C++ 如何调用模板成员函数？
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/12676190/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
How to call a template member function?
提问by ritter
Possible Duplicate:
C++ template member function of template class called from template function
可能的重复：
从模板函数调用的模板类的 C++ 模板成员函数
template<class T1>
class A
{
public:
template<class T0>
void foo() const {}
};
template<class T0,class T1>
void bar( const A<T1>& b )
{
b.foo<T0>(); // This throws " expected primary-expression before ‘>' token"
}
I can change it to
我可以把它改成
b->A<T1>::template foo<T0>();
which compiles fine. However I can also change it to
编译得很好。但是我也可以将其更改为
b.A<T1>::template foo<T0>();
which compiles fine too. eh?
这也编译得很好。嗯？
How does one correctly call the template member function in the sense of the original code?
如何正确调用原代码意义上的模板成员函数？
回答by ritter
Just found it:
刚发现：
According to C++'03 Standard 14.2/4:
根据 C++'03 标准 14.2/4：
When the name of a member template specialization appears after
.or->in a postfix-expression, or after nested-name-specifier in a qualified-id, and the postfix-expression or qualified-id explicitly depends on a template-parameter (14.6.2), the member template name must be prefixed by the keywordtemplate. Otherwise the name is assumed to name a non-template.
当成员模板特化的名称出现在后缀表达式之后
.或->中，或在限定 id 中的嵌套名称说明符之后，并且后缀表达式或限定 id 显式依赖于模板参数 (14.6.2 )，成员模板名称必须以关键字 为前缀template。否则，假定该名称命名为非模板。
Correct code is:
正确的代码是：
b.template foo<T0>();
回答by Ninten
you can call the function this way:
你可以这样调用函数：
b.template foo<T0>();
