Python 2.7.10 错误“从 urllib.request 导入 urlopen”没有名为 request 的模块
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Python 2.7.10 error "from urllib.request import urlopen" no module named request
提问by Steve Maguire
I opened python code from github. I assumed it was python2.xand got the above error when I tried to run it. From the reading I've seen Python 3 has depreciated urllibitself and replaced it with a number of libraries including urllib.request.
我从github. 我认为是这样python2.x，当我尝试运行它时出现了上述错误。从阅读中我看到 Python 3 已经贬值了urllib，取而代之的是许多库，包括urllib.request.
It looks like the code was written in python 3 (a confirmation from someone who knows would be appreciated.) At this point I don't want to move to Python 3 - I haven't researched what it would do to my existing code.
看起来代码是用 python 3 编写的（知道的人的确认将不胜感激。）此时我不想转移到 Python 3 - 我还没有研究它会对我现有的代码做什么。
Thinking there should be a urllibmodule for Python 2, I searched Google (using "python2 urllib download") and did not find one. (It might have been hidden in the many answers since urllibincludes downloading functionality.) I looked in my Python27/libdirectory and didn't see it there.
Can I get a version of this module that runs on Python27? Where and how?
认为应该有一个urllib模块Python 2，我搜索了谷歌（使用“python2 urllib下载”）并没有找到一个。（它可能隐藏在许多答案中，因为urllib包括下载功能。）我查看了我的Python27/lib目录，但没有在那里看到它。我可以获得在 上运行的此模块的版本Python27吗？在哪里以及如何？
回答by NevDev
Try using urllib2:
尝试使用 urllib2：
https://docs.python.org/2/library/urllib2.html
https://docs.python.org/2/library/urllib2.html
This line should work to replace urlopen:
这一行应该可以替代 urlopen：
from urllib2 import urlopen
Tested in Python 2.7 on Macbook Pro
在 Macbook Pro 上用 Python 2.7 测试
Try posting a link to the git in question.
尝试发布指向相关 git 的链接。
回答by Anand S Kumar
You are right the urlliband urllib2packages have been split into urllib.request, urllib.parseand urllib.errorpackages in Python 3.x. The latter packages do not exist in Python 2.x
你是对的urllib和urllib2包在 Python 3.x 中被拆分为urllib.request、urllib.parse和urllib.error包。后面的包在 Python 2.x 中不存在
From documentation-
从文档-
The urllib module has been split into parts and renamed in Python 3 to urllib.request, urllib.parse, and urllib.error.
urllib 模块已被拆分为多个部分，并在 Python 3 中重命名为 urllib.request、urllib.parse 和 urllib.error。
From urllib2documentation-
来自urllib2文档-
The urllib2 module has been split across several modules in Python 3 named urllib.request and urllib.error.
urllib2 模块在 Python 3 中被拆分为多个名为 urllib.request 和 urllib.error 的模块。
So I am pretty sure the code you downloaded has been written for Python 3.x , since they are using a library that is only present in Python 3.x .
所以我很确定你下载的代码是为 Python 3.x 编写的，因为它们使用的库只存在于 Python 3.x 中。
There is a urllibpackage in python, but it does not have the requestsubpackage. Also, lets assume you do lots of work and somehow make requestsubpackage available in Python 2.x .
python中有urllib包，但是没有request子包。此外，假设您做了大量工作，并以某种方式使请求子包在 Python 2.x 中可用。
There is a very very high probability that you will run into more issues, there is lots of incompatibility between Python 2.x and Python 3.x , in the end you would most probably end up rewriting atleast half the code from github (and most probably reading and understanding the complete code from there).
您很有可能会遇到更多问题，Python 2.x 和 Python 3.x 之间存在很多不兼容性，最后您很可能最终会重写 github 中至少一半的代码（以及大多数可能从那里阅读和理解完整的代码）。
Even then there may be other bugs arising from the fact that some of the implementation details changed between Python 2.x to Python 3.x (As an example - list comprehension got its own namespace in Python 3.x)
即便如此，由于某些实现细节在 Python 2.x 到 Python 3.x 之间发生变化，可能会产生其他错误（例如 - 列表理解在 Python 3.x 中有自己的命名空间）
You are better off trying to download and use Python 3 , than trying to make code written for Python 3.x compatible with Python 2.x
您最好尝试下载和使用 Python 3 ，而不是尝试使为 Python 3.x 编写的代码与 Python 2.x 兼容
回答by Jonathan Holloway
Instead of using urllib.request.urlopen() remove request for python 2.
而不是使用 urllib.request.urlopen() 删除 python 2 的请求。
urllib.urlopen() you do not have to request in python 2.x for what you are trying to do. Hope it works for you. This was tested using python 2.7 I was receiving the same error message and this resolved it.
urllib.urlopen() 你不必在 python 2.x 中请求你要做什么。希望对你有效。这是使用 python 2.7 测试的，我收到了相同的错误消息，这解决了它。
回答by user3291138
For now, it seems that I could get over that by adding a ?after the URL.
现在，我似乎可以通过?在 URL 后面添加一个来解决这个问题。
回答by Maciej Osowski
from urllib.request import urlopen, Request
Should solve everything
应该解决一切
回答by boardrider
You can program defensively, and do your import as:
您可以进行防御性编程，并按以下方式进行导入：
try:
from urllib.request import urlopen
except ImportError:
from urllib2 import urlopen
and then in the code, just use:
然后在代码中，只需使用：
data = urlopen(MIRRORS).read(AMOUNT2READ)
回答by ceekay
Change
改变
from urllib.request import urlopen
from urllib.request import urlopen
to
到
from urllib import urlopen
from urllib import urlopen
I was able to solve this problem by changing like this. For Python2.7in macOS10.14
我能够通过这样改变来解决这个问题。对于Python2.7在macOS10.14
