Javascript 限制特殊字符的正则表达式
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Regular Expression to restrict special characters
提问by hemc4
i have an address field in my form and i want to restrict * | \ " : < > [ ] { } \ ( ) '' ; @ & $
i have tried with
我的表单中有一个地址字段，我想限制* | \ " : < > [ ] { } \ ( ) '' ; @ & $
我尝试过的
var nospecial=/^[^* | \ " : < > [ ] { } ` \ ( ) '' ; @ & $]+$/;
if(address.match(nospecial)){
alert('Special characters like * | \ " : < > [ ] { } ` \ ( ) \'\' ; @ & $ are not allowed');
return false;
but it is not working. Please tell me what i missed?
但它不起作用。请告诉我我错过了什么？
回答by Ted Hopp
You need to escape the closing bracket (as well as the backslash) inside your character class. You also don't need all the spaces:
您需要转义字符类中的结束括号（以及反斜杠）。您也不需要所有空格：
var nospecial=/^[^*|\":<>[\]{}`\()';@&$]+$/;
I got rid of all your spaces; if you want to restrict the space character as well, add one space back in.
我摆脱了你所有的空间；如果您还想限制空格字符，请重新添加一个空格。
EDITAs @fab points out in a comment, it would be more efficient to reverse the sense of the regex:
编辑正如@fab 在评论中指出的那样，反转正则表达式的意义会更有效：
var specials=/[*|\":<>[\]{}`\()';@&$]/;
and test for the presence of a special character (rather than the absence of one):
并测试是否存在特殊字符（而不是不存在）：
if (specials.test(address)) { /* bad address */ }
回答by Munavar
Use the below function
使用以下功能
function checkSpcialChar(event){
if(!((event.keyCode >= 65) && (event.keyCode <= 90) || (event.keyCode >= 97) && (event.keyCode <= 122) || (event.keyCode >= 48) && (event.keyCode <= 57))){
event.returnValue = false;
return;
}
event.returnValue = true;
}
