java 获取 HTTP 状态 400 - Spring 中不存在必需的 MultipartFile 参数“文件”
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Geting HTTP Status 400 - Required MultipartFile parameter 'file' is not present in spring
提问by Labeo
I am trying to upload a file using spring. Below is my code how I am working on it
but if I try to use it I am getting this response:
我正在尝试使用spring. 下面是我的代码，我是如何处理它的，但如果我尝试使用它，我会得到这个response：
HTTP Status 400 - Required MultipartFile parameter 'file' is not present
HTTP 状态 400 - 所需的 MultipartFile 参数“文件”不存在
I dont get what the error is.
我不明白错误是什么。
I am using advanced rest client for testing and I am uploading file as an attachment.
我正在使用高级休息客户端进行测试，并将文件作为附件上传。
My Javacode:
我的Java代码：
@RequestMapping(value = "/upload",headers = "Content-Type=multipart/form-data", method = RequestMethod.POST)
@ResponseBody
public String upload(@RequestParam("file") MultipartFile file)
{
String name= "test.xlsx";
if (!file.isEmpty()) {
try {
byte[] bytes = file.getBytes();
BufferedOutputStream stream =
new BufferedOutputStream(new FileOutputStream(new File(name)));
stream.write(bytes);
stream.close();
return "You successfully uploaded " + name + "!";
} catch (Exception e) {
return "You failed to upload " + name + " => " + e.getMessage();
}
} else {
return "You failed to upload " + name + " because the file was empty.";
}
}
采纳答案by Patrick
Spring needs the
春天需要
<bean id="multipartResolver" class="org.springframework.web.multipart.commons.CommonsMultipartResolver" />
<bean id="multipartResolver" class="org.springframework.web.multipart.commons.CommonsMultipartResolver" />
bean to handle file-uploads.
bean 来处理文件上传。
You should register this bean in your application contextfile.
你应该在你的application context文件中注册这个 bean 。
The Content-Type should also be valid. In your case enctype="multipart/form-data"
Content-Type 也应该是有效的。在你的情况下enctype="multipart/form-data"
EDIT1:
编辑1：
You can give the upload and memory size to the bean properties:
您可以为 bean 属性提供上传和内存大小：
<bean id="multipartResolver"
class="org.springframework.web.multipart.commons.CommonsMultipartResolver">
<!-- max upload size in bytes -->
<property name="maxUploadSize" value="20971520" /> <!-- 20MB -->
<!-- max size of file in memory (in bytes) -->
<property name="maxInMemorySize" value="1048576" /> <!-- 1MB -->
</bean>
回答by Sanjay Singh Rawat
when you select the file in advance rest client, on the right sidethere is a input box, write in that input box name of the parameter, in your case name of parameter is file
当您预先选择文件rest client时，右侧有一个输入框，在该输入框中输入参数名称，在您的情况下，参数名称为文件
Parameter name defined here in controller @RequestParam("file")
此处定义的参数名称在控制器@RequestParam("file")
回答by ed u
it works for me after i wrote in that input box name of the parameter "file" when i already have well configured the bean id in the Krajee bootstrap inputfile example ("https://github.com/kartik-v/bootstrap-fileinput").
当我已经在 Krajee 引导程序输入文件示例（“ https://github.com/kartik-v/bootstrap-fileinput”）。
