Java 从键盘读取数据以存储在字符串数组中
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原文地址: http://stackoverflow.com/questions/22346306/
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Reading data from keyboard to store in string array
提问by CHAITHANYA PADALA
String s[];
System.out.println("Enter loop value");
int t = s.nextInt();
for(int i=0;i<t;i++)
{
str[i]=s.nextLine();
}
while it reading it gives null pointer exception
当它读取它时会给出空指针异常
采纳答案by Sanjeev
What you need is something like this:
你需要的是这样的：
Scanner s = new Scanner(System.in);
System.out.println("Enter loop value");
int t = s.nextInt(); // read number of element
s.nextLine(); // consume new line
String str[] = new String[t];
for(int i=0;i<t;i++)
{
str[i]=s.nextLine();
}
System.out.println(Arrays.toString(str));
Hope this helps.
希望这可以帮助。
回答by rzysia
Try something like this:
尝试这样的事情：
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
System.out.println("Enter loop value");
String a[] = new String[Integer.parseInt(br.readLine())];
for (int i = 0; i < a.length; i++) {
a[i] = br.readLine();
}
回答by slartidan
I changed the typos and missing declarations in your code:
我更改了代码中的拼写错误和缺失的声明：
package snippet;
import java.io.IOException;
import java.util.Arrays;
import java.util.Scanner;
public class Snippet {
public static void main(String[] args) throws IOException {
Scanner s = new Scanner(System.in);
String str[] = new String[10];
System.out.println("Enter loop value (maximum 9)");
int t = s.nextInt();
for (int i = 0; i <= t; i++) {
str[i] = s.nextLine();
}
System.out.println("your entered lines:");
System.out.println(Arrays.toString(str));
}
}
However, I would recommend to store the values in a Listinstead of an Array. I also prefer using a BufferedReaderto using a Scanner.
但是，我建议将值存储在 aList而不是Array. 我也更喜欢使用 a 而不是BufferedReader使用Scanner.
回答by CHAITHANYA PADALA
//After modifying my code works well
import java.io.*;
import java.util.Scanner;
class Sample
{
public static void main(String[] args) throws Exception
{
bufferedReader();
scanner();
}
static void bufferedReader()throws Exception{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
System.out.println("Enter Number of Strings");
int len = Integer.parseInt(br.readLine());
String a[] = new String[len];
for(int i=0; i<len; i++){
System.out.println("Enter String"+ (i+1));
a[i] = br.readLine();
}
for(String str : a)
System.out.println(str);
}
static void scanner(){
Scanner s = new Scanner(System.in);
System.out.println("Enter Number of Strings");
int len = Integer.parseInt(s.nextLine());
String a[] = new String[len];
for(int i=0; i<len; i++){
System.out.println("Enter String"+ (i+1));
a[i] = s.nextLine();
}
for(String str : a)
System.out.println(str);
}
}
But when using Scanner nextLine() skips the data when read if any one knows please post description with example
但是当使用 Scanner 时 nextLine() 在读取时跳过数据，如果有人知道请用示例发布说明
