Javascript 如何将所有参数作为集合传递给另一个函数而不是作为单个参数？
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How to pass all arguments as collection to another function and not as single argument?
提问by Hansjoerg
I have a function that accepts any number and kind of arguments, so no specific parameter has been defined. This function should call another function passing all arguments.
我有一个函数可以接受任意数量和类型的参数，所以没有定义特定的参数。这个函数应该调用另一个传递所有参数的函数。
The problem is that I can pass "arguments" in order to include all arguments but in this case it will work like a single argument and not the way we expect arguments to work.
问题是我可以传递“参数”以包含所有参数，但在这种情况下，它将像单个参数一样工作，而不是我们期望参数工作的方式。
An example:
一个例子：
The main function:
主要功能：
function handleCall() {
// let's call a sub-function
// and pass all arguments (my question is how this is handled the right way)
function callSubFunction( arguments );
}
function callSubfunction( userid, customerid, param) {
// passed arguments are now
alert( 'userid = ' + userid );
// this will not work, you have to use arguments[2]
alert( param );
}
The example call:
handleCall( 1029, 232, 'param01' );
Using the approach above, all arguments will be stored in "userid" as pseudo-array and items can be accessed e.g. arguments[2] but not using the parameter name "param".
使用上述方法，所有参数都将作为伪数组存储在“userid”中，并且可以访问项目，例如参数 [2] 但不使用参数名称“param”。
In ColdFusion, the solution for such stuff is the parameter "argumentCollection", this way you can pass parameters stored in a structure without being converted to a single argument with the type struct containing all key/values.
在 ColdFusion 中，解决此类问题的方法是参数“argumentCollection”，这样您就可以传递存储在结构中的参数，而无需将其转换为包含所有键/值的结构类型的单个参数。
How can I achieve the same with JavaScript?
我怎样才能用 JavaScript 达到同样的效果？
回答by alexmngn
If you want to do the same with the spread syntax, you can use the following:
如果你想对传播语法做同样的事情，你可以使用以下内容：
function handleCall(...args) {
callSubFunction(...args);
}
回答by user113716
You can use the .apply()methodto call a function and pass the arguments as a set.
您可以使用该.apply()方法调用函数并将参数作为集合传递。
callSubFunction.apply( this, arguments );
The first argument will set the value of thisin the allSubFunctionmethod. I just set it to the current thisvalue. The second is the collection of arguments to send.
第一个参数将设置的值this在allSubFunction方法。我只是将其设置为当前this值。第二个是要发送的参数集合。
So your handleCall()function will look like:
所以你的handleCall()函数看起来像：
function handleCall() {
//set the value of "this" and pass on the arguments object
callSubFunction.apply( this, arguments );
}
It isn't required that you send an Argumentsobject. You could send an Arrayof arguments if the circumstance required.
您不需要发送Arguments对象。Array如果情况需要，您可以发送一个参数。
回答by Jimmy Chandra
Use apply like so:
像这样使用 apply：
function Foo()
{
Bar.apply(this, arguments);
}
function Bar(a, b)
{
alert(a);
alert(b);
}
