获取 Windows 批处理文件中的最后一个命令行参数
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Get last command line argument in windows batch file
提问by Jarek
I need to get last argument passed to windows batch script, how can I do that?
我需要将最后一个参数传递给 Windows 批处理脚本，我该怎么做？
回答by Random832
This will get the count of arguments:
这将获得参数的计数：
set count=0
for %%a in (%*) do set /a count+=1
To get the actual last argument, you can do
要获得实际的最后一个参数，您可以执行
for %%a in (%*) do set last=%%a
Note that this will fail if the command line has unbalanced quotes - the command line is re-parsed by forrather than directly using the parsing used for %1etc.
请注意，如果命令行具有不平衡的引号，这将失败 - 命令行被重新解析for而不是直接使用用于%1等的解析。
回答by Joey
The easiest and perhaps most reliable way would be to just use cmd's own parsing for arguments and shiftthen until no more are there.
最简单也可能是最可靠的方法是只使用cmd自己的参数解析，shift然后直到不再存在。
Since this destroys the use of %1, etc. you can do it in a subroutine:
由于这会破坏 等的使用%1，因此您可以在子例程中执行此操作：
@echo off
call :lastarg %*
echo Last argument: %LAST_ARG%
goto :eof
:lastarg
set "LAST_ARG=%~1"
shift
if not "%~1"=="" goto lastarg
goto :eof
回答by mohan raj
set first=""
set last=""
for %%a in (%*) do (
SETLOCAL ENABLEDELAYEDEXPANSION
if !first!=="" (set first=!last!) else (set first=!first! !last!)
set last=%%a
)
ENDLOCAL & set "last=%last%" & set "first=%first%"
echo %last% "and" %first%
