在java中格式化字符串数组
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Formatting a string array in java
提问by ashu
I have a string array which has k elements. I want to print them out using System.out.format, but the issue is that I do not know k. So essentially, I want to use something like:
System.out.format("%s %s ... k times", str1, str2, ... strk);(where k is a variable)
我有一个包含 k 个元素的字符串数组。我想使用 System.out.format 将它们打印出来，但问题是我不知道 k。所以本质上，我想使用类似的东西：（
System.out.format("%s %s ... k times", str1, str2, ... strk);其中 k 是一个变量）
I was looking through the java documentation, but could not find a way to do this. Is there a simple way out?
我正在查看 java 文档，但找不到执行此操作的方法。有没有简单的出路？
Thanks!
谢谢！
采纳答案by duffymo
Use a loop:
使用循环：
for (String s : array) {
System.out.print(String.format("%s ", s);
}
System.out.println();
回答by Tricky12
for(int i = 0; i < array.length; i++) {
System.out.print("%s ", array[i]);
}
回答by Jean Logeart
Try:
尝试：
StringBuilder sb = new StringBuilder();
for(String s : myArray){
sb.append(s).append(" ");
}
sb.append(myArray.length).append(" times");
System.out.println(sb.toString()); // print the string
回答by Ruchira Gayan Ranaweera
you can use
您可以使用
System.out.format("%s". Arrays.toString(your_array));
回答by Jesper
Do you simply want to concatenate kstrings with a space between each of the strings? You don't need System.out.formatfor that. You could simply create a loop to concatenate them together with a StringBuilder:
您是否只是想将k 个字符串与每个字符串之间的空格连接起来？你不需要System.out.format那个。您可以简单地创建一个循环将它们与 a 连接在一起StringBuilder：
public String concatStrings(String... s) {
StringBuilder sb = new StringBuilder();
if (s.length > 0) {
sb.append(s[0]);
for (int i = 1; i < s.length; i++) {
sb.append(' ').append(s[i]);
}
}
return sb.toString();
}
回答by Reimeus
I want to specify the number of characters that I want for each string. Something like %15s
我想为每个字符串指定我想要的字符数。类似于 %15s
That will only specify the padding for each String. If the Stringlength is less than the value specified in the format specifier, then the full Stringis used. You could use substring
那只会指定每个String. 如果String长度小于格式说明符中指定的值，则使用完整String的。你可以用substring
void displayArray(String[] str, int characters) {
for (String s: str) {
System.out.print(s.substring(0, Math.min(s.length(), characters)) + " ");
}
System.out.println();
}
回答by Peter Walser
That's typical toolbox code- code you often use and reuse, and best keep in a static-access utility class (such as StringUtil). Here's a generic function that works on all kinds of non-primitive arrays, and lets you specify the separator (space, comma, slash, whatever):
这是典型的工具箱代码- 您经常使用和重用的代码，最好保留在静态访问实用程序类（例如StringUtil）中。这是一个适用于各种非原始数组的通用函数，并允许您指定分隔符（空格、逗号、斜杠等）：
public static <T> void print (PrintStream out, String separator, T... elements) {
for (int i = 0; i < elements.length; i++) {
if (i > 0) {
out.print(separator);
}
out.print(elements[i]);
}
}
Example Usage:
示例用法：
String[] s = {"A", "B", "C", "D", "E"};
Integer[] n = {1, 2, 3, 4, 5}; //non-primitive
print(System.out, " ", s);
print(System.out, ", ", n);
回答by Dominic Fox
Java 8:
爪哇 8：
String formatted = Stream.of(arrayOfStrings)
.collect(Collectors.joining(",","[","]"));
String formatted = Stream.of(arrayOfSomethingElse)
.map(Object::toString)
.collect(Collectors.joining(",","[","]"));
