bash 在文件名中间添加字符
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add character to the middle of a file name
提问by steve-er-rino
I need to add a character to the middle of a file name, I need to do this for about 8000 files all in the same directory. I'm looking for a command-line option:
我需要在文件名的中间添加一个字符，我需要对同一目录中的大约 8000 个文件执行此操作。我正在寻找一个命令行选项：
Example (all files that need renaming are five digits, they are in a directory that contains other six-digit filenames that do not need to be renamed):
示例（所有需要重命名的文件都是五位数，它们所在的目录包含其他不需要重命名的六位数文件名）：
01011
02022
12193
To:
到：
010101
020202
121903
I've tried a couple of things: rename, mv, etc. Similar to this (Bash - Adding 0's in the middle of a file name) but not exactly
我尝试了几件事：重命名、mv 等。与此类似（Bash - 在文件名中间添加 0）但不完全相同
回答by ruakh
You can write:
你可以写：
for file in * ; do
mv ./"$file" "${file:0:4}0${file:4}"
done
(See the explanation of ${parameter:offset}and ${parameter:offset:length}in §3.5.3 "Shell Parameter Expansion" of the Bash Reference Manual.)
（请参阅Bash 参考手册的§3.5.3 “Shell Parameter Expansion”和中的解释。）${parameter:offset}${parameter:offset:length}
Edited to add:If you only want to capture a specific subset of files, you can change *to a more-specific pattern such as [0-9][0-9][0-9][0-9][0-9](which matches filenames consisting of five digits).
编辑添加：如果您只想捕获特定的文件子集，您可以更改*为更具体的模式，例如[0-9][0-9][0-9][0-9][0-9]（匹配由五位数字组成的文件名）。
Incidentally, you can format the whole thing on one line:
顺便说一句，您可以在一行中格式化整个内容：
for file in [0-9][0-9][0-9][0-9][0-9] ; do mv "$file" "${file:0:4}0${file:4}" ; done
回答by edu
Try using below code.
尝试使用以下代码。
rename -v -n "s/(S01S0[0-2][0-9])/$1-/" *
-nto check the command output.
-n检查命令输出。
回答by Roger Barreto
For a Windows prompt environment suposing that all the files start with the same name you could use rename.
对于假设所有文件都以相同名称开头的 Windows 提示环境，您可以使用重命名。
rename 0101* 01010*
For a delimited size you could use
对于分隔大小，您可以使用
rename ????* ????0*
Real example
真实例子
Pasta de C:\temp
10/08/2013 00:37 <DIR> .
10/08/2013 00:37 <DIR> ..
10/08/2013 00:37 0 teste.txt
1 arquivo(s) 0 bytes
2 pasta(s) 846.577.762.304 bytes disponíveis
C:\temp>rename ???* ???0*
C:\temp>dir
O volume na unidade C nao tem nome.
O Número de Série do Volume é 7868-7679
Pasta de C:\temp
10/08/2013 00:38 <DIR> .
10/08/2013 00:38 <DIR> ..
10/08/2013 00:37 0 tes0e.txt
1 arquivo(s) 0 bytes
2 pasta(s) 846.577.762.304 bytes disponíveis
回答by jrd1
How about:
怎么样：
for file in * ; do mv "$file" "${file:0:4}0${file:4:1}" ; done
