php json 解码一个txt文件
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php json decode a txt file
提问by fish man
I have the following file:
我有以下文件：
data.txt
数据.txt
{name:yekky}{name:mussie}{name:jessecasicas}
I am quite new at PHP. Do you know how I can use the decode the above JSON using PHP?
我对 PHP 很陌生。您知道我如何使用 PHP 解码上述 JSON 吗？
My PHP code
我的 PHP 代码
var_dump(json_decode('data.txt', true));// var_dump value null
foreach ($data->name as $result) {
echo $result.'<br />';
}
回答by brian_d
json_decodetakes a string as an argument. Read in the file with file_get_contents
json_decode将字符串作为参数。读入文件file_get_contents
$json_data = file_get_contents('data.txt');
json_decode($json_data, true);
You do need to adjust your sample string to be valid JSON by adding quotes around strings, commas between objects and placing the objects inside a containing array (or object).
您确实需要通过在字符串周围添加引号、在对象之间添加逗号并将对象放置在包含数组（或对象）中来将示例字符串调整为有效的 JSON。
[{"name":"yekky"}, {"name":"mussie"}, {"name":"jessecasicas"}]
回答by KingCrunch
As I mentioned in your other questionyou are not producing valid JSON. See my answer there, on how to create it. That will lead to something like
正如我在您的另一个问题中提到的，您没有生成有效的 JSON。请参阅我的答案，了解如何创建它。这将导致类似的事情
[{"name":"yekky"},{"name":"mussie"},{"name":"jessecasicas"}]
(I dont know, where your quotes are gone, but json_encode()usually produce valid json)
（我不知道，你的引号在哪里，但json_encode()通常会产生有效的 json）
And this is easy readable
这很容易阅读
$data = json_decode(file_get_contents('data.txt'), true);
回答by Halcyon
Your JSON data is invalid. You have multiple objects there (and you're missing quotes), you need some way to separate them before you feed the to json_decode.
您的 JSON 数据无效。您在那里有多个对象（并且您缺少引号），您需要某种方法将它们分开，然后再将它们提供给json_decode.
回答by Matthew
$data = json_decode(file_get_contents('data.txt'), true);
But your JSON needs to be formatted correctly:
但是您的 JSON 需要正确格式化：
[ {"name":"yekky"}, ... ]
回答by phihag
That's not a valid JSON file, according to JSONLint. If it were, you'd have to read it first:
根据JSONLint，这不是有效的 JSON 文件。如果是这样，你必须先阅读它：
$jsonBytes = file_get_contents('data.json');
$data = json_decode($jsonBytes, true);
/* Do something with data.
If you set the second argument of json_decode (as above), it's an array,
otherwise an object.
*/
回答by powtac
You have to read the file!
你必须阅读文件！
$json = file_get_contents('data.txt');
var_dump(json_decode($json, true));
