Python 和 JSON - TypeError 列表索引必须是整数而不是 str
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Python and JSON - TypeError list indices must be integers not str
提问by user3718365
I am learning to use Python and APIs (specifically, this World Cup API, http://www.kimonolabs.com/worldcup/explorer)
我正在学习使用 Python 和 API（特别是这个世界杯 API，http://www.kimonolabs.com/worldcup/explorer）
The JSON data looks like this:
JSON 数据如下所示：
[
{
"firstName": "Nicolas Alexis Julio",
"lastName": "N'Koulou N'Doubena",
"nickname": "N. N'Koulou",
"assists": 0,
"clubId": "5AF524A1-830C-4D75-8C54-2D0BA1F9BE33",
"teamId": "DF25ABB8-37EB-4C2A-8B6C-BDA53BF5A74D",
"id": "D9AD1E6D-4253-4B88-BB78-0F43E02AF016",
"type": "Player"
},
{
"firstName": "Alexandre Dimitri",
"lastName": "Song-Billong",
"nickname": "A. Song",
"clubId": "35BCEEAF-37D3-4685-83C4-DDCA504E0653",
"teamId": "DF25ABB8-37EB-4C2A-8B6C-BDA53BF5A74D",
"id": "A84540B7-37B6-416F-8C4D-8EAD55D113D9",
"type": "Player"
},
]
I am simply trying to print all of the firstNames in this API. Here's what I have:
我只是想打印这个 API 中的所有 firstNames。这是我所拥有的：
import urllib2
import json
url = "http://worldcup.kimonolabs.com/api/players?apikey=xxx"
json_obj = urllib2.urlopen(url).read
readable_json = json.dumps(json_obj)
playerstuff = readable_json['firstName']
for i in playerstuff:
print i['firstName']
But when I run it, I get the error "...line 8, in ...TypeError: list indices must be integers, not str"
但是当我运行它时，我收到错误“...第 8 行，...TypeError：列表索引必须是整数，而不是 str”
I have looked around for solutions, but seem to find questions to more "in depth" API questions and I don't really understand it all yet, so any help or explanation as to what I need to do would be amazing. Thank you!
我四处寻找解决方案，但似乎找到了更“深入”的 API 问题的问题，但我还没有真正理解这一切，因此任何有关我需要做的事情的帮助或解释都会很棒。谢谢！
采纳答案by jwodder
First of all, you should be using json.loads, not json.dumps. loadsconverts JSON source text to a Python value, while dumpsgoes the other way.
首先，您应该使用json.loads，而不是json.dumps。 loads将 JSON 源文本转换为 Python 值，dumps反之亦然。
After you fix that, based on the JSON snippet at the top of your question, readable_jsonwill be a list, and so readable_json['firstName']is meaningless. The correct way to get the 'firstName'field of every element of a list is to eliminate the playerstuff = readable_json['firstName']line and change for i in playerstuff:to for i in readable_json:.
在您修复该问题后，根据您问题顶部的 JSON 片段，readable_json将是一个列表，因此readable_json['firstName']毫无意义。获取'firstName'列表中每个元素的字段的正确方法是消除该playerstuff = readable_json['firstName']行并更改for i in playerstuff:为for i in readable_json:.
回答by AlexLordThorsen
You can simplify your code down to
您可以将代码简化为
url = "http://worldcup.kimonolabs.com/api/players?apikey=xxx"
json_obj = urllib2.urlopen(url).read
player_json_list = json.loads(json_obj)
for player in readable_json_list:
print player['firstName']
You were trying to access a list element using dictionary syntax. the equivalent of
您试图使用字典语法访问列表元素。相当于
foo = [1, 2, 3, 4]
foo["1"]
It can be confusing when you have lists of dictionaries and keeping the nesting in order.
当您有字典列表并保持嵌套顺序时，这可能会令人困惑。
回答by Hernan Ramirez
I solved changing
我解决了改变
readable_json['firstName']
by
经过
readable_json[0]['firstName']
