string Shell 脚本变量替换字符
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Shell script variable replacing characters
提问by thetux4
I have a variable var="abcde$$$$$$$$fff$$gg". I want to replace all $ with space ' ' but the following puts just one space
我有一个变量 var="abcde$$$$$$$$fff$$gg"。我想用空格 ' ' 替换所有 $ 但下面只放一个空格
var=$( echo "$var" | tr '$' ' ')
How can i replace them all?
我怎样才能全部替换它们？
回答by ghostdog74
you can replace without calling external commands (using bash)
您可以在不调用外部命令的情况下进行替换（使用 bash）
$ var='abcde$$$$$$$$fff$$gg'
$ echo "${var//$/ }"
abcde fff gg
Note that you should use single quotes so that the "$" sign does not get interpolated
请注意，您应该使用单引号，以便“$”符号不会被插入
回答by l0b0
Works for me. You'll need to use single quotes or escape the dollar signs, otherwise they are removed from the double-quoted string:
对我来说有效。您需要使用单引号或转义美元符号，否则它们将从双引号字符串中删除：
echo 'abcde$$$$$$$$fff$$gg' | tr '$' ' '
abcde fff gg
echo "abcde$$$$$$$$fff$$gg" | tr '$' ' '
abcde fff gg
echo abcde$$$$$$$$fff$$gg | tr '$' ' '
abcde fff gg
echo $'abcde$$$$$$$$fff$$gg' | tr '$' ' '
abcde fff gg
回答by Swepter
Old question, but I write this for them hwo will come here after a search with their diseired search engine You have to use echo -elike this
老问题，但我写这为他们与他们的diseired搜索引擎搜索后藿会来这里，你必须使用echo -e类似这样的
var="$( echo -e "$var" | tr '$' ' ' )"
