asp.net-mvc MVC 3 不能将字符串作为视图模型传递？
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MVC 3 Can't pass string as a View's model?
提问by Tony
I have a strange problem with my model passed to the View
我传递给视图的模型有一个奇怪的问题
Controller
控制器
[Authorize]
public ActionResult Sth()
{
return View("~/Views/Sth/Sth.cshtml", "abc");
}
View
看法
@model string
@{
ViewBag.Title = "lorem";
Layout = "~/Views/Shared/Default.cshtml";
}
The error message
错误信息
The view '~/Views/Sth/Sth.cshtml' or its master was not found or no view engine supports the searched locations. The following locations were searched:
~/Views/Sth/Sth.cshtml
~/Views/Sth/abc.master //string model is threated as a possible Layout's name ?
~/Views/Shared/abc.master
~/Views/Sth/abc.cshtml
~/Views/Sth/abc.vbhtml
~/Views/Shared/abc.cshtml
~/Views/Shared/abc.vbhtml
Why can't I pass a simple string as a model ?
为什么我不能传递一个简单的字符串作为模型？
回答by nemesv
回答by nemesv
If you use named parameters you can skip the need to give the first parameter altogether
如果您使用命名参数，则可以完全跳过提供第一个参数的需要
return View(model:"abc");
or
或者
return View(viewName:"~/Views/Sth/Sth.cshtml", model:"abc");
will also serve the purpose.
也将达到目的。
回答by gdoron is supporting Monica
You meant this Viewoverload:
你的意思是这个View超载：
protected internal ViewResult View(string viewName, Object model)
MVC is confused by this overload:
MVC 被这个重载弄糊涂了：
protected internal ViewResult View(string viewName, string masterName)
Use this overload:
使用这个重载：
protected internal virtual ViewResult View(string viewName, string masterName,
Object model)
This way:
这边走：
return View("~/Views/Sth/Sth.cshtml", null , "abc");
By the way, you could just use this:
顺便说一句，你可以使用这个：
return View("Sth", null, "abc");
回答by Alex Dresko
It also works if you pass null for the first two parameters:
如果您为前两个参数传递 null ，它也可以工作：
return View(null, null, "abc");
回答by Tim Mac
It also works if you declare the string as an object:
如果您将字符串声明为对象，它也可以工作：
object str = "abc";
return View(str);
Or:
或者：
return View("abc" as object);
回答by Hiren Patel
You also write like
你也这样写
return View(model: "msg");
返回视图（模型：“味精”）；
