Java 如何将 url 中的特殊字符作为参数值处理？
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How to handle special characters in url as parameter values?
提问by Puneet Purohit
Can anyone suggest how to handle below url as values of parameter of strLocation is haveing special charecters ? Thanks in advance
任何人都可以建议如何处理以下 url，因为 strLocation 的参数值具有特殊字符？提前致谢
http://localhost:8080/safp/contacts/FirmAddress.do?btnAction=FirmAddress&firmId=122379069&strLocation=!@#$%^&*()_+&async=true&newAccID=112
采纳答案by Juned Ahsan
Use URLEncoderto encode your URL string with special characters.When encoding a String, the following rules apply:
使用URLEncoder使用特殊字符对 URL 字符串进行编码。对字符串进行编码时，以下规则适用：
- The alphanumeric characters "a" through "z", "A" through "Z" and "0" through "9" remain the same.
- The special characters ".", "-", "*", and "_" remain the same.
- The space character " " is converted into a plus sign "+".
- All other characters are unsafe and are first converted into one or more bytes using some encoding scheme. Then each byte is represented
by the 3-character string "%xy", where xy is the two-digit
hexadecimal representation of the byte. The recommended encoding
scheme to use is UTF-8. However, for compatibility reasons, if an
encoding is not specified, then the default encoding of the platform
is used.
- 字母数字字符“a”到“z”、“A”到“Z”和“0”到“9”保持不变。
- 特殊字符“.”、“-”、“*”和“_”保持不变。
- 空格字符“”被转换为加号“+”。
- 所有其他字符都是不安全的，首先使用某种编码方案将其转换为一个或多个字节。然后每个字节
由 3 个字符的字符串“%xy”表示，其中 xy 是
字节的两位十六进制表示。推荐使用的编码
方案是 UTF-8。但是，出于兼容性原因，如果
未指定编码，
则使用平台的默认编码。
For example using UTF-8 as the encoding scheme the string The string ü@foo-barwould get converted to The+string+%C3%BC%40foo-barbecause in UTF-8 the character ü is encoded as two bytes C3 (hex) and BC (hex), and the character @ is encoded as one byte 40 (hex).
例如，使用 UTF-8 作为字符串The string ü@foo-bar将被转换为的编码方案，The+string+%C3%BC%40foo-bar因为在 UTF-8 中，字符 ü 被编码为两个字节 C3（十六进制）和 BC（十六进制），而字符 @ 被编码为一个字节 40（十六进制）。
回答by Tarsem Singh
Use URLEncoder.encode()
使用URLEncoder.encode()
String url="http://localhost:8080/safp/contacts/FirmAddress.do?btnAction=FirmAddress&firmId="+URLEncoder.encode("122379069","UTF-8")+"&strLocation="+URLEncoder.encode("!@#$%^&*()_+","UTF-8")+"&async=true&newAccID=112";
Note: Don't encodethe whole url because it will also encode the //from http://
注意：不要encode使用整个 url，因为它也会对//from进行编码http://
