java 当字符串包含 [] 个字符时替换字符串中的子字符串
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replace substring in string when string contains [] characters
提问by mbrc
I want to replace substringin string. For example:
我想替换 substringin 字符串。例如：
localStringBuilder is for example "[sender] is xxxx xxxx xxx".
and when I run
当我跑步时
localStringBuilder.toString().replaceAll("[sender]", callerName);
not working correctly. Prblem is with []characters. How to solve this?
工作不正常。问题在于[]字符。如何解决这个问题？
采纳答案by dantuch
Just use replacein place of replaceAll
只用replace代替replaceAll
replaceAlltake REGEX as input, not a String, but regex. []are important parts of regexes using to group expressions.
replaceAll将 REGEX 作为输入，不是字符串，而是正则表达式。[]是正则表达式的重要组成部分，用于对表达式进行分组。
localStringBuilder.toString().replace("[sender]", callerName);will work exaclty as you expect, because it takes normal Strings as both parameters.
localStringBuilder.toString().replace("[sender]", callerName);将按照您的预期工作，因为它将普通字符串作为两个参数。
is the same. Works when is no [] characters in string– @mbrc 1 min ago
is the same. Works when is no [] characters in string– @mbrc 1 分钟前
not true, I've testedit:
不是真的，我已经测试过了：
public static void main(String[] args) {
String s = "asd[something]123";
String replace = s.replace("[something]", "new1");
System.out.println(replace);
}
output: asdnew1123
输出：asdnew1123
回答by DJClayworth
replaceAll returns a new string with the replacement. It doesn't replace the characters in the original string.
replaceAll 返回一个带有替换的新字符串。它不会替换原始字符串中的字符。
String newString = localStringBuilder.toString().replaceAll("[sender]", callerName);
String newString = localStringBuilder.toString().replaceAll("[sender]", callerName);
回答by Ransom Briggs
Use this
用这个
localStringBuilder.toString().replaceAll("\[sender\]", callerName);
回答by Dan D.
This works:
这有效：
locaStringBuilder.toString().replaceAll("\[sender\]", callerName);
