typescript 打字稿：要求语句不是导入语句的一部分
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Typescript : require statement not part of an import statement
提问by Paleo
Typescript version 2.2.2
打字稿版本 2.2.2
I wrote this require in my UserRoutzr.ts
我在 UserRoutzr.ts 中写了这个要求
const users = <IUser[]> require(path.join(process.cwd() + "/data"));
TSLint is raising the following warning:
TSLint 发出以下警告：
require statement not part of an import statement
if I changed it to :
如果我将其更改为：
import users = <IUser[]> require(path.join(process.cwd() + "/data"));
Then it's raising an error :
然后它引发了一个错误：
TS1003 Identifier expected
How should I rewrite this require ? thanks for feedback
我应该如何重写这个 require ？感谢反馈
回答by Paleo
TypeScript modules are an implementation of ES6 modules. ES6 modules are static. Your issue comes from the dynamic path: path.join(process.cwd() + "/data"). The compiler can't determine which module it is at compile time, and the linter doesn't like the causes that lead to any.
TypeScript 模块是 ES6 模块的实现。ES6 模块是静态的。您的问题来自动态路径：path.join(process.cwd() + "/data"). 编译器在编译时无法确定它是哪个模块，并且 linter 不喜欢导致any.
You should use a static path to the module. At compile time, TypeScript resolves it. And it affects the right exported type (IUser[]) to users.
您应该使用模块的静态路径。在编译时，TypeScript 会解决它。并且它会影响正确的导出类型 ( IUser[]) 到users.
import users = require("./yourModuleThatExportsUsers");
Notice: If your module datacontains just data, you could consider to change it to a JSON file, which could be loaded (Node.js) or bundled (Webpack).
注意：如果您的模块data只包含数据，您可以考虑将其更改为 JSON 文件，该文件可以加载 (Node.js) 或捆绑 (Webpack)。
UPDATE (from May 2019) — It is also possible to use dynamic import, with which TypeScript accepts static and dynamic paths:
更新（从 2019 年 5 月开始）——也可以使用动态导入，TypeScript 接受静态和动态路径：
const users = await import("./yourModuleThatExportsUsers");
See also: TypeScript 2.4 Release Notes
另请参阅：TypeScript 2.4 发行说明
回答by holi-java
may be you need dynamic module loading, and the code like this:
可能你需要动态模块加载，代码如下：
import {IUser} from './lib/user';
const users:IUser[] = require(path.join(process.cwd() + "/data"));
