如何以编程方式确定驱动器的空间/大小？在 Linux 和 Windows 上
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原文地址: http://stackoverflow.com/questions/1960421/
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How can I determine the space/size of my drive programatically? Both in LInux and on Windows
提问by Shaobo Wang
That is : How can I check the drive size which is not formatted... Don't consider the formatted drives...just unformatted drive.
即：如何检查未格式化的驱动器大小...不要考虑已格式化的驱动器...只是未格式化的驱动器。
采纳答案by Eric Seppanen
Under Linux, if you want the size of the entire drive, read /sys/block/sda/size.
在 Linux 下，如果您想要整个驱动器的大小，请阅读/sys/block/sda/size.
To find the size of a partition, read /sys/block/sda/sda1/size.
要查找分区的大小，请阅读/sys/block/sda/sda1/size。
Replace sda, sda1with names of your devices/partitions.
将sda,替换sda1为您的设备/分区的名称。
Or, if you can open the raw device file, you can use the BLKGETSIZEioctl.
或者，如果您可以打开原始设备文件，则可以使用BLKGETSIZEioctl.
回答by CodingLab
for windows.. you can use DeviceIoControl().
对于 Windows.. 你可以使用 DeviceIoControl()。
#include <windows.h>
#include <winioctl.h>
#include <stdio.h>
BOOL GetDriveGeometry(DISK_GEOMETRY *pdg)
{
HANDLE hDevice; // handle to the drive to be examined
BOOL bResult; // results flag
DWORD junk; // discard results
hDevice = CreateFile(TEXT("\\.\PhysicalDrive0"), // drive
0, // no access to the drive
FILE_SHARE_READ | // share mode
FILE_SHARE_WRITE,
NULL, // default security attributes
OPEN_EXISTING, // disposition
0, // file attributes
NULL); // do not copy file attributes
if (hDevice == INVALID_HANDLE_VALUE) // cannot open the drive
{
return (FALSE);
}
bResult = DeviceIoControl(hDevice, // device to be queried
IOCTL_DISK_GET_DRIVE_GEOMETRY, // operation to perform
NULL, 0, // no input buffer
pdg, sizeof(*pdg), // output buffer
&junk, // # bytes returned
(LPOVERLAPPED) NULL); // synchronous I/O
CloseHandle(hDevice);
return (bResult);
}
int main(int argc, char *argv[])
{
DISK_GEOMETRY pdg; // disk drive geometry structure
BOOL bResult; // generic results flag
ULONGLONG DiskSize; // size of the drive, in bytes
bResult = GetDriveGeometry (&pdg);
if (bResult)
{
printf("Cylinders = %I64d\n", pdg.Cylinders);
printf("Tracks/cylinder = %ld\n", (ULONG) pdg.TracksPerCylinder);
printf("Sectors/track = %ld\n", (ULONG) pdg.SectorsPerTrack);
printf("Bytes/sector = %ld\n", (ULONG) pdg.BytesPerSector);
DiskSize = pdg.Cylinders.QuadPart * (ULONG)pdg.TracksPerCylinder *
(ULONG)pdg.SectorsPerTrack * (ULONG)pdg.BytesPerSector;
printf("Disk size = %I64d (Bytes) = %I64d (Gb)\n", DiskSize,
DiskSize / (1024 * 1024 * 1024));
}
else
{
printf ("GetDriveGeometry failed. Error %ld.\n", GetLastError ());
}
return ((int)bResult);
}
回答by mwfearnley
Programmatically in Linux:
在 Linux 中以编程方式：
#include <fcntl.h>
#include <linux/fs.h>
#include <sys/ioctl.h>
#include <stdio.h>
#include <unistd.h>
int main(int argc, char **argv)
{
int fd;
unsigned long long numblocks=0;
fd = open(argv[1], O_RDONLY);
ioctl(fd, BLKGETSIZE64, &numblocks);
close(fd);
printf("Number of bytes: %llu, this makes %.3f GB\n",
numblocks,
(double)numblocks / (1024 * 1024 * 1024));
}
This is basically the code from http://www.linuxproblem.org/art_20.html, adapted to use BLKGETSIZE64, with various warnings fixed.
这基本上是来自http://www.linuxproblem.org/art_20.html的代码，适合使用BLKGETSIZE64，并修复了各种警告。
