jQuery 带有逗号分隔符的数字的正则表达式验证
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Regex validation for numbers with comma separator
提问by Suvonkar
Need a regular expression to validate number with comma separator. 1,5,10,55is valid but 1,,,,10is not valid.
需要一个正则表达式来验证带有逗号分隔符的数字。 1,5,10,55有效但1,,,,10无效。
回答by Kobi
This should do it:
这应该这样做：
^\d+(,\d+)*$
The regex is rather simple: \d+is the first number, followed by optional commas and more numbers.
正则表达式相当简单：\d+是第一个数字，后跟可选的逗号和更多数字。
You may want to throw in \s*where you see fit, or remove all spaces before validation.
您可能想要\s*在您认为合适的地方加入，或者在验证之前删除所有空格。
- To allow negative numbers replace
\d+with[+-]?\d+ - To allow fractions: replace
\d+with[+-]?\d+(?:\.\d+)?
- 允许负数替换
\d+为[+-]?\d+ - 允许分数：替换
\d+为[+-]?\d+(?:\.\d+)?
回答by polygenelubricants
Here are the components of the regex we're going to use:
以下是我们将要使用的正则表达式的组件：
\dis the shorthand for the digit character class+is one-or-more repetition specifier*is zero-or-more repetition specifier(...)performs grouping^and$are the beginning and end of the line anchors respectively
\d是数字字符类的简写+是一个或多个重复说明符*是零个或多个重复说明符(...)进行分组^和$分别是线锚的开始和结束
We can now compose the regex we need:
我们现在可以编写我们需要的正则表达式：
^\d+(,\d+)*$
That is:
那是：
from beginning...
| ...to the end
| |
^\d+(,\d+)*$ i.e. ^num(,num)*$
\_/ \_/
num num
Note that the *means that having just one number is allowed. If you insist on at least two numbers, then use +instead. You can also replace \d+with another pattern for the number to allow e.g. sign and/or fractional part.
请注意，这*意味着允许只有一个数字。如果您坚持至少使用两个数字，请+改用。您还可以替换\d+为其他模式的数字以允许例如符号和/或小数部分。
References
参考
Advanced topics: optimization
进阶课题：优化
Optionally you can make the brackets non-capturingfor performance:
您可以选择使括号不捕获性能：
^\d+(?:,\d+)*$
And if the flavor supports it, you can make all repetition possessivein this case:
如果口味支持它，在这种情况下，您可以使所有重复都具有所有格：
^\d++(?:,\d++)*+$
References
参考
回答by Sachin R
^[0-9]*(,){1}[0-9]*/
try this
尝试这个
