java 从java中的hashMaps列表的值中获取键

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时间:2020-11-03 00:32:17  来源:igfitidea点击:

Get the key from the value of a list of hashMaps in java

javaarraylisthashmap

提问by Eric G

I have 4 hashMaps:

我有 4 个 hashMap:

         Map <String, Integer> item1 =new HashMap<String, Integer>();
         Map <String, Integer> item2 =new HashMap<String, Integer>();
         Map <String, Integer> item3 =new HashMap<String, Integer>();
         Map <String, Integer> item4 =new HashMap<String, Integer>();  

I added the 4 of them to a list:

我将其中的 4 个添加到列表中:

       List<Map> Items= new ArrayList<>();
        Items.add(item1);
        Items.add(item2);
        Items.add(item3);
        Items.add(item4);

I wanted to get the key from the value using the list of hashMaps "Items" So I tried this code:

我想使用 hashMaps "Items" 列表从值中获取键所以我尝试了这个代码:

  for(int i=0; i<n; i++)
            {  
               String key= null;
               int value=v;
              for(Map.Entry entry: Items.get(i).entrySet()){
                  if(value == (entry.getValue())){
                      key = (String) entry.getKey();
                      break;
                  }
              }

But the Items.get(i).entrySet() doesn't work!

但是 Items.get(i).entrySet() 不起作用!

I get these errors:

我收到这些错误:

-Map.Entry is a raw type. References to generic type Map<K,V>.Entry<K,V> should be parameterized
-Type mismatch: cannot convert from element type Object to Map.Entry
-Incompatible operand types int and Object

Does anyone know how to do it?

有谁知道怎么做?

回答by Eric G

First remake the List variable to include the types of the map. This will make the .entrySet()return the correct formatting of the entry Map<String,Integer>

首先重新创建 List 变量以包含地图的类型。这将使.entrySet()返回的条目格式正确Map<String,Integer>

List<Map<String, Integer>> items = new ArrayList<>();

for (int i = 0; i < items.size(); i++) {
    String key = null;
    int value = 0;
    for (Map.Entry<String, Integer> entry: items.get(i).entrySet()) {
        if (value == (entry.getValue())) {
            key = (String) entry.getKey();
            break;
        }
    }
}

回答by Bahramdun Adil

You can try this

你可以试试这个

First add the generic part <String, Integer>to the Mapof Listas below:

首先将通用部分添加<String, Integer>Mapof 中List,如下所示:

List<Map<String, Integer>> Items= new ArrayList<>();

And then:

接着:

for (Map<String, Integer> item : Items) {
    for (Map.Entry<String, Integer> entry: items.get(i).entrySet()) {
        // do what you want with the entry
    }
}

回答by SkyWalker

You can use it. It will work fine.

你可以使用它。它会正常工作。

import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;

public class MapTest {

    public static void main(String[] args) {
        Map <String, Integer> item1 =new HashMap<String, Integer>();
        Map <String, Integer> item2 =new HashMap<String, Integer>();
        Map <String, Integer> item3 =new HashMap<String, Integer>();
        Map <String, Integer> item4 =new HashMap<String, Integer>();  

        List<Map<String, Integer>> Items= new ArrayList<Map<String, Integer>>();
        Items.add(item1);
        Items.add(item2);
        Items.add(item3);
        Items.add(item4);

        for (int i = 0; i < Items.size(); i++) {
            String key = null;
            int value = 0;
            for (Map.Entry<String, Integer> entry: Items.get(i).entrySet()) {
                if (value == (entry.getValue())) {
                    key = (String) entry.getKey();
                    break;
                }
            }
        }
    }
}