Python Networkx：如何在图形中显示节点和边属性
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Networkx: how to show node and edge attributes in a graph drawing
提问by Bravo
I have a graph G with attribute 'state' for nodes and edges. I want to draw the graph, all nodes labelled, and with the state marked outside the corresponding edge/node.
我有一个图 G，节点和边的属性为“状态”。我想绘制图形，标记所有节点，并在相应的边/节点外部标记状态。
for v in G.nodes():
G.node[v]['state']='X'
G.node[1]['state']='Y'
G.node[2]['state']='Y'
for n in G.edges_iter():
G.edge[n[0]][n[1]]['state']='X'
G.edge[2][3]['state']='Y'
The command draw.networkx has an option for labels, but I do not understand how to provide the attribute as a label to this command. Could someone help me out?
命令 draw.networkx 有一个标签选项，但我不明白如何将该属性作为标签提供给该命令。有人可以帮我吗？
回答by Aric
It's not so pretty - but it works like this:
它不是那么漂亮 - 但它的工作原理是这样的：
from matplotlib import pyplot as plt
import networkx as nx
G = nx.Graph()
G.add_edge(1,2)
G.add_edge(2,3)
for v in G.nodes():
G.node[v]['state']='X'
G.node[1]['state']='Y'
G.node[2]['state']='Y'
for n in G.edges_iter():
G.edge[n[0]][n[1]]['state']='X'
G.edge[2][3]['state']='Y'
pos = nx.spring_layout(G)
nx.draw(G, pos)
node_labels = nx.get_node_attributes(G,'state')
nx.draw_networkx_labels(G, pos, labels = node_labels)
edge_labels = nx.get_edge_attributes(G,'state')
nx.draw_networkx_edge_labels(G, pos, labels = edge_labels)
plt.savefig('this.png')
plt.show()
