C# 如何通过 [WebMethod] 返回数据表

声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow 原文地址: http://stackoverflow.com/questions/10415563/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me): StackOverFlow

提示:将鼠标放在中文语句上可以显示对应的英文。显示中英文
时间:2020-08-09 13:45:37  来源:igfitidea点击:

How to return a Datatable by a [WebMethod]

c#web-servicesdatatable

提问by Pomster

I have a webservice that should return the top 5 emails in my inbox and display them in a data grid. I put my data into a DataTablefirst. But keep getting errors

我有一个网络服务,它应该返回收件箱中前 5 封电子邮件并将它们显示在数据网格中。我把我的数据放到了DataTable第一个。但不断收到错误

Here is my code, Am I missing anything or declaring something wrong?

这是我的代码,我是否遗漏了什么或声明了错误?

[WebMethod]
    public DataTable DisplayMailList(String inMailServer, String inPort, bool inSSlCheck, String inUsername, String inPassword)
    {   
        objClient.Connect(inMailServer, int.Parse(inPort), inSSlCheck);
        objClient.Authenticate(inUsername, inPassword);

        int count = objClient.GetMessageCount();

        DataTable dtMessages = new DataTable(); // Creating datatable.
        dtMessages.Columns.Add("MessageNumber");
        dtMessages.Columns.Add("From");
        dtMessages.Columns.Add("Subject");
        dtMessages.Columns.Add("DateSent");
        dtMessages.TableName = "dtMessages";

        int counter = 0;
        for (int i = count; i >= 1; i--)
        {
            OpenPop.Mime.Message msg = objClient.GetMessage(i);

            dtMessages.Rows.Add();
            dtMessages.Rows[dtMessages.Rows.Count - 1]["MessageNumber"] = i; //Populateing Datatable
            dtMessages.Rows[dtMessages.Rows.Count - 1]["Subject"] = msg.Headers.Subject;
            dtMessages.Rows[dtMessages.Rows.Count - 1]["DateSent"] = msg.Headers.DateSent;

            counter++;
            if (counter > 5)
            {
                break;
            }
        }
        return dtMessages;
    }

Think the problem is public DataTableI had it declared as an object but that did not work ether .... sigh, what should I declare it as?
this is the error....

认为问题是公共数据表我将它声明为一个对象,但它不起作用以太......叹息,我应该将它声明为什么?
这是错误....

System.InvalidOperationException: There was an error generating the XML document. ---> System.InvalidOperationException: Cannot serialize the DataTable. DataTable name is not set.

System.InvalidOperationException: 生成 XML 文档时出错。---> System.InvalidOperationException: 无法序列化数据表。未设置数据表名称。

采纳答案by Ivan Karajas

Assigning a value to dtMessages.DataTablename will stop the serialization error, as the error message suggests.

dtMessages.DataTable正如错误消息所暗示的那样,为 name分配一个值将停止序列化错误。

    [WebMethod]
    public DataTable GetDataTable()
    {
        DataTable dt = new DataTable();
        dt.Columns.Add("Col1", typeof(string));
        dt.Rows.Add("testing");
        dt.TableName = "Blah";  // <---
        return dt;
    }

But I agree with Bob Horn that you're better off defining a class for your return value than using a DataTable.

但我同意 Bob Horn 的观点,即为返回值定义一个类比使用 DataTable 更好。

回答by Mohammed Yasin

This worked for me:

这对我有用:

In your Application

在您的应用程序中

      public void app()
      {
        try
        {
            DataTable dtInput = new DataTable();
            DataRow drRow;
            dtInput.Columns.Add("ID");
            dtInput.Columns.Add("Name");
            drRow = dtInput.NewRow();
            drRow["ID"] = 1;
            drRow["Name"] = "Star";
            dtInput.Rows.Add(drRow);
            dtInput.TableName = "Input";//Table name is mandatory to avoid serialization exception 
            DataTable dtOutput = new DataTable();
            dtOutput.TableName = "Output";//Table name is mandatory to avoid serialization exception 
            service.TestService(dtInput ,ref dtOutput);
        }
        catch (Exception ex)
        {
        }
      } 

In your service

为您服务

      DataTable dtOutput= new DataTable();
      [WebMethod]
      public void TestService(DataTable dtInput , ref DataTable dtOutput)
      {
        DataRow drRow;
        drRow= dtInput.NewRow();
        drRow["ID"] = 2;
        drRow["Name"] = "Success";
        dtInput.Rows.Add(drRow);
        dtOutput= dtInput;
       }

回答by LifeiSHot

Just give a table name when create a datatable object

创建数据表对象时只需给出表名

DataTable dt = new DataTable("tablename");