xcode 检查字符串中的字符串
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Check for String within a String
提问by Lauren Quantrell
I'm trying to compare two strings
我正在尝试比较两个字符串
NSString strOne = @"Cat, Dog, Cow";
NSString strTwo = @"Cow";
How do I determine if strOne contains strTwo
如何确定 strOne 是否包含 strTwo
回答by fbrereto
Try using rangeOfString:
尝试使用 rangeOfString:
NSRange result = [strOne rangeOfString:strTwo];
From the documentation:
从文档：
Returns an
NSRangestructure giving the location and length in the receiver of the first occurrence ofaString. Returns{NSNotFound, 0}if aString is not found or is empty (@"").
返回一个
NSRange结构体，给出 的第一次出现在接收器中的位置和长度aString。返回{NSNotFound, 0}如果ASTRING找不到或为空（@""）。
回答by Lauren Quantrell
For anyone needing the code to check is a string exists within a string, here's my code thanks to fbrereto. This example checks to see if any string contained in an array of strings (stringArray) can be found within a string (myString):
对于需要代码来检查字符串中是否存在字符串的任何人，感谢 fbrereto，这是我的代码。此示例检查是否可以在字符串 (myString) 中找到包含在字符串数组 (stringArray) 中的任何字符串：
int count = [stringArray count];
for (NSUInteger x = 0; x < count; ++x) {
NSRange range = [self.myString rangeOfString:[stringArray objectAtIndex:x]];
if (range.length > 0) {
// A match has been found
NSLog(@"string match: %@",[stringArray objectAtIndex:x]);
}
}
回答by Mooner
I believe this is the correct syntax for checking if the range exists (correcting response from Kendall):
range.location != NSNotFound
我相信这是检查范围是否存在的正确语法（更正来自 Kendall 的响应）：
range.location != NSNotFound
回答by redux
Gradually straying off topic, but I always explode my strings, which would mean just exploding it using your search string as a key and you can use the array count to see how many instances you have.
逐渐偏离主题，但我总是分解我的字符串，这意味着只需使用您的搜索字符串作为关键字分解它，您可以使用数组计数来查看您有多少个实例。
Just incase anyone is coming from a code language that uses "explode" to blow a string up into an array like me, I found writing my own explode function tremendously helpful, those not using "explode" are missing out:
以防万一有人来自使用“爆炸”将字符串炸成数组的代码语言，我发现编写自己的爆炸函数非常有帮助，那些不使用“爆炸”的人错过了：
- (NSMutableArray *) explodeString : (NSString *)myString key:(NSString*) myKey
{
NSMutableArray *myArray = [[NSMutableArray alloc] init];
NSRange nextBreak = [myString rangeOfString:myKey];
while(nextBreak.location != NSNotFound)
{
[myArray addObject: [myString substringToIndex:nextBreak.location]];
myString = [myString substringFromIndex:nextBreak.location + nextBreak.length];
nextBreak = [myString rangeOfString:myKey];
}
if(myString.length > 0)
[myArray addObject:myString];
return myArray;
}
works like this:
像这样工作：
[self explodeString: @"John Smith|Age: 37|Account Balance: .00" key:@"|"];
which will return this array:
这将返回这个数组：
[@"John Smith", @"Age: 37", @"Account Balance: .00"];
This lets you quickly pull out a specific value in a tight space, Like if you have a client and you want to know how much money he has:
这使您可以在狭窄的空间中快速提取特定值，例如，如果您有一个客户并且您想知道他有多少钱：
[[self explodeString: clientData key: pipe] objectAtIndex: 1];
or if you wanted specifically the dollar amount as a float:
或者，如果您特别想要将美元金额作为浮动金额：
[[[self explodeString: [[self explodeString: clientData key: pipe] objectAtIndex: 1] key: @": "] objectAtIndex: 2] floatValue];
anyway I find arrays way easier to work with and more flexible, so this is very helpful to me. Additionally with a little effort you could make an "explodable string" data type for your private library that lets you treat it like a string or return an index value based on the key
无论如何，我发现数组更易于使用且更灵活，因此这对我非常有帮助。此外，只需稍加努力，您就可以为您的私有库创建一个“可分解的字符串”数据类型，让您将其视为字符串或基于键返回索引值
ExplodableString *myExplodableString;
myExplodableString.string = @"This is an explodable|string";
NSString *secondValue = [myExplodableString useKey: @"|" toGetValue: index];
