"git checkout --" 。vs git 结帐
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"git checkout --" . vs git checkout
提问by Laoujin
I always used git checkout -- .to clear my working directory. I thought I read somewhere that the --was required to avoid git thinking you are passing parameters (or something)
我总是用来git checkout -- .清除我的工作目录。我以为我在某处读到--需要避免 git 认为您正在传递参数（或其他东西）
Now a colleague told me I could drop the --, and indeed, a quick test did exactly the same.
现在一位同事告诉我，我可以放弃--，而且确实，快速测试完全相同。
Is there are any difference between those two commands?
这两个命令有什么区别吗？
PS: Asking here because git checkout -- .vs git checkout .is kind of hard to google...
PS：在这里问是因为git checkout -- .vsgit checkout .很难用谷歌搜索......
回答by Tim Biegeleisen
I seem to recall that the --is a way to tell Git to treat what follows checkoutas a file and not as a branch. Suppose that you had both a file and a branch called stuff. Then the following command would seem ambiguous:
我似乎记得这--是一种告诉 Git 将后面的内容checkout视为文件而不是分支的方法。假设您有一个文件和一个名为stuff. 那么下面的命令似乎不明确：
git checkout stuff
because it is not clear whether you are asking to checkout a file or a branch. By using --you explicitly tell Git to checkout a file by that name/path. So in this case the following commands allow checking out a branch and a file called stuff:
因为不清楚您是要求签出文件还是分支。通过使用，--您明确告诉 Git 按该名称/路径检出文件。因此，在这种情况下，以下命令允许检出一个分支和一个名为 的文件stuff：
git checkout stuff # checkout the branch stuff
git checkout -- stuff # checkout the file stuff
Note that git checkout <name>is really meant for branches, but Git syntax is relaxed, and if Git can't find a branch, then it will look for a file.
请注意，这git checkout <name>实际上是针对分支的，但是 Git 语法很宽松，如果 Git 找不到分支，那么它会查找文件。
Closely related: Git change branch when file of same name is present
密切相关：当存在同名文件时，Git 更改分支
回答by Powerlord
--as a standalone argument (i.e. not part of another argument) is used by many UNIX command line programs to indicate that anything that follows it is not an argument.
--作为一个独立的参数（即不是另一个参数的一部分），许多 UNIX 命令行程序使用它来表示它后面的任何内容都不是参数。
Why? Well, in this case, it's being used in case you have a path whose name starts with --, which shouldn't be interpreted as its own argument.
为什么？好吧，在这种情况下，如果您有一个名称以 开头的路径--，它不应该被解释为它自己的参数。
i.e. git checkout -- --mydirectorywhich, without the --would throw an error.
即git checkout -- --mydirectory，没有--将抛出错误。
