windows 如何获得鼠标光标图标VS C++
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How to get mouse cursor icon VS c++
提问by Nikola
I use this code to get mouse position on screen and it's working. I also get cursor width and height. What I need is cursor icon in the moment I call function GetIconInfo. In ii iI have ii.hbmColor and ii.hbmMask. Value of hbmColor is 0x0, hbmMask is 0x2f0517f1. Can I extract mouse cursor from that two pointer and how?
我使用此代码在屏幕上获取鼠标位置并且它正在工作。我也得到光标的宽度和高度。我需要的是在调用函数 GetIconInfo 时的光标图标。在 ii iI 中有 ii.hbmColor 和 ii.hbmMask。hbmColor 的值为 0x0，hbmMask 的值为 0x2f0517f1。我可以从那两个指针中提取鼠标光标吗？如何提取？
CURSORINFO cursorInfo = { 0 };
cursorInfo.cbSize = sizeof(cursorInfo);
HDC memoryDC = (HDC)malloc(100);
memset(memoryDC, 0x00, 100);
if (::GetCursorInfo(&cursorInfo)) {
ICONINFO ii = {0};
GetIconInfo(cursorInfo.hCursor, &ii);
BITMAP bm;
GetObject(ii.hbmMask,sizeof(BITMAP),&bm);
DeleteObject(ii.hbmColor);
DeleteObject(ii.hbmMask);
::DrawIcon(memoryDC, cursorInfo.ptScreenPos.x - ii.xHotspot, cursorInfo.ptScreenPos.y - ii.yHotspot, cursorInfo.hCursor);
for(int i = 0; i < bm.bmWidth; i++){
for(int j = 0; j < bm.bmHeight; j++){
COLORREF c = GetPixel(memoryDC, i, j);
printf("%x", c);
}
}
}
回答by tenfour
CURSORINFO cursorInfo = { 0 };
cursorInfo.cbSize = sizeof(cursorInfo);
if (::GetCursorInfo(&cursorInfo))
{
ICONINFO ii = {0};
GetIconInfo(cursorInfo.hCursor, &ii);
DeleteObject(ii.hbmColor);
DeleteObject(ii.hbmMask);
::DrawIcon(memoryDC, cursorPos.x - ii.xHotspot, cursorPos.y - ii.yHotspot, cursorInfo.hCursor);
}
回答by Alesk
the cursor informations are formatted like explained here : http://www.daubnet.com/en/file-format-cur
光标信息的格式如下所述：http: //www.daubnet.com/en/file-format-cur
you have to get each pixel from each bit of the data buffer, and not from each byte, so 1 byte = 8 pixels. Also, be careful with some applications wich may have special sized cursors (not multiple of 8), like 26x23 In this case you'll have to ignore the last bits of each line. with a line of 26 pixels, you'll get 4 bytes, you'll read the first 3 bytes to get the 24 first pixels, and then read 2 bits of the 4th byte to get the last 2 pixels, and then ignore the last 6 bits before jumping to the next line.
您必须从数据缓冲区的每一位而不是每个字节中获取每个像素，因此 1 个字节 = 8 个像素。此外，请注意某些可能具有特殊尺寸游标（不是 8 的倍数）的应用程序，例如 26x23 在这种情况下，您必须忽略每行的最后一位。一行 26 个像素，你会得到 4 个字节，你将读取前 3 个字节以获得前 24 个像素，然后读取第 4 个字节的 2 位以获得最后 2 个像素，然后忽略最后一个跳转到下一行之前的 6 位。
