在 bash 中尝试整数相等时“找不到命令”
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"Command not found" when attempting integer equality in bash
提问by Margaret
Ok, this is probably going to be ultra obvious to anyone that has spent more time with bash than I have.
好的，对于那些在 bash 上花费的时间比我多的人来说，这可能是非常明显的。
I'm trying to run this code:
我正在尝试运行此代码：
#!/bin/bash
if ["1" -eq "2"]
then
echo "True"
else
echo "False"
fi
but when I execute the file, it sends back
但是当我执行文件时，它会发回
./test.sh: line 3: 1: command not found
False
There must be something major I'm missing. I've seen people use a semicolon after the brackets, this doesn't seem to make any difference... :S
一定有什么重要的东西我错过了。我见过人们在括号后使用分号，这似乎没有任何区别......：S
采纳答案by RageZ
yep eq is used only for arithmetic comparaisons.
是的 eq 仅用于算术比较。
for string comparison you have to use =
对于字符串比较，您必须使用 =
#!/bin/bash
if [ "1" = "2" ]
then
echo "True"
else
echo "False"
fi
plus you need some space around the brackets.
此外，您需要在括号周围留出一些空间。
回答by SiegeX
You need to add a space after the [and before the ]like so:
您需要在之后[和之前添加一个空格，]例如：
if [ "1" -eq "2" ]
However, that way is deprecated and the better method to use is:
但是，这种方式已被弃用，更好的使用方法是：
#!/bin/bash
if ((1 == 2))
then
echo "True"
else
echo "False"
fi
回答by Michael Burr
Try adding spaces around your brackets:
尝试在括号周围添加空格：
if [ "1" -eq "2" ]
