Java Android 资源 - 数组数组
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Android Resource - Array of Arrays
提问by JediPotPie
I am trying to implement a resource data structure that includes an array of arrays, specifically strings. The issue I run into is how to get the sub-array objects and their specific values. Here is what my resource file looks like....
我正在尝试实现一个包含数组数组的资源数据结构，特别是字符串。我遇到的问题是如何获取子数组对象及其特定值。这是我的资源文件的样子....
<resources>
<array name="array0">
<item>
<string-array name="array01">
<item name="id">1</item>
<item name="title">item one</item>
</string-array>
</item>
<item>
<string-array name="array02">
<item name="id">2</item>
<item name="title">item two</item>
</string-array>
</item>
<item>
<string-array name="array03">
<item name="id">3</item>
<item name="title">item three</item>
</string-array>
</item>
</array>
</resources>
Then, in my Java code I retrieve the array and try to access the sub elements like so...
然后，在我的 Java 代码中，我检索数组并尝试像这样访问子元素......
TypedArray typedArray = getResources().obtainTypedArray(R.array.array0);
TypedValue typedValue = null;
typedArray.getValue(0, typedValue);
At this point the typedArray object should represent the string-array "array01", however, I don't see how to retrieve the "id" and "title" string elements. Any help would be appreciated, thanks in advance.
此时 typedArray 对象应该表示字符串数组“array01”，但是，我不知道如何检索“id”和“title”字符串元素。任何帮助将不胜感激，提前致谢。
采纳答案by Ted Hopp
You can almost do what you want. You have to declare each array separately and then an array of references. Something like this:
你几乎可以为所欲为。您必须分别声明每个数组，然后是一个引用数组。像这样的东西：
<string-array name="array01">
<item name="id">1</item>
<item name="title">item one</item>
</string-array>
<!-- etc. -->
<array name="array0">
<item>@array/array01</item>
<!-- etc. -->
</array>
Then in your code you do something like this:
然后在你的代码中你做这样的事情：
Resources res = getResources();
TypedArray ta = res.obtainTypedArray(R.array.array0);
int n = ta.length();
String[][] array = new String[n][];
for (int i = 0; i < n; ++i) {
int id = ta.getResourceId(i, 0);
if (id > 0) {
array[i] = res.getStringArray(id);
} else {
// something wrong with the XML
}
}
ta.recycle(); // Important!
回答by Andi Krusch
An Array isn't a name/value pair. You only can access the elements by number. The syntax in the xml is wrong. It should be that way:
数组不是名称/值对。您只能按编号访问元素。xml 中的语法是错误的。应该是这样：
<string-array name="string_array_name">
<item>text_string1</item>
<item>text_string2</item>
</string-array>
回答by Tuan Nguyen
according to @Ted Hopp answer, more elegant way:
根据@Ted Hopp 的回答，更优雅的方式是：
<integer-array name="id_array">
<item>1</item>
<item>2</item>
<item>3</item>
</integer-array>
<string-array name="name_array">
<item>name 1</item>
<item>name 2</item>
<item>name 3</item>
</string-array>
<array name="array0">
<item>@array/id_array</item>
<item>@array/name_array</item>
</array>
make sure sub arrays row count is identical.
enjoy write code to access array cells!
android is still a kid while maintain the ugly "item" tag of the TypedArray "array0".
in my opinion, the most flexible should be:
确保子数组行数相同。
享受编写代码来访问数组单元的乐趣！
android 仍然是一个孩子，同时保持 TypedArray “array0”的丑陋“item”标签。
在我看来，最灵活的应该是：
<array name="array0">
<integer-array name="id_array">
<item>1</item>
<item>2</item>
<item>3</item>
</integer-array>
<string-array name="name_array">
<item>name 1</item>
<item>name 2</item>
<item>name 3</item>
</string-array>
</array>
but don't do that because that's not android way :)
但不要这样做，因为那不是 android 方式:)
回答by Bill
https://developer.android.com/guide/topics/resources/more-resources.html#Color
https://developer.android.com/guide/topics/resources/more-resources.html#Color
<?xml version="1.0" encoding="utf-8"?>
<resources>
<array name="icons">
<item>@drawable/home</item>
<item>@drawable/settings</item>
<item>@drawable/logout</item>
</array>
<array name="colors">
<item>#FFFF0000</item>
<item>#FF00FF00</item>
<item>#FF0000FF</item>
</array>
</resources>
This application code retrieves each array and then obtains the first entry in each array:
此应用程序代码检索每个数组，然后获取每个数组中的第一个条目：
Resources res = getResources();
TypedArray icons = res.obtainTypedArray(R.array.icons);
Drawable drawable = icons.getDrawable(0);
TypedArray colors = res.obtainTypedArray(R.array.colors);
int color = colors.getColor(0,0);
