scala SparkSQL 时间戳查询失败

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时间:2020-10-22 06:44:08  来源:igfitidea点击:

SparkSQL Timestamp query failure

scalatimestampapache-sparkapache-spark-sql

提问by bobo32

I put some log files into sql tables through Spark and my schema looks like this:

我通过 Spark 将一些日志文件放入 sql 表中,我的架构如下所示:

|-- timestamp: timestamp (nullable = true) 
|-- c_ip: string (nullable = true) 
|-- cs_username: string (nullable = true) 
|-- s_ip: string (nullable = true) 
|-- s_port: string (nullable = true) 
|-- cs_method: string (nullable = true) 
|-- cs_uri_stem: string (nullable = true) 
|-- cs_query: string (nullable = true) 
|-- sc_status: integer (nullable = false) 
|-- sc_bytes: integer (nullable = false) 
|-- cs_bytes: integer (nullable = false) 
|-- time_taken: integer (nullable = false) 
|-- User_Agent: string (nullable = true) 
|-- Referrer: string (nullable = true) 

As you can notice I created a timestamp field which I read is supported by Spark (Date wouldn't work as far as I understood). I would love to use for queries like "where timestamp>(2012-10-08 16:10:36.0)" but when I run it I keep getting errors. I tried these 2 following sintax forms: For the second one I parse a string so Im sure Im actually pass it in a timestamp format. I use 2 functions: parseand date2timestamp.

正如您所注意到的,我创建了一个时间戳字段,我读取了它由 Spark 支持(据我所知,日期不起作用)。我很想使用诸如“where timestamp>(2012-10-08 16:10:36.0)”之类的查询,但是当我运行它时,我不断收到错误消息。我尝试了以下两种语法形式:对于第二个,我解析一个字符串,所以我确定我实际上以时间戳格式传递它。我使用 2 个函数:parsedate2timestamp

Any hint on how I should handle timestamp values?

关于我应该如何处理时间戳值的任何提示?

Thanks!

谢谢!

1) scala> sqlContext.sql("SELECT * FROM Logs as l where l.timestamp=(2012-10-08 16:10:36.0)").collect

1) scala> sqlContext.sql("SELECT * FROM Logs as l where l.timestamp=(2012-10-08 16:10:36.0)").collect

java.lang.RuntimeException: [1.55] failure: ``)'' expected but 16 found 

SELECT * FROM Logs as l where l.timestamp=(2012-10-08 16:10:36.0) 
                                                  ^ 

2) sqlContext.sql("SELECT * FROM Logs as l where l.timestamp="+date2timestamp(formatTime3.parse("2012-10-08 16:10:36.0"))).collect

2) sqlContext.sql("SELECT * FROM Logs as l where l.timestamp="+date2timestamp(formatTime3.parse("2012-10-08 16:10:36.0"))).collect

java.lang.RuntimeException: [1.54] failure: ``UNION'' expected but 16 found 

SELECT * FROM Logs as l where l.timestamp=2012-10-08 16:10:36.0 
                                                 ^ 

回答by bobo32

I figured that the problem was the precision of the timestamp first of all and also the string that I pass representing the timestamp has to be casted as a String

我认为问题首先是时间戳的精度,而且我传递的代表时间戳的字符串必须被转换为字符串

So this query works now:

所以这个查询现在有效:

sqlContext.sql("SELECT * FROM Logs as l where cast(l.timestampLog as String) <= '2012-10-08 16:10:36'")

回答by Guillaume

You forgot the quotation marks.

你忘了引号。

Try something with this syntax:

尝试使用以下语法:

L.timestamp = '2012-07-16 00:00:00'

Alternatively, try

或者,尝试

L.timestamp = CAST('2012-07-16 00:00:00' AS TIMESTAMP)

回答by Azeroth2b

Cast the string representation of the timestamp to timestamp. cast('2012-10-10 12:00:00' as timestamp) Then you can do comparison as timestamps, not strings. Instead of:

将时间戳的字符串表示形式转换为时间戳。cast('2012-10-10 12:00:00' as timestamp) 然后您可以将比较作为时间戳,而不是字符串。代替:

sqlContext.sql("SELECT * FROM Logs as l where cast(l.timestampLog as String) <= '2012-10-08 16:10:36'")

try

尝试

sqlContext.sql("SELECT * FROM Logs as l where l.timestampLog <= cast('2012-10-08 16:10:36' as timestamp)")

回答by Ivan Stoyanov

Sadly this didn't work for me. I am using Apache Spark 1.4.1. The following code is my solution:

可悲的是,这对我不起作用。我正在使用 Apache Spark 1.4.1。以下代码是我的解决方案:

Date date = new Date();

String query = "SELECT * FROM Logs as l where l.timestampLog <= CAST('" + new java.sql.Timestamp(date.getTime()) + "' as TIMESTAMP)";

sqlContext.sql(query);

Casting the timestampLog as string did not throw any errors but returned no data.

将 timestampLog 转换为字符串不会引发任何错误,但没有返回任何数据。