Javascript 具有特殊字符的Javascript正则表达式密码验证
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Javascript regular expression password validation having special characters
提问by Srikanth Sridhar
I am trying to validate the password using regular expression. The password is getting updated if we have all the characters as alphabets. Where am i going wrong ? is the regular expression right ?
我正在尝试使用正则表达式验证密码。如果我们将所有字符都作为字母，密码就会更新。我哪里错了？正则表达式对吗？
function validatePassword() {
var newPassword = document.getElementById('changePasswordForm').newPassword.value;
var minNumberofChars = 6;
var maxNumberofChars = 16;
var regularExpression = /^[a-zA-Z0-9!@#$%^&*]{6,16}$/;
alert(newPassword);
if(newPassword.length < minNumberofChars || newPassword.length > maxNumberofChars){
return false;
}
if(!regularExpression.test(newPassword)) {
alert("password should contain atleast one number and one special character");
return false;
}
}
回答by Jo?o Silva
Use positive lookaheadassertions:
使用积极的前瞻断言：
var regularExpression = /^(?=.*[0-9])(?=.*[!@#$%^&*])[a-zA-Z0-9!@#$%^&*]{6,16}$/;
Without it, your current regex only matches that you have 6 to 16 valid characters, it doesn'tvalidate that it has at leasta number, and at leasta special character. That's what the lookahead above is for.
没有它，您当前的正则表达式只匹配您有 6 到 16 个有效字符，它不会验证它至少有一个数字，至少有一个特殊字符。这就是上面的前瞻。
(?=.*[0-9])- Assert a string has at least one number;(?=.*[!@#$%^&*])- Assert a string has at least one special character.
(?=.*[0-9])- 断言一个字符串至少有一个数字；(?=.*[!@#$%^&*])- 断言一个字符串至少有一个特殊字符。
回答by atul-tagra
function validatePassword() {
var p = document.getElementById('newPassword').value,
errors = [];
if (p.length < 8) {
errors.push("Your password must be at least 8 characters");
}
if (p.search(/[a-z]/i) < 0) {
errors.push("Your password must contain at least one letter.");
}
if (p.search(/[0-9]/) < 0) {
errors.push("Your password must contain at least one digit.");
}
if (errors.length > 0) {
alert(errors.join("\n"));
return false;
}
return true;
}
There is a certain issue in below answer as it is not checking whole string due to absence of [ ] while checking the characters and numerals, this is correct version
以下答案存在某个问题，因为在检查字符和数字时由于缺少 [ ] 而没有检查整个字符串，这是正确的版本
回答by Ujjaval
you can make your own regular expression for javascript validation
您可以为javascript验证制作自己的正则表达式
/^ : Start
(?=.{8,}) : Length
(?=.*[a-zA-Z]) : Letters
(?=.*\d) : Digits
(?=.*[!#$%&? "]) : Special characters
$/ : End
(/^
(?=.*\d) //should contain at least one digit
(?=.*[a-z]) //should contain at least one lower case
(?=.*[A-Z]) //should contain at least one upper case
[a-zA-Z0-9]{8,} //should contain at least 8 from the mentioned characters
$/)
Example:- /^(?=.*\d)(?=.*[a-zA-Z])[a-zA-Z0-9]{7,}$/
回答by Rujoota Shah
I use the following script for min 8 letter password, with at least a symbol, upper and lower case letters and a number
我使用以下脚本输入最少 8 个字母的密码，至少包含一个符号、大小写字母和一个数字
function checkPassword(str)
{
var re = /^(?=.*\d)(?=.*[!@#$%^&*])(?=.*[a-z])(?=.*[A-Z]).{8,}$/;
return re.test(str);
}
回答by ChaosPandion
Don't try and do too much in one step. Keep each rule separate.
不要试图一步做太多。将每个规则分开。
function validatePassword() {
var p = document.getElementById('newPassword').value,
errors = [];
if (p.length < 8) {
errors.push("Your password must be at least 8 characters");
}
if (p.search(/[a-z]/i) < 0) {
errors.push("Your password must contain at least one letter.");
}
if (p.search(/[0-9]/) < 0) {
errors.push("Your password must contain at least one digit.");
}
if (errors.length > 0) {
alert(errors.join("\n"));
return false;
}
return true;
}
回答by Valentino Pereira
Regex for password:
密码正则表达式：
/^(?=.*\d)(?=.*[A-Z])(?=.*[a-z])(?=.*[a-zA-Z!#$%&? "])[a-zA-Z0-9!#$%&?]{8,20}$/
/^(?=.*\d)(?=.*[A-Z])(?=.*[a-z])(?=.*[a-zA-Z!#$%&? "])[a-zA-Z0-9!#$%&?]{8,20}$/
Took me a while to figure out the restrictions, but I did it!
我花了一段时间才弄清楚这些限制，但我做到了！
Restrictions: (Note: I have used >>and <<to show the important characters)
限制：（注意：我使用了>>和<<来显示重要的字符）
- Minimum 8 characters
{>>8,20} - Maximum 20 characters
{8,>>20} - At least one uppercase character
(?=.*[A-Z]) - At least one lowercase character
(?=.*[a-z]) - At least one digit
(?=.*\d) - At least one special character
(?=.*[a-zA-Z >>!#$%&? "<<])[a-zA-Z0-9 >>!#$%&?<< ]
- 最少 8 个字符
{>>8,20} - 最多 20 个字符
{8,>>20} - 至少一个大写字符
(?=.*[A-Z]) - 至少一个小写字符
(?=.*[a-z]) - 至少一位
(?=.*\d) - 至少一个特殊字符
(?=.*[a-zA-Z >>!#$%&? "<<])[a-zA-Z0-9 >>!#$%&?<< ]
回答by Mustafa Gen?
If you check the length seperately, you can do the following:
如果单独检查长度，您可以执行以下操作：
var regularExpression = /^[a-zA-Z]$/;
if (regularExpression.test(newPassword)) {
alert("password should contain atleast one number and one special character");
return false;
}
