Javascript HttpPostedfileBase 使用 jQuery Ajax 为空

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时间:2020-08-23 01:42:04  来源:igfitidea点击:

HttpPostedfileBase is null using jQuery Ajax

javascriptasp.net-mvc

提问by salar

I have problem with uploading file In Asp.net Mvc. First of all I should use Ajax to pass the upload file value.

我在 Asp.net Mvc 中上传文件时遇到问题。首先我应该使用 Ajax 来传递上传文件的值。

In javascript I have model that I fill it, When I check it with debugger is correctly fill the object, but when I send this model to server (Controller )

在javascript中,我有填充它的模型,当我用调试器检查它时是否正确填充了对象,但是当我将此模型发送到服务器(Controller)时

The httpPostedfileBase value is Always null.

httpPostedfileBase 值始终为空。

I search it on google, in some post I saw that I cant use file uploader with Ajax, but in other I saw that I can.

我在谷歌上搜索它,在一些帖子中我看到我不能在 Ajax 中使用文件上传器,但在其他帖子中我看到我可以。

But I can not fix my Code.

但我无法修复我的代码。

There is my Javascript Code.

有我的 Javascript 代码。

$(document).ready(function () {

$('#btnUploadFile').on('click', function () {
   var data= new FormData();

    debugger;
    var files = $("#fileUpload").get(0).files;

    if (files.length > 0) {
        data.append("UploadedImage", files[0]);
    }
    var ResturantSharingViewModel =
   {
       Type: $("#SharingTargetType").val(),
       SharingTitle: $("#SharingTitle").val(),
       content: $("#Content").val(),
       ItemId : $("#ItemId").val(),
       Photos: files[0]
   };
    $.ajax({
        type: 'POST',
        dataType: 'json',
        contentType: 'application/json',
        url: '<%= Url.Action("SaveOneDatabase")%>',
        data: JSON.stringify(ResturantSharingViewModel),
          success: function (result) {
              var rs = result;
          },
          error: function () {
              alert("Error loading data! Please try again.");
          }
      });

My Controller public virtual bool SaveOneDatabase(ResturantSharingViewModel result) My ResturantSharingViewModel View Model

我的控制器public virtual bool SaveOneDatabase(ResturantSharingViewModel result) 我的 ResturantSharingViewModel 视图模型

 public class ResturantSharingViewModel
{
    public Guid SharingPremiumHistoryID { get; set; }
    public string SharingTitle { get; set; }
    public string Content { get; set; }
    public DateTime AddedDate { get; set; }
    public bool IsSubmit { get; set; }
    public DateTime SubmitedDate { get; set; }
    public IEnumerable<SelectListItem> SharingTypes { get; set; }
    public IEnumerable<SelectListItem> SharingTargetType { get; set; }
    public short Type { get; set; }
    public Guid ItemId { get; set; }
    public HttpPostedFileBase[] Photos { get; set; }
}

My Html Elements

我的 HTML 元素

    <form enctype="multipart/form-data">
    <article>
    <%--<% =Html.BeginForm("Add","PremiumSharing") %>--%>
   <hgroup class="radiogroup">
    <h1>????? ???</h1>
    <%= Html.HiddenFor(model => model.SharingPremiumHistoryID) %>
    <%= Html.HiddenFor(model => model.ItemId) %>
    <div class="group">
        <span> ????? ?? </span>
        <%= Html.DropDownListFor(model => model.SharingTargetType, Model.SharingTypes) %>
    </div>
</hgroup>
<div class="newseditor">
    <div class="input-form">
        <%= Html.LabelFor(model => model.SharingTitle, "????? ???") %>
        <%= Html.TextBoxFor(model => model.SharingTitle) %>
    </div>

    <div class="input-form">
        <%= Html.LabelFor(model => model.Content, "??? ???") %>
        <%= Html.TextAreaFor(model => model.Content) %>
    </div>
    <div><input id="fileUpload" type="file" />

    </div>
    <% if (ViewBag.IsInEditMode != null && !(bool)ViewBag.IsInEditMode)
       {%>
    <div class="input-form">
        <%= Html.CheckBox("SendToInTheCity") %> ????? ?? ??? ??? ???? ???????
    </div>
    <%} %>

    <div class="input-submit">
        <button name="post" id="btnUploadFile"  onclick="uploadFile()" >????? ???</button>
    </div>
    <br />
</div>

采纳答案by Andreas

First, it's possible to upload with Ajax, the important thing is you need to set <form enctype="multipart/form-data"></form>on you form to tell it your form has an file upload input. Then you need to accept HttpPostedFileBaseas an input parameter in your controller action.

首先,可以使用 Ajax 上传,重要的是您需要<form enctype="multipart/form-data"></form>在表单上设置以告诉它您的表单有一个文件上传输入。然后,您需要HttpPostedFileBase在控制器操作中接受作为输入参数。

Try this. Example of jquery upload code. (Taken mostly from How can I upload files asynchronously?)

尝试这个。jquery 上传代码示例。(主要来自如何异步上传文件?

function uploadFile(uploadId) {
    var formData = new FormData($('form')[0]);

    $.ajax({
        url: '<%= Url.Action("SaveOneDatabase")%>',
        type: 'Post',
        beforeSend: function(){},
        success: function(result){

        },
        xhr: function() {  // Custom XMLHttpRequest
        var myXhr = $.ajaxSettings.xhr();
            if(myXhr.upload) { // Check if upload property exists
                // Progress code if you want
            }
            return myXhr;
        },
        error: function(){},
        data: formData,
        cache: false,
        contentType: false,
        processData: false
    });
}

HTML Form needs this attribute. See this post why you need it -> What does enctype='multipart/form-data' mean?

HTML 表单需要这个属性。看到这篇文章你为什么需要它 -> enctype='multipart/form-data' 是什么意思?

enctype="multipart/form-data"

C#

C#

[HttpPost]
public ActionResult SaveOneDatabase(HttpPostedFileBase file)
{
}

回答by a moradi

View:

看法:

<script/>
var add_photo_url = "@Url.Action("AddPhoto", "Gallery")"; 
    var model = new FormData();    
    var i=0;//selected file index 
    model.append("File", files[i]);
    model.append("Name", "test");
    $.ajax({// and other parameter is set here 
        url: add_photo_url,
            type: "POST",
            data: model,
            dataType: "json",
            cache: false,
            contentType: false,
            processData: false

        })
        .always(function (result) { 
        });
</script>

View Model:

查看型号:

public class PhotoAlbumViewModel {
    public  string Name { get; set; }
    public HttpPostedFileBase File { get; set; }
}

Controller:

控制器:

public JsonResult AddPhoto(PhotoAlbumViewModel model) {
    // var result =...
    // and set your result; 
    return Json(result, JsonRequestBehavior.AllowGet);
}

回答by Pratap Singh Mehra

I have modified @a moradi's answer.

我修改了@a moradi 的答案。

JS:

JS:

//FormData:
//Treat it like a normal form but with "multipart/form-data" encoding type.
//Inside it works on same XMLHttpRequest.send() method.    
var model = new FormData();
model.append("File", $('#file')[0].files[0]);
model.append("Name", "Name");
$.ajax({ 
        url: someUrl,
        type: "POST",
        data: model,
        //contentType: 
        //Sets the ContentType in header.
        //The default contentType is "application/x-www-form-urlencoded; charset=UTF-8". But this will prevent us sending AntiForgeryToken to service/controller.
        //To prevent this contentType is set to false.
        contentType: false,
        //processData:
        //To prevent data in data option getting converted to string format, 'processData' option is set to false.
        processData: false,
        success = function (m) {...}
        error = function (m) {...}
    });

View Model:

查看型号:

public class PhotoAlbumViewModel {
    public  string Name { get; set; }
    public HttpPostedFileBase File { get; set; }
}

Controller:

控制器:

public JsonResult AddPhoto(PhotoAlbumViewModel model) {
    ...
}

Refrence:

参考:

Reffer following links for details: FormData, JQuery, ContentType

有关详细信息,请参阅以下链接:FormDataJQueryContentType