Java 将双精度存储在数组中
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Storing doubles in an array
提问by Code123
Alright, so I want to store values in an array. Here is my code :
好的，所以我想将值存储在数组中。这是我的代码：
import java.util.Scanner;
public class test {
public static void main(String args[]){
Scanner bob = new Scanner(System.in);
double[] mylist;
System.out.println("What is your first value?");
mylist = bob.nextDouble();
System.out.println("What is your second value?");
mylist = bob.nextDouble();
}
}
Issue #1: I'm being told mylist = bob.nextDouble()should be nextLine(). Why is that if it is clearly a double?
问题 #1：我被告知mylist = bob.nextDouble()应该是nextLine(). 如果它显然是双重的，为什么会这样？
Goal: I want to somehow store those values given into an array so that I could later pull them out. Can anyone help?
目标：我想以某种方式将这些给定的值存储到一个数组中，以便我以后可以将它们取出。任何人都可以帮忙吗？
UPDATE
更新
For Issue #1, it tells me that it cannot convert from Double()to Double[]. What does this mean?
对于问题 #1，它告诉我它不能从 转换Double()为Double[]. 这是什么意思？
采纳答案by Tot Zam
mylistis an arrayof doubles, not a single double.
mylist是array双打，不是单打double。
When you do mylist = bob.nextDouble();you are basically trying to make an entire array equal a single number.
当您这样做时，mylist = bob.nextDouble();您基本上是在尝试使整个数组等于一个数字。
You instead need to assign the number to a specific place in the array.
您需要将数字分配到数组中的特定位置。
Initialize the array with the amount of elements you are going to store in the array:
double[] mylist = new double[2];Assign the double to a specific place in the array:
mylist[0] = bob.nextDouble(); mylist[1] = bob.nextDouble();
使用要存储在数组中的元素数量初始化数组：
double[] mylist = new double[2];将 double 分配给数组中的特定位置：
mylist[0] = bob.nextDouble(); mylist[1] = bob.nextDouble();
回答by Elliott Frisch
It's an array (which is a type of object). First, create an array large enough to store your double(s) (not int(s)). And store the values at appropriate indices. Something like,
它是一个数组（它是一种对象）。首先，创建一个足够大的数组来存储您的double（s）（不是int（s））。并将值存储在适当的索引处。就像是，
Scanner bob = new Scanner(System.in);
double[] mylist = new double[2];
System.out.println("What is your first value?");
mylist[0] = bob.nextDouble();
System.out.println("What is your second value?");
mylist[1] = bob.nextDouble();
System.out.println(Arrays.toString(mylist));
回答by Dici
An array is not a double, you need to select an index :
数组不是双精度数，您需要选择一个索引：
double[] arr = new double[2];
System.out.println("What is your first value?");
arr[0] = bob.nextDouble();
System.out.println("What is your second value?");
arr[1] = bob.nextDouble();
Also, don't call an array a list, use CamelCase for naming your variables/methods/classes, and initialize the array. I recommend you reading a Java tutorial for working on the basics of the language.
另外，不要将数组称为列表，使用 CamelCase 命名变量/方法/类，并初始化数组。我建议您阅读 Java 教程以了解该语言的基础知识。
回答by Juned Ahsan
The error is because you are trying to assign a double value to array in the following statement:
错误是因为您试图在以下语句中为数组分配双精度值：
mylist = bob.nextDouble();
as mylist is defined as an array here:
因为 mylist 在这里被定义为一个数组：
double[] mylist;
First you need to intialize your array:
首先你需要初始化你的数组：
double[] mylist = new double[2]; // initialise array to have two elements
and then try to assign the array elements with the user input like this:
然后尝试使用用户输入分配数组元素，如下所示：
mylist[0] = bob.nextDouble();
mylist[1] = bob.nextDouble();
回答by Samrat Dutta
Better still, use a list with generics.
更好的是，使用带有泛型的列表。
List<Double> myList;
myList.add(bob.nextDouble());
That way, you can add as many doubles you want to the list. So that you dont have to worry about the indexing.
这样，您可以在列表中添加任意数量的双打。这样您就不必担心索引。
