jQuery 未捕获的语法错误:意外的令牌非法
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Uncaught SyntaxError: Unexpected token ILLEGAL
提问by sathis
May i know whats wrong in this.I am new to world of programing ..So if you help me it would be wonderful.The error comes on the line
我可以知道这有什么问题吗。我是编程世界的新手..所以如果你能帮助我那就太好了。错误就行了
arr[${i.count-1}][1]=${employee.email};
arr[${i.count-1}][1]=${employee.email};
Awaiting for your response.The entire Code as follows..
等待您的回复。整个代码如下..
$(function() {
var arr = new Array();
arr[0]=new Array(4);
arr[0][0]=sathis;
arr[0][1][email protected];
arr[0][2]=namakkal;
arr[0][3]=21;
arr[1]=new Array(4);
arr[1][0]=ganesh;
arr[1][1][email protected];
arr[1][2]=karaikudi;
arr[1][3]=22;
arr[2]=new Array(4);
arr[2][0]=karthik;
arr[2][1][email protected];
arr[2][2]=trichy;
arr[2][3]=25;
var str="<table><tr><th>Name</th><th>Email</th><th>City</th><th>Age</th></tr><tr><td>";
$("#emp_name").change(function() {
var i=$(this).val();
str=str+arr[i-1][0]+"</td><td>"+arr[i-1][1]+"</td><td>"+arr[i-1][2]+"</td><td>"+arr[i-1][3]+"</td><tr></table>";
$("#viewer").html(str);
alert(str);
});
});
回答by that person
You need quotes for strings.
For example, you need arr[0][0]='sathis';
instead of arr[0][0]=sathis;
您需要字符串的引号。例如,您需要arr[0][0]='sathis';
代替arr[0][0]=sathis;
Also, there's an easier way to do arrays:
此外,还有一种更简单的方法来处理数组:
arr[0] = ['sathis', '[email protected]', 'namakkal', 21];
回答by taco
As [user:638452] pointed out, this could be a bad invisible character. Backspaced over an invisible character where Javascript told me the error was, and my code worked without modification.
正如 [user:638452] 指出的那样,这可能是一个不好的隐形字符。在 Javascript 告诉我错误所在的不可见字符上退格,并且我的代码无需修改即可运行。