ios 如何从十六进制字符串创建 UIColor？
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/1560081/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
How can I create a UIColor from a hex string?
提问by Rupesh
How can I create a UIColorfrom a hexadecimalstring format, such as #00FF00?
如何UIColor从十六进制字符串格式创建一个，例如#00FF00？
回答by Tom
I've found the simplest way to do this is with a macro. Just include it in your header and it's available throughout your project.
我发现最简单的方法是使用宏。只需将它包含在您的标题中，它就可以在您的整个项目中使用。
#define UIColorFromRGB(rgbValue) [UIColor colorWithRed:((float)((rgbValue & 0xFF0000) >> 16))/255.0 green:((float)((rgbValue & 0xFF00) >> 8))/255.0 blue:((float)(rgbValue & 0xFF))/255.0 alpha:1.0]
Also formatted version of this code:
此代码的也格式化版本：
#define UIColorFromRGB(rgbValue) \
[UIColor colorWithRed:((float)((rgbValue & 0xFF0000) >> 16))/255.0 \
green:((float)((rgbValue & 0x00FF00) >> 8))/255.0 \
blue:((float)((rgbValue & 0x0000FF) >> 0))/255.0 \
alpha:1.0]
Usage:
用法：
label.textColor = UIColorFromRGB(0xBC1128);
回答by darrinm
A concise solution:
一个简洁的解决方案：
// Assumes input like "#00FF00" (#RRGGBB).
+ (UIColor *)colorFromHexString:(NSString *)hexString {
unsigned rgbValue = 0;
NSScanner *scanner = [NSScanner scannerWithString:hexString];
[scanner setScanLocation:1]; // bypass '#' character
[scanner scanHexInt:&rgbValue];
return [UIColor colorWithRed:((rgbValue & 0xFF0000) >> 16)/255.0 green:((rgbValue & 0xFF00) >> 8)/255.0 blue:(rgbValue & 0xFF)/255.0 alpha:1.0];
}
回答by Micah Hainline
I've got a solution that is 100% compatible with the hex format strings used by Android, which I found very helpful when doing cross-platform mobile development. It lets me use one color palate for both platforms. Feel free to reuse without attribution, or under the Apache license if you prefer.
我有一个与 Android 使用的十六进制格式字符串 100% 兼容的解决方案，我发现它在进行跨平台移动开发时非常有用。它让我可以为两个平台使用一种颜色。随意重用，无需署名，或者如果您愿意，可以在 Apache 许可下重用。
#import "UIColor+HexString.h"
@interface UIColor(HexString)
+ (UIColor *) colorWithHexString: (NSString *) hexString;
+ (CGFloat) colorComponentFrom: (NSString *) string start: (NSUInteger) start length: (NSUInteger) length;
@end
@implementation UIColor(HexString)
+ (UIColor *) colorWithHexString: (NSString *) hexString {
NSString *colorString = [[hexString stringByReplacingOccurrencesOfString: @"#" withString: @""] uppercaseString];
CGFloat alpha, red, blue, green;
switch ([colorString length]) {
case 3: // #RGB
alpha = 1.0f;
red = [self colorComponentFrom: colorString start: 0 length: 1];
green = [self colorComponentFrom: colorString start: 1 length: 1];
blue = [self colorComponentFrom: colorString start: 2 length: 1];
break;
case 4: // #ARGB
alpha = [self colorComponentFrom: colorString start: 0 length: 1];
red = [self colorComponentFrom: colorString start: 1 length: 1];
green = [self colorComponentFrom: colorString start: 2 length: 1];
blue = [self colorComponentFrom: colorString start: 3 length: 1];
break;
case 6: // #RRGGBB
alpha = 1.0f;
red = [self colorComponentFrom: colorString start: 0 length: 2];
green = [self colorComponentFrom: colorString start: 2 length: 2];
blue = [self colorComponentFrom: colorString start: 4 length: 2];
break;
case 8: // #AARRGGBB
alpha = [self colorComponentFrom: colorString start: 0 length: 2];
red = [self colorComponentFrom: colorString start: 2 length: 2];
green = [self colorComponentFrom: colorString start: 4 length: 2];
blue = [self colorComponentFrom: colorString start: 6 length: 2];
break;
default:
[NSException raise:@"Invalid color value" format: @"Color value %@ is invalid. It should be a hex value of the form #RBG, #ARGB, #RRGGBB, or #AARRGGBB", hexString];
break;
}
return [UIColor colorWithRed: red green: green blue: blue alpha: alpha];
}
+ (CGFloat) colorComponentFrom: (NSString *) string start: (NSUInteger) start length: (NSUInteger) length {
NSString *substring = [string substringWithRange: NSMakeRange(start, length)];
NSString *fullHex = length == 2 ? substring : [NSString stringWithFormat: @"%@%@", substring, substring];
unsigned hexComponent;
[[NSScanner scannerWithString: fullHex] scanHexInt: &hexComponent];
return hexComponent / 255.0;
}
@end
回答by Tommie C.
There's a nice post on how to tackle the OP's question of extracting a UIColorfrom a hex string. The solution presented below is different from others because it supports string values that may include '0x' or '#' prefixed to the hex string representation... (see usage)
有一篇关于如何解决 OPUIColor从十六进制字符串中提取 a 的问题的好帖子。下面介绍的解决方案与其他解决方案不同，因为它支持的字符串值可能包括前缀为十六进制字符串表示的“0x”或“#”...（请参阅用法）
Here's the main bit...
这是主要的一点...
- (UIColor *)getUIColorObjectFromHexString:(NSString *)hexStr alpha:(CGFloat)alpha
{
// Convert hex string to an integer
unsigned int hexint = [self intFromHexString:hexStr];
// Create a color object, specifying alpha as well
UIColor *color =
[UIColor colorWithRed:((CGFloat) ((hexint & 0xFF0000) >> 16))/255
green:((CGFloat) ((hexint & 0xFF00) >> 8))/255
blue:((CGFloat) (hexint & 0xFF))/255
alpha:alpha];
return color;
}
Helper method...
辅助方法...
- (unsigned int)intFromHexString:(NSString *)hexStr
{
unsigned int hexInt = 0;
// Create scanner
NSScanner *scanner = [NSScanner scannerWithString:hexStr];
// Tell scanner to skip the # character
[scanner setCharactersToBeSkipped:[NSCharacterSet characterSetWithCharactersInString:@"#"]];
// Scan hex value
[scanner scanHexInt:&hexInt];
return hexInt;
}
Usage:
用法：
NSString *hexStr1 = @"123ABC";
NSString *hexStr2 = @"#123ABC";
NSString *hexStr3 = @"0x123ABC";
UIColor *color1 = [self getUIColorObjectFromHexString:hexStr1 alpha:.9];
NSLog(@"UIColor: %@", color1);
UIColor *color2 = [self getUIColorObjectFromHexString:hexStr2 alpha:.9];
NSLog(@"UIColor: %@", color2);
UIColor *color3 = [self getUIColorObjectFromHexString:hexStr3 alpha:.9];
NSLog(@"UIColor: %@", color3);
Swift 2+
斯威夫特 2+
I've ported this solution to Swift 2.2. Note that I've changed the alphaparameter to use a default set to 1.0. I've also updated the int type to UInt32as required by the NSScannerclass in Swift 2.2.
我已将此解决方案移植到 Swift 2.2。请注意，我已将alpha参数更改为使用默认设置为 1.0。我还UInt32根据NSScannerSwift 2.2 中的类的要求更新了 int 类型。
func colorWithHexString(hexString: String, alpha:CGFloat = 1.0) -> UIColor {
// Convert hex string to an integer
let hexint = Int(self.intFromHexString(hexString))
let red = CGFloat((hexint & 0xff0000) >> 16) / 255.0
let green = CGFloat((hexint & 0xff00) >> 8) / 255.0
let blue = CGFloat((hexint & 0xff) >> 0) / 255.0
// Create color object, specifying alpha as well
let color = UIColor(red: red, green: green, blue: blue, alpha: alpha)
return color
}
func intFromHexString(hexStr: String) -> UInt32 {
var hexInt: UInt32 = 0
// Create scanner
let scanner: NSScanner = NSScanner(string: hexStr)
// Tell scanner to skip the # character
scanner.charactersToBeSkipped = NSCharacterSet(charactersInString: "#")
// Scan hex value
scanner.scanHexInt(&hexInt)
return hexInt
}
Swift 4+
斯威夫特 4+
Using the same logic with changes applied for swift 4,
对适用于 swift 4 的更改使用相同的逻辑，
func colorWithHexString(hexString: String, alpha:CGFloat = 1.0) -> UIColor {
// Convert hex string to an integer
let hexint = Int(self.intFromHexString(hexStr: hexString))
let red = CGFloat((hexint & 0xff0000) >> 16) / 255.0
let green = CGFloat((hexint & 0xff00) >> 8) / 255.0
let blue = CGFloat((hexint & 0xff) >> 0) / 255.0
// Create color object, specifying alpha as well
let color = UIColor(red: red, green: green, blue: blue, alpha: alpha)
return color
}
func intFromHexString(hexStr: String) -> UInt32 {
var hexInt: UInt32 = 0
// Create scanner
let scanner: Scanner = Scanner(string: hexStr)
// Tell scanner to skip the # character
scanner.charactersToBeSkipped = CharacterSet(charactersIn: "#")
// Scan hex value
scanner.scanHexInt32(&hexInt)
return hexInt
}
Color Hex References
颜色十六进制参考
回答by Ethan Strider
This is a function that takes a hex string and returns a UIColor.
(You can enter hex strings with either format: #ffffffor ffffff)
这是一个接受十六进制字符串并返回 UIColor 的函数。
（您可以使用以下任一格式输入十六进制字符串：#ffffff或ffffff）
Usage:
用法：
var color1 = hexStringToUIColor("#d3d3d3")
Swift 4:
斯威夫特 4：
func hexStringToUIColor (hex:String) -> UIColor {
var cString:String = hex.trimmingCharacters(in: .whitespacesAndNewlines).uppercased()
if (cString.hasPrefix("#")) {
cString.remove(at: cString.startIndex)
}
if ((cString.count) != 6) {
return UIColor.gray
}
var rgbValue:UInt32 = 0
Scanner(string: cString).scanHexInt32(&rgbValue)
return UIColor(
red: CGFloat((rgbValue & 0xFF0000) >> 16) / 255.0,
green: CGFloat((rgbValue & 0x00FF00) >> 8) / 255.0,
blue: CGFloat(rgbValue & 0x0000FF) / 255.0,
alpha: CGFloat(1.0)
)
}
Swift 3:
斯威夫特 3：
func hexStringToUIColor (hex:String) -> UIColor {
var cString:String = hex.trimmingCharacters(in: .whitespacesAndNewlines).uppercased()
if (cString.hasPrefix("#")) {
cString.remove(at: cString.startIndex)
}
if ((cString.characters.count) != 6) {
return UIColor.gray
}
var rgbValue:UInt32 = 0
Scanner(string: cString).scanHexInt32(&rgbValue)
return UIColor(
red: CGFloat((rgbValue & 0xFF0000) >> 16) / 255.0,
green: CGFloat((rgbValue & 0x00FF00) >> 8) / 255.0,
blue: CGFloat(rgbValue & 0x0000FF) / 255.0,
alpha: CGFloat(1.0)
)
}
Swift 2:
斯威夫特 2：
func hexStringToUIColor (hex:String) -> UIColor {
var cString:String = hex.stringByTrimmingCharactersInSet(NSCharacterSet.whitespaceAndNewlineCharacterSet() as NSCharacterSet).uppercaseString
if (cString.hasPrefix("#")) {
cString = cString.substringFromIndex(cString.startIndex.advancedBy(1))
}
if ((cString.characters.count) != 6) {
return UIColor.grayColor()
}
var rgbValue:UInt32 = 0
NSScanner(string: cString).scanHexInt(&rgbValue)
return UIColor(
red: CGFloat((rgbValue & 0xFF0000) >> 16) / 255.0,
green: CGFloat((rgbValue & 0x00FF00) >> 8) / 255.0,
blue: CGFloat(rgbValue & 0x0000FF) / 255.0,
alpha: CGFloat(1.0)
)
}
Source: arshad/gist:de147c42d7b3063ef7bc
回答by Damien Romito
Use this Category :
使用此类别：
in the file UIColor+Hexadecimal.h
在文件UIColor+Hexadecimal.h 中
#import <UIKit/UIKit.h>
@interface UIColor(Hexadecimal)
+ (UIColor *)colorWithHexString:(NSString *)hexString;
@end
in the file UIColor+Hexadecimal.m
在文件UIColor+Hexadecimal.m 中
#import "UIColor+Hexadecimal.h"
@implementation UIColor(Hexadecimal)
+ (UIColor *)colorWithHexString:(NSString *)hexString {
unsigned rgbValue = 0;
NSScanner *scanner = [NSScanner scannerWithString:hexString];
[scanner setScanLocation:1]; // bypass '#' character
[scanner scanHexInt:&rgbValue];
return [UIColor colorWithRed:((rgbValue & 0xFF0000) >> 16)/255.0 green:((rgbValue & 0xFF00) >> 8)/255.0 blue:(rgbValue & 0xFF)/255.0 alpha:1.0];
}
@end
In Class you want use it :
在课堂上你想使用它：
#import "UIColor+Hexadecimal.h"
and:
和：
[UIColor colorWithHexString:@"#6e4b4b"];
回答by Firo
A great Swift implementation (updated for Xcode 7) using extensions, pulled together from a variety of different answers and places. You will also need the string extensions at the end.
一个伟大的 Swift 实现（针对 Xcode 7 更新）使用扩展，从各种不同的答案和地方汇集在一起。最后还需要字符串扩展。
Use:
用：
let hexColor = UIColor(hex: "#00FF00")
NOTE: I added an option for 2 additional digits to the end of the standard 6 digit hex value for an alpha channel (pass in value of 00-99). If this offends you, just remove it. You could implement it to pass in an optional alpha parameter.
注意：我在 alpha 通道的标准 6 位十六进制值的末尾添加了 2 个额外数字的选项（传入值00- 99）。如果这冒犯了您，请将其删除。您可以实现它以传入可选的 alpha 参数。
Extension:
延期：
extension UIColor {
convenience init(var hex: String) {
var alpha: Float = 100
let hexLength = hex.characters.count
if !(hexLength == 7 || hexLength == 9) {
// A hex must be either 7 or 9 characters (#RRGGBBAA)
print("improper call to 'colorFromHex', hex length must be 7 or 9 chars (#GGRRBBAA)")
self.init(white: 0, alpha: 1)
return
}
if hexLength == 9 {
// Note: this uses String subscripts as given below
alpha = hex[7...8].floatValue
hex = hex[0...6]
}
// Establishing the rgb color
var rgb: UInt32 = 0
let s: NSScanner = NSScanner(string: hex)
// Setting the scan location to ignore the leading `#`
s.scanLocation = 1
// Scanning the int into the rgb colors
s.scanHexInt(&rgb)
// Creating the UIColor from hex int
self.init(
red: CGFloat((rgb & 0xFF0000) >> 16) / 255.0,
green: CGFloat((rgb & 0x00FF00) >> 8) / 255.0,
blue: CGFloat(rgb & 0x0000FF) / 255.0,
alpha: CGFloat(alpha / 100)
)
}
}
String extensions:
Float source
Subscript source
extension String {
/**
Returns the float value of a string
*/
var floatValue: Float {
return (self as NSString).floatValue
}
/**
Subscript to allow for quick String substrings ["Hello"][0...1] = "He"
*/
subscript (r: Range<Int>) -> String {
get {
let start = self.startIndex.advancedBy(r.startIndex)
let end = self.startIndex.advancedBy(r.endIndex - 1)
return self.substringWithRange(start..<end)
}
}
}
回答by Manu Gupta
You can make a extension like this
你可以做这样的扩展
extension UIColor{
convenience init(rgb: UInt, alphaVal: CGFloat) {
self.init(
red: CGFloat((rgb & 0xFF0000) >> 16) / 255.0,
green: CGFloat((rgb & 0x00FF00) >> 8) / 255.0,
blue: CGFloat(rgb & 0x0000FF) / 255.0,
alpha: alphaVal
)
}
}
And use it anywhere like this
并在任何地方使用它
UIColor(rgb: 0xffffff, alphaVal: 0.2)
回答by Adam Wright
There is no builtin conversion from a hexadecimal string to a UIColor(or CGColor) that I'm aware of. However, you can easily write a couple of functions for this purpose - for example, see iphone development accessing uicolor components
没有从十六进制字符串到我所知道的UIColor(或CGColor) 的内置转换。但是，您可以为此目的轻松编写几个函数 - 例如，请参阅iphone development accessing uicolor components
回答by Hlung
I found a good UIColorcategory for this, UIColor+PXExtensions.
我UIColor为此找到了一个很好的类别，UIColor+PXExtensions。
Usage: UIColor *mycolor = [UIColor pxColorWithHexValue:@"#BADA55"];
用法： UIColor *mycolor = [UIColor pxColorWithHexValue:@"#BADA55"];
And, just in case the link to my gist fails, here is the actual implementation code:
而且，以防万一到我的要点的链接失败，这里是实际的实现代码：
//
// UIColor+PXExtensions.m
//
#import "UIColor+UIColor_PXExtensions.h"
@implementation UIColor (UIColor_PXExtensions)
+ (UIColor*)pxColorWithHexValue:(NSString*)hexValue
{
//Default
UIColor *defaultResult = [UIColor blackColor];
//Strip prefixed # hash
if ([hexValue hasPrefix:@"#"] && [hexValue length] > 1) {
hexValue = [hexValue substringFromIndex:1];
}
//Determine if 3 or 6 digits
NSUInteger componentLength = 0;
if ([hexValue length] == 3)
{
componentLength = 1;
}
else if ([hexValue length] == 6)
{
componentLength = 2;
}
else
{
return defaultResult;
}
BOOL isValid = YES;
CGFloat components[3];
//Seperate the R,G,B values
for (NSUInteger i = 0; i < 3; i++) {
NSString *component = [hexValue substringWithRange:NSMakeRange(componentLength * i, componentLength)];
if (componentLength == 1) {
component = [component stringByAppendingString:component];
}
NSScanner *scanner = [NSScanner scannerWithString:component];
unsigned int value;
isValid &= [scanner scanHexInt:&value];
components[i] = (CGFloat)value / 256.0f;
}
if (!isValid) {
return defaultResult;
}
return [UIColor colorWithRed:components[0]
green:components[1]
blue:components[2]
alpha:1.0];
}
@end
