == "X" {
            result.append(cleanPhoneNumber[index])
            index = cleanPhoneNumber.index(after: index)
        } else {
            result.append(ch)
        }
    }
    return result
}

Call the above function from the UITextField delegate method:

从 UITextField 委托方法调用上述函数:

func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {
    guard let text = textField.text else { return false }
    let newString = (text as NSString).replacingCharacters(in: range, with: string)
    textField.text = formattedNumber(number: newString)
    return false
}

So, that is work better.

所以,这是更好的工作。

"" => ""
"0" => "+0"
"412" => "+4 (12"
"12345678901" => "+1 (234) 567-8901"
"a1_b2-c3=d4 e5&f6|g7?h8" => "+1 (234) 567-8"

回答by Mobile Dan

Swift 3 & 4

斯威夫特 3 & 4

This solution removes any non-numeric characters before applying formatting. It returns nilif the source phone number cannot be formatted according to assumptions.

此解决方案在应用格式之前删除任何非数字字符。nil如果无法根据假设格式化源电话号码,则返回。

Swift 4

斯威夫特 4

The Swift 4 solution accounts for the deprecation of CharacterView and Sting becoming a collection of characters as the CharacterView is.

Swift 4 解决方案解释了 CharacterView 的弃用,Sting 变成了 CharacterView 的字符集合。

import Foundation

func format(phoneNumber sourcePhoneNumber: String) -> String? {
    // Remove any character that is not a number
    let numbersOnly = sourcePhoneNumber.components(separatedBy: CharacterSet.decimalDigits.inverted).joined()
    let length = numbersOnly.count
    let hasLeadingOne = numbersOnly.hasPrefix("1")

    // Check for supported phone number length
    guard length == 7 || (length == 10 && !hasLeadingOne) || (length == 11 && hasLeadingOne) else {
        return nil
    }

    let hasAreaCode = (length >= 10)
    var sourceIndex = 0

    // Leading 1
    var leadingOne = ""
    if hasLeadingOne {
        leadingOne = "1 "
        sourceIndex += 1
    }

    // Area code
    var areaCode = ""
    if hasAreaCode {
        let areaCodeLength = 3
        guard let areaCodeSubstring = numbersOnly.substring(start: sourceIndex, offsetBy: areaCodeLength) else {
            return nil
        }
        areaCode = String(format: "(%@) ", areaCodeSubstring)
        sourceIndex += areaCodeLength
    }

    // Prefix, 3 characters
    let prefixLength = 3
    guard let prefix = numbersOnly.substring(start: sourceIndex, offsetBy: prefixLength) else {
        return nil
    }
    sourceIndex += prefixLength

    // Suffix, 4 characters
    let suffixLength = 4
    guard let suffix = numbersOnly.substring(start: sourceIndex, offsetBy: suffixLength) else {
        return nil
    }

    return leadingOne + areaCode + prefix + "-" + suffix
}

extension String {
    /// This method makes it easier extract a substring by character index where a character is viewed as a human-readable character (grapheme cluster).
    internal func substring(start: Int, offsetBy: Int) -> String? {
        guard let substringStartIndex = self.index(startIndex, offsetBy: start, limitedBy: endIndex) else {
            return nil
        }

        guard let substringEndIndex = self.index(startIndex, offsetBy: start + offsetBy, limitedBy: endIndex) else {
            return nil
        }

        return String(self[substringStartIndex ..< substringEndIndex])
    }
}

Swift 3

斯威夫特 3

import Foundation

func format(phoneNumber sourcePhoneNumber: String) -> String? {

    // Remove any character that is not a number
    let numbersOnly = sourcePhoneNumber.components(separatedBy: CharacterSet.decimalDigits.inverted).joined()
    let length = numbersOnly.characters.count
    let hasLeadingOne = numbersOnly.hasPrefix("1")

    // Check for supported phone number length
    guard length == 7 || (length == 10 && !hasLeadingOne) || (length == 11 && hasLeadingOne) else {
        return nil
    }

    let hasAreaCode = (length >= 10)
    var sourceIndex = 0

    // Leading 1
    var leadingOne = ""
    if hasLeadingOne {
        leadingOne = "1 "
        sourceIndex += 1
    }

    // Area code
    var areaCode = ""
    if hasAreaCode {
        let areaCodeLength = 3
        guard let areaCodeSubstring = numbersOnly.characters.substring(start: sourceIndex, offsetBy: areaCodeLength) else {
            return nil
        }
        areaCode = String(format: "(%@) ", areaCodeSubstring)
        sourceIndex += areaCodeLength
    }

    // Prefix, 3 characters
    let prefixLength = 3
    guard let prefix = numbersOnly.characters.substring(start: sourceIndex, offsetBy: prefixLength) else {
        return nil
    }
    sourceIndex += prefixLength

    // Suffix, 4 characters
    let suffixLength = 4
    guard let suffix = numbersOnly.characters.substring(start: sourceIndex, offsetBy: suffixLength) else {
        return nil
    }

    return leadingOne + areaCode + prefix + "-" + suffix
}

extension String.CharacterView {
    /// This method makes it easier extract a substring by character index where a character is viewed as a human-readable character (grapheme cluster).
    internal func substring(start: Int, offsetBy: Int) -> String? {
        guard let substringStartIndex = self.index(startIndex, offsetBy: start, limitedBy: endIndex) else {
            return nil
        }

        guard let substringEndIndex = self.index(startIndex, offsetBy: start + offsetBy, limitedBy: endIndex) else {
            return nil
        }

        return String(self[substringStartIndex ..< substringEndIndex])
    }
}

Example

例子

func testFormat(sourcePhoneNumber: String) -> String {
    if let formattedPhoneNumber = format(phoneNumber: sourcePhoneNumber) {
        return "'\(sourcePhoneNumber)' => '\(formattedPhoneNumber)'"
    }
    else {
        return "'\(sourcePhoneNumber)' => nil"
    }
}

print(testFormat(sourcePhoneNumber: "1 800 222 3333"))
print(testFormat(sourcePhoneNumber: "18002223333"))
print(testFormat(sourcePhoneNumber: "8002223333"))
print(testFormat(sourcePhoneNumber: "2223333"))
print(testFormat(sourcePhoneNumber: "18002223333444"))
print(testFormat(sourcePhoneNumber: "Letters8002223333"))
print(testFormat(sourcePhoneNumber: "1112223333"))

Example Output

示例输出

'1 800 222 3333' => '1 (800) 222-3333'

'18002223333' => '1 (800) 222-3333'

'8002223333' => '(800) 222-3333'

'2223333' => '222-3333'

'18002223333444' => nil

'Letters8002223333' => '(800) 222-3333'

'1112223333' => nil

回答by Дар?я Прокопович

Really simple solution:

非常简单的解决方案:

extension String {
    func applyPatternOnNumbers(pattern: String, replacmentCharacter: Character) -> String {
        var pureNumber = self.replacingOccurrences( of: "[^0-9]", with: "", options: .regularExpression)
        for index in 0 ..< pattern.count {
            guard index < pureNumber.count else { return pureNumber }
            let stringIndex = String.Index(encodedOffset: index)
            let patternCharacter = pattern[stringIndex]
            guard patternCharacter != replacmentCharacter else { continue }
            pureNumber.insert(patternCharacter, at: stringIndex)
        }
        return pureNumber
    }
}

Usage:

用法:

guard let text = textField.text else { return }
textField.text = text.applyPatternOnNumbers(pattern: "+# (###) ###-####", replacmentCharacter: "#")

回答by Thomas Staltner

Swift 3 but should also be translatable to Swift 4

Swift 3 但也应该可以翻译成 Swift 4

  1. ErrorHandling

    enum PhoneNumberFormattingError: Error {
        case wrongCharactersInPhoneNumber
        case phoneNumberLongerThanPatternAllowes
    }
    
  2. Create Patterns

    enum PhoneNumberFormattingPatterns: String {
        case mobile = "+xx (yxx) xxxxxxxxxxx"
        case home = "+xx (yxxx) xxxx-xxx"
    }
    
  3. Insert Function

    /**
         Formats a phone-number to correct format
         - Parameter pattern: The pattern to format the phone-number.
         - Example:
            - x: Says that this should be a digit.
            - y: Says that this digit cannot be a "0".
            - The length of the pattern restricts also the length of allowed phone-number digits.
                - phone-number: "+4306641234567"
                - pattern: "+xx (yxx) xxxxxxxxxxx"
                - result: "+43 (664) 1234567"
    
         - Throws:
            - PhoneNumberFormattingError
                - wrongCharactersInPhoneNumber: if phone-number contains other characters than digits.
                - phoneNumberLongerThanPatternAllowes: if phone-number is longer than pattern allows.
         - Returns:
            - The formatted phone-number due to the pattern.
         */
    extension String {
        func vpToFormattedPhoneNumber(withPattern pattern: PhoneNumberFormattingPatterns) throws -> String {
            let phoneNumber = self.replacingOccurrences(of: "+", with: "")
            var retVal: String = ""
            var index = 0
            for char in pattern.rawValue.lowercased().characters {
                guard index < phoneNumber.characters.count else {
                    return retVal
                }
    
                if char == "x" {
                    let charIndex = phoneNumber.index(phoneNumber.startIndex, offsetBy: index)
                    let phoneChar = phoneNumber[charIndex]
                    guard "0"..."9" ~= phoneChar else {
                        throw PhoneNumberFormattingError.wrongCharactersInPhoneNumber
                    }
                    retVal.append(phoneChar)
                    index += 1
                } else if char == "y" {
                    var charIndex = phoneNumber.index(phoneNumber.startIndex, offsetBy: index)
                    var indexTemp = 1
                    while phoneNumber[charIndex] == "0" {
                        charIndex = phoneNumber.index(phoneNumber.startIndex, offsetBy: index + indexTemp)
                        indexTemp += 1
                    }
    
                    let phoneChar = phoneNumber[charIndex]
                    guard "0"..."9" ~= phoneChar else {
                        throw PhoneNumberFormattingError.wrongCharactersInPhoneNumber
                    }
                    retVal.append(phoneChar)
                    index += indexTemp
                } else {
                    retVal.append(char)
                }
            }
    
            if phoneNumber.endIndex > phoneNumber.index(phoneNumber.startIndex, offsetBy: index) {
                throw PhoneNumberFormattingError.phoneNumberLongerThanPatternAllowes
            }
    
            return retVal
        }
    }
    
  4. Usage

    let phoneNumber = "+4306641234567"
    let phoneNumber2 = "4343211234567"
    
    do {
        print(try phoneNumber.vpToFormattedPhoneNumber(withPattern: .mobile))
        print(try phoneNumber2.vpToFormattedPhoneNumber(withPattern: .home))
    } catch let error as PhoneNumberFormattingError {
        switch error {
        case .wrongCharactersInPhoneNumber:
            print("wrong characters in phone number")
        case .phoneNumberLongerThanPatternAllowes:
            print("too long phone number")
        default:
            print("unknown error")
        }
    } catch {
        print("something other went wrong")
    }
    
    // output: +43 (664) 1234567
    // output: +43 (4321) 1234-567
    
  1. 错误处理

    enum PhoneNumberFormattingError: Error {
        case wrongCharactersInPhoneNumber
        case phoneNumberLongerThanPatternAllowes
    }
    
  2. 创建模式

    enum PhoneNumberFormattingPatterns: String {
        case mobile = "+xx (yxx) xxxxxxxxxxx"
        case home = "+xx (yxxx) xxxx-xxx"
    }
    
  3. 插入功能

    /**
         Formats a phone-number to correct format
         - Parameter pattern: The pattern to format the phone-number.
         - Example:
            - x: Says that this should be a digit.
            - y: Says that this digit cannot be a "0".
            - The length of the pattern restricts also the length of allowed phone-number digits.
                - phone-number: "+4306641234567"
                - pattern: "+xx (yxx) xxxxxxxxxxx"
                - result: "+43 (664) 1234567"
    
         - Throws:
            - PhoneNumberFormattingError
                - wrongCharactersInPhoneNumber: if phone-number contains other characters than digits.
                - phoneNumberLongerThanPatternAllowes: if phone-number is longer than pattern allows.
         - Returns:
            - The formatted phone-number due to the pattern.
         */
    extension String {
        func vpToFormattedPhoneNumber(withPattern pattern: PhoneNumberFormattingPatterns) throws -> String {
            let phoneNumber = self.replacingOccurrences(of: "+", with: "")
            var retVal: String = ""
            var index = 0
            for char in pattern.rawValue.lowercased().characters {
                guard index < phoneNumber.characters.count else {
                    return retVal
                }
    
                if char == "x" {
                    let charIndex = phoneNumber.index(phoneNumber.startIndex, offsetBy: index)
                    let phoneChar = phoneNumber[charIndex]
                    guard "0"..."9" ~= phoneChar else {
                        throw PhoneNumberFormattingError.wrongCharactersInPhoneNumber
                    }
                    retVal.append(phoneChar)
                    index += 1
                } else if char == "y" {
                    var charIndex = phoneNumber.index(phoneNumber.startIndex, offsetBy: index)
                    var indexTemp = 1
                    while phoneNumber[charIndex] == "0" {
                        charIndex = phoneNumber.index(phoneNumber.startIndex, offsetBy: index + indexTemp)
                        indexTemp += 1
                    }
    
                    let phoneChar = phoneNumber[charIndex]
                    guard "0"..."9" ~= phoneChar else {
                        throw PhoneNumberFormattingError.wrongCharactersInPhoneNumber
                    }
                    retVal.append(phoneChar)
                    index += indexTemp
                } else {
                    retVal.append(char)
                }
            }
    
            if phoneNumber.endIndex > phoneNumber.index(phoneNumber.startIndex, offsetBy: index) {
                throw PhoneNumberFormattingError.phoneNumberLongerThanPatternAllowes
            }
    
            return retVal
        }
    }
    
  4. 用法

    let phoneNumber = "+4306641234567"
    let phoneNumber2 = "4343211234567"
    
    do {
        print(try phoneNumber.vpToFormattedPhoneNumber(withPattern: .mobile))
        print(try phoneNumber2.vpToFormattedPhoneNumber(withPattern: .home))
    } catch let error as PhoneNumberFormattingError {
        switch error {
        case .wrongCharactersInPhoneNumber:
            print("wrong characters in phone number")
        case .phoneNumberLongerThanPatternAllowes:
            print("too long phone number")
        default:
            print("unknown error")
        }
    } catch {
        print("something other went wrong")
    }
    
    // output: +43 (664) 1234567
    // output: +43 (4321) 1234-567
    

回答by iOS Developer

You can use this library https://github.com/luximetr/AnyFormatKit

你可以使用这个库https://github.com/luximetr/AnyFormatKit

Example

例子

let textInputController = TextInputController()

let textInput = TextInputField() // or TextInputView or any TextInput
textInputController.textInput = textInput // setting textInput

let formatter = TextInputFormatter(textPattern: "### (###) ###-##-##", prefix: "+12")
textInputController.formatter = formatter // setting formatter

Just set your textField to this textInputController and it will format text with pattern, that you set.

只需将您的 textField 设置为此 textInputController ,它将使用您设置的模式格式化文本。

回答by Chhaileng

Swift 4

斯威夫特 4

Create this function and call on text field event Editing Changed

创建此函数并调用文本字段事件 Editing Changed

private func formatPhone(_ number: String) -> String {
    let cleanNumber = number.components(separatedBy: CharacterSet.decimalDigits.inverted).joined()
    let format: [Character] = ["X", "X", "X", "-", "X", "X", "X", "-", "X", "X", "X", "X"]

    var result = ""
    var index = cleanNumber.startIndex
    for ch in format {
        if index == cleanNumber.endIndex {
            break
        }
        if ch == "X" {
            result.append(cleanNumber[index])
            index = cleanNumber.index(after: index)
        } else {
            result.append(ch)
        }
    }
    return result
}

回答by Mark Wilson

Swift 5.1 Update on Дар?я Прокопович great solution

Swift 5.1 更新 Дар?я Прокопович 很好的解决方案

extension String {

    func applyPatternOnNumbers(pattern: String, replacmentCharacter: Character) -> String {
        var pureNumber = self.replacingOccurrences( of: "[^0-9]", with: "", options: .regularExpression)
        for index in 0 ..< pattern.count {
            guard index < pureNumber.count else { return pureNumber }
            let stringIndex = String.Index(utf16Offset: index, in: self)
            let patternCharacter = pattern[stringIndex]
            guard patternCharacter != replacmentCharacter else { continue }
            pureNumber.insert(patternCharacter, at: stringIndex)
        }
        return pureNumber
    }
}

Usage:

用法:

let formattedText = text.applyPatternOnNumbers(pattern: "+# (###) ###-####", replacmentCharacter: "#")

回答by Prabhat Kasera

This is the extension which will full fill your requirement:

这是将完全满足您的要求的扩展:

 extension String {
 func convertToInternationalFormat() -> String {
    let isMoreThanTenDigit = self.count > 10
    _ = self.startIndex
    var newstr = ""
    if isMoreThanTenDigit {
        newstr = "\(self.dropFirst(self.count - 10))"
    }
    else if self.count == 10{
        newstr = "\(self)"
    }
    else {
        return "number has only \(self.count) digits"
    }
    if  newstr.count == 10 {
        let internationalString = "(\(newstr.dropLast(7))) \(newstr.dropLast(4).dropFirst(3)) \(newstr.dropFirst(6).dropLast(2)) \(newstr.dropFirst(8))"
        newstr = internationalString
    }
    return newstr
 }
 }

INPUT :
var str1 = "9253248954"
var str2 = "+19253248954"
var str3 = "19253248954"

OUTPUT :
str1.convertToInternationalFormat() // "(925) 324 89 54"
str2.convertToInternationalFormat() // "(925) 324 89 54"
str3.convertToInternationalFormat() // "(925) 324 89 54"

回答by digitalHound

There are a number of good answers here but I took a completely different approach and thought I'd share in case it helps.

这里有很多很好的答案,但我采取了一种完全不同的方法,并认为我会分享以防万一。

To start I broke up the formatting steps and components into their own separate responsibilities.

首先,我将格式化步骤和组件分解为各自独立的职责。

Phone number format can generally be broken down into local, domestic or international format types that vary by string length.

电话号码格式通常可以分解为本地、国内或国际格式类型,这些类型因字符串长度而异。

I defined the types:

我定义了类型:

/// Defines the three different types of formatting phone numbers use
///
/// - local: Numbers used locally.
/// - domestic: Numbers used locally including area codes.
/// - international: Numbers used internationally with country codes.
public enum PhoneFormatType {
    case local
    case domestic
    case international
}

Then defined the separators available to format a phone number string:

然后定义可用于格式化电话号码字符串的分隔符:

// Defines separators that are available for use in formatting
// phone number strings.
public enum PhoneFormatSeparator {
    case hyphen
    case plus
    case space
    case parenthesisLH
    case parenthesisRH
    case slash
    case backslash
    case pipe
    case asterisk

    public var value: String {
        switch self {
        case .hyphen: return "-"
        case .plus: return "+"
        case .space: return " "
        case .parenthesisLH: return "("
        case .parenthesisRH: return ")"
        case .slash: return "/"
        case .backslash: return "\"
        case .pipe: return "|"
        case .asterisk: return "*"
        }
    }
}

Next I defined formatting rules that specify the index (in a phone number string) where the separators like +,-,etc are inserted.

接下来,我定义了格式规则,用于指定插入 +、- 等分隔符的索引(在电话号码字符串中)。

// defines the separators that should be inserted in a phone number string
// and the indexes where they should be applied
public protocol PhoneNumberFormatRule {

    // the index in a phone number where this separator should be applied
    var index: Int { get set }

    // the priority in which this rule should be applied. Sorted in inverse, 0 is highest priority, higher numbers are lower priority
    var priority: Int { get set }

    // the separator to use at this index
    var separator: PhoneFormatSeparator { get set }
}

/// Default implementation of PhoneNumberFormatRule
open class PNFormatRule: PhoneNumberFormatRule {
    public var index: Int
    public var priority: Int
    public var separator: PhoneFormatSeparator

    public init(_ index: Int, separator: PhoneFormatSeparator, priority: Int = 0) {
        self.index = index
        self.separator = separator
        self.priority = priority
    }
}

With these defined, I created rulesets that associate rules with a given format type.

定义了这些之后,我创建了将规则与给定格式类型相关联的规则集。

/// Defines the rule sets associated with a given phone number type.
/// e.g. international/domestic/local
public protocol PhoneFormatRuleset {

    /// The type of phone number formatting to which these rules apply
    var type: PhoneFormatType { get set }

    /// A collection of rules to apply for this phone number type.
    var rules: [PhoneNumberFormatRule] { get set }

    /// The maximum length a number using this format ruleset should be. (Inclusive)
    var maxLength: Int { get set }
}

With everything defined this way, you can setup rulesets quickly to suit whatever format you need.

通过以这种方式定义所有内容,您可以快速设置规则集以适应您需要的任何格式。

Here's an example of a ruleset that defines 3 rules for a hyphen formatted phone number string typically used in the US:

下面是一个规则集示例,它为通常在美国使用的连字符格式的电话号码字符串定义了 3 条规则:

    // Formats phone numbers:
    //  .local: 123-4567
    //  .domestic: 123-456-7890
    //  .international: +1 234-567-8901
    static func usHyphen() -> [PhoneFormatRuleset] {
        return [
            PNFormatRuleset(.local, rules: [
                PNFormatRule(3, separator: .hyphen)
                ], maxLength: 7),
            PNFormatRuleset(.domestic, rules: [
                PNFormatRule(3, separator: .hyphen),
                PNFormatRule(6, separator: .hyphen)
                ], maxLength: 10),
            PNFormatRuleset(.international, rules: [
                PNFormatRule(0, separator: .plus),
                PNFormatRule(1, separator: .space),
                PNFormatRule(4, separator: .hyphen),
                PNFormatRule(7, separator: .hyphen)
                ], maxLength: 11)
        ]
    }

The (not so) heavy lifting of the formatting logic happens here:

格式化逻辑的(并非如此)繁重的工作发生在这里:

// formats a string using the format rule provided at initialization
public func format(number: String) -> String {

    // strip non numeric characters
    let n = number.components(separatedBy: CharacterSet.decimalDigits.inverted).joined()

    // bail if we have an empty string, or if no ruleset is defined to handle formatting
    guard n.count > 0, let type = type(for: n.count), let ruleset = ruleset(for: type) else {
        return n
    }

    // this is the string we'll return
    var formatted = ""

    // enumerate the numeric string
    for (i,character) in n.enumerated() {

        // bail if user entered more numbers than allowed for our formatting ruleset
        guard i <= ruleset.maxLength else {
            break
        }

        // if there is a separator defined to be inserted at this index then add it to the formatted string
        if let separator = ruleset.separator(for: i) {
            formatted+=separator
        }

        // now append the character
        formatted+="\(character)"
    }

    return formatted
} 

I've created a framework with a sample project you can look through here: https://github.com/appteur/phoneformat

我创建了一个带有示例项目的框架,您可以在此处查看:https: //github.com/appteur/phoneformat

Here is how it works as you type:

这是您键入时的工作方式:

Demo Gif

演示 Gif

I also set it up so you can just import it with cocoapods.

我也设置了它,所以你可以用 cocoapods 导入它。

pod 'SwiftPhoneFormat', '1.0.0'

Then use it:

然后使用它:

import SwiftPhoneFormat

var formatter = PhoneFormatter(rulesets: PNFormatRuleset.usParethesis())
let formatted = formatter.format(number: numberString)