Java 参数 [变量] 的非法修饰符；只允许final
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Illegal modifier for parameter [variable]; only final is permitted
提问by iShaalan
I am trying to write a method that gets a string of numbers "123188"
我正在尝试编写一个获取一串数字“123188”的方法
then returns an int[]which contains digits.
然后返回int[]包含数字的 。
that what I've got so far :
到目前为止我所拥有的：
public int[] stringToDig(String a)
{
char [] ch1 = a.toCharArray();
int [] conv = new int [ch1.length];
for (int i=0 ; i<ch1.length ; i++)
conv[i] = Character.getNumericValue(ch1[i]);
return conv;
}
and I got that
我明白了
Multiple markers at this line:
- Syntax error on token "(", ; expected
- Syntax error on token ")", ; expected
- Illegal modifier for parameter stringToDig; only final is permitted
此行的多个标记：
- 标记 "(", ; 预期的语法错误
- 标记“)”上的语法错误, ; 预期的
- 参数 stringToDig 的非法修饰符；只允许final
采纳答案by Cruncher
You can't put methods inside of other methods in Java.
您不能将方法放在 Java 中的其他方法中。
Structure your program like this:
像这样构建你的程序：
public class Test
{
public static void main(String[] args)
{
int[] digits = stringToDig("54235");
}
public int[] stringToDig(String a)
{
char [] ch1 = a.toCharArray();
int [] conv = new int [ch1.length];
for (int i=0 ; i<ch1.length ; i++)
conv[i] = Character.getNumericValue(ch1[i]);
return conv;
}
}
回答by óscar López
Try this:
尝试这个：
public int[] stringToDig(String a) {
char[] ch1 = a.toCharArray();
int[] conv = new int[ch1.length];
for (int i = 0; i < ch1.length; i++)
conv[i] = Character.digit(ch1[i], 10); // here's the difference
return conv;
}
The preferred method for converting a character digit to the corresponding intvalue is by using the digit()method. Here's another option, although it's a bit of a hack and will only work for digits in base 10 (unlike using digits(), which works for other bases):
将字符数字转换为相应int值的首选方法是使用该digit()方法。这是另一种选择，虽然它有点小技巧，并且只适用于以 10 为基数的数字（与 using 不同digits()，它适用于其他基数）：
conv[i] = ch1[i] - '0';
Besides that, @Cruncher is right - the errors shown seem to indicate that you forgot to put the method insidea class! follow his advice.
除此之外，@Cruncher 是对的 - 显示的错误似乎表明您忘记将该方法放入类中！听从他的建议。
回答by kelunik
This code works for me:
这段代码对我有用：
public int[] stringToDig(String a) {
char[] chars = a.toCharArray();
int[] ints = new int[chars.length];
for (int i = 0; i < chars.length; i++)
ints[i] = chars[i] - 48;
return ints;
}
回答by SAnDAnGE
import java.util.Arrays;
public class NewClass {
public static void main(String[] args) { System.out.println(Arrays.toString(stringToDig("123456789"))); } public static int[] stringToDig(String a) { int [] c = new int[a.length()]; for (int i = 0; i < c.length; i++) { c[i] = Integer.parseInt(String.valueOf(a.charAt(i))); } return c; }}
导入 java.util.Arrays;
公共类新类{
public static void main(String[] args) { System.out.println(Arrays.toString(stringToDig("123456789"))); } public static int[] stringToDig(String a) { int [] c = new int[a.length()]; for (int i = 0; i < c.length; i++) { c[i] = Integer.parseInt(String.valueOf(a.charAt(i))); } return c; }}
