xcode Swift 3 和 Xcode8 - init 的模糊使用
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Swift 3 and Xcode8 - Ambiguous use of init
提问by theDC
Before I installed Xcode 8 and converted project to Swift 3, the following line was fine. Now after conversion it looks like this:
在我安装 Xcode 8 并将项目转换为 Swift 3 之前，以下行很好。现在转换后它看起来像这样：
let valueData:Data = Data(bytes: UnsafePointer<UInt8>(&intVal), count: sizeof(NSInteger))
it shows the error
它显示错误
Ambiguous use of 'init'
'init' 的歧义使用
what is wrong with it in Swift 3? How to fix it?
Swift 3 有什么问题？如何解决？
采纳答案by Martin R
The easiest way to create Datafrom a simple value is to go via
UnsafeBufferPointer, then you don't need any explicit pointer conversion or size calculation:
Data从简单值创建的最简单方法是通过 via
UnsafeBufferPointer，然后您不需要任何显式指针转换或大小计算：
var intVal = 1000
let data = Data(buffer: UnsafeBufferPointer(start: &intVal, count: 1))
print(data as NSData) // <e8030000 00000000>
For a more generic approach for conversion from values to Dataand back, see for example round trip Swift number types to/from Data.
有关从值到Data和返回的更通用的转换方法，请参阅例如往返 Swift 数字类型到/从 Data。
回答by Jans
UnsafePointerhas initializer for both UnsafePointerand UnsafeMutablePointer, and sizeof was moved to MemoryLayoutdisambiguate it as:
UnsafePointer有初始值都为UnsafePointer和UnsafeMutablePointer，和sizeof被转移到MemoryLayout歧义它：
let valueData = withUnsafePointer(to: &intVal){
return Data(bytes: ##代码##, count: MemoryLayout<NSInteger>.size)
}
