LARAVEL Payload is invalid 错误但解密数据是正确的
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LARAVEL Payload is invalid error but decrypted data is correct
提问by 180doman
Recently i made new project with composer and added very basic authentication with make:auth - nothing fancy.
最近我用作曲家做了一个新项目，并用 make:auth 添加了非常基本的身份验证 - 没什么特别的。
Next i wanted to encrypt nameand emailcolumns on my database so i changed their types from VARCHAR(191) to LONGTEXT and added some very basic mutators to Users model
接下来我想加密我数据库中的name和email列，所以我将它们的类型从 VARCHAR(191) 更改为 LONGTEXT 并向用户模型添加了一些非常基本的修改器
public function setNameAttribute($value) {
$this->attributes['name'] = Crypt::encryptString($value);
}
public function getNameAttribute($value) {
return Crypt::decryptString($value);
}
public function setEmailAttribute($value) {
$this->attributes['email'] = Crypt::encryptString($value);
}
public function getEmailAttribute($value) {
return Crypt::decryptString($value);
}
But when im testing with my very simple route i get Payload is invalid error even though i see in error contents that fields has been decrypted properly.
但是，当我使用我的非常简单的路线进行测试时，即使我在错误内容中看到字段已被正确解密，我也会收到有效载荷无效错误。
Route::get('user',function(){
$user= \App\User::find(3);
//dd($user->name);
dd(Crypt::decryptString($user->name));
dd(Crypt::decryptString($user->email));
});
});
Screenshot link https://ibb.co/deBPpR
回答by Sapnesh Naik
The error is because you are calling Crypt::decryptStringon an already mutated (and decrypted) name property. i.e your getNameAttributedecrypts the encrypted string and when you call
错误是因为您正在调用Crypt::decryptString一个已经发生变异（和解密）的 name 属性。即你getNameAttribute解密加密的字符串，当你打电话
Crypt::decryptString($user->name); // this is causing the error
You basically pass a decrypted string for decryption again.
您基本上可以再次传递解密的字符串进行解密。
Just do:
做就是了：
echo $user->name;
and you will get the decrypted name.
你会得到解密的名字。
If you really want to see the raw value then use:
如果您真的想查看原始值，请使用：
echo $user->getOriginal('name'); //get original value from DB bypassing the accessor
