MySQL 从表中选择行,其中具有相同 id 的另一个表中的行在另一列中具有特定值

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时间:2020-08-31 11:58:36  来源:igfitidea点击:

Select rows from a table where row in another table with same id has a particular value in another column

mysqlsqlselectjoin

提问by Jonathon Oates

In MySQL:

在 MySQL 中:

If we have two tables:

如果我们有两个表:

comments
key    |    value
=================
1      |    foo
2      |    bar
3      |    foobar
4      |    barfoo

and:

和:

meta
comment_key    |    value
=========================
1              |    1
2              |    1
3              |    2
4              |    1

I want to get the comments from the commenttable that have a corresponding comment_keyin the metatable that have a specific value(the valuecolumn in the metatable).

我想从comment表格中获取评论,这些评论comment_keymeta表格中具有特定的value(表格中的valuemeta)。

For example, I'd like to select all the rows from the commenttable that have a valueof 1in the metatable:

例如,我想选择所有从该行comment有一个表value1meta表:

I'd expect these results:

我希望这些结果:

key    |    value
=================
1      |    foo
2      |    bar
4      |    barfoo

And if I were to select all the rows from the commenttable that have a valueof 2in the metatable:

而如果我选择所有从该行comment表中有一个value2meta表:

I'd expect this result:

我希望这个结果:

key    |    value
=================
3      |    foobar

I really hope someone can help, thank you all in advance!

我真的希望有人可以提供帮助,提前谢谢大家!

I think I need to do a join? Any pointers would be great, and if at all possible, a short explanation so I can work out where I was going wrong -> so I'll know for next time!

我想我需要加入?任何指针都会很棒,如果可能的话,还有一个简短的解释,这样我就可以找出我哪里出错了 -> 这样我下次就知道了!

回答by ruakh

I actually wouldn't recommend a JOIN for this — or rather, I'd recommend a "semijoin", which is a relational-algebra concept not directly expressed in SQL. A semijoin is essentially a join where you want to retrieve records from only one table, but with the proviso that they have corresponding records in a different table.

我实际上不会为此推荐 JOIN - 或者更确切地说,我会推荐“ semijoin”,这是一个没有直接在 SQL 中表达的关系代数概念。半连接本质上是一种连接,您只想从一个表中检索记录,但条件是它们在不同的表中有相应的记录。

In SQL notation, this concept is expressed indirectly, by using an INclause, with a subquery:

在SQL符号,这个概念间接表达,通过使用一个IN子句,具有子查询

SELECT key, value
  FROM comments
 WHERE key IN
        ( SELECT comment_key
            FROM meta
           WHERE value = 1
        )
;

(MySQL will actually end up translating that back into a semijoin internally — essentially a sort of degenerate inner-join — but the INclause is the natural way to express it in raw SQL.)

(MySQL 实际上最终会在内部将其转换回半连接——本质上是一种退化的内连接——但该IN子句是在原始 SQL 中表达它的自然方式。)

回答by SnowCrash

You're looking for a plain, vanilla equi-join here.

您正在这里寻找一个普通的香草 equi-join。

SELECT `comment`.`key`   AS `key`,
       `comment`.`value` AS `value`
    FROM `comments` 
        JOIN `meta` 
            ON `comments`.`key` = `meta`.`comment_key` 
    WHERE `meta`.`value` = 1;

I'm not really sure what sort of advice you're looking for here but you can read more about the topic (not MySQL specific) at Wikipedia's SQL JOIN page.

我不确定您在这里寻找什么样的建议,但您可以在Wikipedia 的 SQL JOIN 页面上阅读有关该主题的更多信息(不是特定于 MySQL 的)

I'd recommend indexing on comment.keyand meta.comment_keywith both being PRIMARY KEY indexes assuming that you want there to only be 1 metarow per commentrow (PRIMARY KEYs are UNIQUE by definition). If you want to allow more than 1 metaper commentthen add a separate index idcolumn to metaand make that the PRIMARY KEY with comment_keyjust a b-tree index.

我建议在comment. keymetacomment_key两个都是 PRIMARY KEY 索引,假设您希望metacomment行只有 1行(PRIMARY KEY 根据定义是唯一的)。如果您想允许超过 1meta个,comment则添加一个单独的索引id列,meta并使其成为comment_key仅具有 b 树索引的 PRIMARY KEY 。

I'm also not sure how the performance of this will compare to the "semi-join" answer also listed but, to me, this is the simpler and more natural way to express the query; with only two tables, though, it shouldn't be too challenging for MySQL to optimize.

我也不确定它的性能与列出的“半连接”答案相比如何,但对我来说,这是表达查询的更简单、更自然的方式;然而,只有两个表,MySQL 优化应该不会太具有挑战性。

回答by Darius Miliauskas

I would use "INNER JOIN" in the following way:

我会以下列方式使用“INNER JOIN”:

SELECT comments.key, comments.value FROM comments 
INNER JOIN meta ON comments.key=meta.comment_key WHERE meta.value = 1;

Cheers! ;-)

干杯! ;-)