php SimpleXML - I/O 警告：无法加载外部实体
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SimpleXML - I/O warning : failed to load external entity
提问by Gavin Mannion
I'm trying to create a small application that will simply read an RSS feed and then layout the info on the page.
我正在尝试创建一个小型应用程序，该应用程序将简单地读取 RSS 提要，然后在页面上布置信息。
All the instructions I find make this seem simplistic but for some reason it just isn't working. I have the following
我发现的所有说明都使这看起来很简单，但由于某种原因它不起作用。我有以下
include_once(ABSPATH.WPINC.'/rss.php');
$feed = file_get_contents('http://feeds.bbci.co.uk/sport/0/football/rss.xml?edition=int');
$items = simplexml_load_file($feed);
That's it, it then breaks on the third line with the following error
就是这样，然后它在第三行中断并出现以下错误
Error: [2] simplexml_load_file() [function.simplexml-load-file]: I/O warning : failed to load external entity "<?xml version="1.0" encoding="UTF-8"?> <?xm
The rest of the XML file is shown.
I have turned on allow_url_fopen and allow_url_include in my settings but still nothing. I've tried multiple feeds that all end up with the same result?
我在我的设置中打开了 allow_url_fopen 和 allow_url_include 但仍然没有。我尝试了多个提要，但结果都一样？
I'm going mad here
我要疯了
回答by Amal Murali
simplexml_load_file()interprets an XML file(either a file on your disk or a URL) into an object. What you have in $feedis a string.
simplexml_load_file()将XML 文件（磁盘上的文件或 URL）解释为对象。你所拥有的$feed是一个字符串。
You have two options:
您有两个选择：
Use
file_get_contents()to get the XML feed as a string, and use esimplexml_load_string():$feed = file_get_contents('...'); $items = simplexml_load_string($feed);Load the XML feed directly using
simplexml_load_file():$items = simplexml_load_file('...');
用于
file_get_contents()以字符串形式获取 XML 提要，并使用 esimplexml_load_string()：$feed = file_get_contents('...'); $items = simplexml_load_string($feed);使用
simplexml_load_file()以下命令直接加载 XML 提要：$items = simplexml_load_file('...');
回答by Herlon Aguiar
You can also load the content with cURL, if file_get_contents insn't enabled on your server.
如果您的服务器上未启用 file_get_contents，您还可以使用 cURL 加载内容。
Example:
例子：
$ch = curl_init();
curl_setopt($ch,CURLOPT_URL,"http://feeds.bbci.co.uk/sport/0/football/rss.xml?edition=int");
curl_setopt($ch,CURLOPT_RETURNTRANSFER,true);
$output = curl_exec($ch);
curl_close($ch);
$items = simplexml_load_string($output);
回答by Herlon Aguiar
this also works:
这也有效：
$url = "http://www.some-url";
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
$xmlresponse = curl_exec($ch);
$xml=simplexml_load_string($xmlresponse);
then I just run a forloop to grab the stuff from the nodes.
然后我只是运行一个 forloop 来从节点中获取东西。
like this:`
像这样：`
for($i = 0; $i < 20; $i++) {
$title = $xml->channel->item[$i]->title;
$link = $xml->channel->item[$i]->link;
$desc = $xml->channel->item[$i]->description;
$html .="<div><h3>$title</h3>$link<br />$desc</div><hr>";
}
echo $html;
***note that your node names will differ, obviously..and your HTML might be structured differently...also your loop might be set to higher or lower amount of results.
***请注意，您的节点名称显然会有所不同……并且您的 HTML 可能具有不同的结构……您的循环也可能设置为更高或更低的结果数量。
回答by Júnior Mendon?a
$url = 'http://legis.senado.leg.br/dadosabertos/materia/tramitando';
$xml = file_get_contents("xml->{$url}");
$xml = simplexml_load_file($url);
