每天在同一时间做某事的 Python 脚本
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Python script to do something at the same time every day
提问by Paul McKenzie
采纳答案by sissi_luaty
You can do that like this:
你可以这样做：
from datetime import datetime
from threading import Timer
x=datetime.today()
y=x.replace(day=x.day+1, hour=1, minute=0, second=0, microsecond=0)
delta_t=y-x
secs=delta_t.seconds+1
def hello_world():
print "hello world"
#...
t = Timer(secs, hello_world)
t.start()
This will execute a function (eg. hello_world) in the next day at 1a.m.
这将在第二天凌晨 1 点执行一个函数（例如 hello_world）。
EDIT:
编辑：
As suggested by @PaulMag, more generally, in order to detect if the day of the month must be reset due to the reaching of the end of the month, the definition of y in this context shall be the following:
正如@PaulMag 所建议的那样，更一般地，为了检测是否由于到达月底而必须重置月份中的日期，在这种情况下 y 的定义应如下所示：
y = x.replace(day=x.day, hour=1, minute=0, second=0, microsecond=0) + timedelta(days=1)
With this fix, it is also needed to add timedelta to the imports. The other code lines maintain the same. The full solution, using also the total_seconds() function, is therefore:
使用此修复程序，还需要将 timedelta 添加到导入中。其他代码行保持相同。因此，还使用 total_seconds() 函数的完整解决方案是：
from datetime import datetime, timedelta
from threading import Timer
x=datetime.today()
y = x.replace(day=x.day, hour=1, minute=0, second=0, microsecond=0) + timedelta(days=1)
delta_t=y-x
secs=delta_t.total_seconds()
def hello_world():
print "hello world"
#...
t = Timer(secs, hello_world)
t.start()
回答by Paul Collingwood
APScheduler might be what you are after.
APScheduler 可能就是您所追求的。
from datetime import date
from apscheduler.scheduler import Scheduler
# Start the scheduler
sched = Scheduler()
sched.start()
# Define the function that is to be executed
def my_job(text):
print text
# The job will be executed on November 6th, 2009
exec_date = date(2009, 11, 6)
# Store the job in a variable in case we want to cancel it
job = sched.add_date_job(my_job, exec_date, ['text'])
# The job will be executed on November 6th, 2009 at 16:30:05
job = sched.add_date_job(my_job, datetime(2009, 11, 6, 16, 30, 5), ['text'])
https://apscheduler.readthedocs.io/en/latest/
https://apscheduler.readthedocs.io/en/latest/
You can just get it to schedule another run by building that into the function you are scheduling.
您可以通过将其构建到您正在调度的函数中来让它安排另一次运行。
回答by user2099484
I spent quite a bit of time also looking to launch a simple Python program at 01:00. For some reason, I couldn't get cronto launch it and APScheduler seemed rather complex for something that should be simple. Schedule (https://pypi.python.org/pypi/schedule) seemed about right.
我还花了很多时间寻找在 01:00 启动一个简单的 Python 程序。出于某种原因，我无法让cron来启动它，而 APScheduler 对于一些应该很简单的东西来说似乎相当复杂。时间表（https://pypi.python.org/pypi/schedule）似乎是正确的。
You will have to install their Python library:
您必须安装他们的 Python 库：
pip install schedule
This is modified from their sample program:
这是从他们的示例程序中修改的：
import schedule
import time
def job(t):
print "I'm working...", t
return
schedule.every().day.at("01:00").do(job,'It is 01:00')
while True:
schedule.run_pending()
time.sleep(60) # wait one minute
You will need to put your own function in place of job and run it with nohup, e.g.:
您需要将自己的功能放在工作位置并使用 nohup 运行它，例如：
nohup python2.7 MyScheduledProgram.py &
Don't forget to start it again if you reboot.
如果您重新启动，请不要忘记再次启动它。
回答by Ankit
I needed something similar for a task. This is the code I wrote: It calculates the next day and changes the time to whatever is required and finds seconds between currentTime and next scheduled time.
我需要类似的东西来完成任务。这是我写的代码：它计算第二天并将时间更改为所需的任何时间，并在 currentTime 和下一个预定时间之间找到秒数。
import datetime as dt
def my_job():
print "hello world"
nextDay = dt.datetime.now() + dt.timedelta(days=1)
dateString = nextDay.strftime('%d-%m-%Y') + " 01-00-00"
newDate = nextDay.strptime(dateString,'%d-%m-%Y %H-%M-%S')
delay = (newDate - dt.datetime.now()).total_seconds()
Timer(delay,my_job,()).start()
