C# Decimal.Parse 和不正确的字符串格式错误
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Decimal.Parse and incorrect string format error
提问by Tony
I have a simple problem with decimal parsing. The following code works fine on my computer but when I publish the project on the server (VPS, Windows Server 2008 R2 standard edition) I get the error "Input string was in incorrect format." Any ideas what's wrong?
我有一个十进制解析的简单问题。以下代码在我的计算机上运行良好，但是当我在服务器（VPS、Windows Server 2008 R2 标准版）上发布项目时，出现错误“输入字符串的格式不正确”。任何想法有什么问题？
I store that parsed number in the MySQL DB table - the column type is DECIMAL(10, 4)
我将解析后的数字存储在 MySQL 数据库表中 - 列类型是 DECIMAL(10, 4)
Source Code:
源代码：
CultureInfo nonInvariantCulture = new CultureInfo("en-AU"); //or pl-PL
nonInvariantCulture.NumberFormat.NumberDecimalSeparator = ".";
Thread.CurrentThread.CurrentCulture = nonInvariantCulture;
string toConvert = ("3,4589").Replace(",", "."); //it's an example
decimal parsed = decimal.Parse(toConvert);
采纳答案by Martin Liversage
If you know that the string representation of the number uses comma as the decimal separator you can parse the value using a custom NumberFormatInfo:
如果您知道数字的字符串表示使用逗号作为小数点分隔符，您可以使用自定义来解析该值NumberFormatInfo：
var number = "3,4589";
var numberFormatInfo = new NumberFormatInfo { NumberDecimalSeparator = "," };
var value = Decimal.Parse(number, numberFormatInfo);
You can also use an existing CultureInfofor a culture that you know will work like pl-PLbut I think this is easier to understand.
您也可以将现有CultureInfo的文化用于您知道会起作用的文化，pl-PL但我认为这更容易理解。
If on the other hand the format of the number is 3.4589you can simply use CultureInfo.InvariantCulturewhich you can consider a kind of "default" culture based on en-US:
另一方面，如果数字的格式是3.4589您可以简单地使用CultureInfo.InvariantCulture它，您可以考虑一种基于以下内容的“默认”文化en-US：
var number = "3.4589";
var value = Decimal.Parse(number, CultureInfo.InvariantCulture);
回答by V4Vendetta
You can build a custom NumberFormatInfoto parse your value
您可以构建自定义NumberFormatInfo来解析您的值
something on these lines
这些线上的东西
NumberFormatInfo numinf = new NumberFormatInfo();
numinf.NumberDecimalSeparator= ",";
decimal.Parse("3,4589", numinf);
回答by Smaug
I guess for a work around the below code will sort it out the problem.
我想解决以下代码可以解决问题。
decimal parsed = decimal.Parse(toConvert, CultureInfo.InvariantCulture);
