我想将 JSONObject 添加到 JSONArray 并且该 JSONArray 包含在其他 JSONObject 中
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I want to add a JSONObject to a JSONArray and that JSONArray included in other JSONObject
提问by Ajka
I need below kind of structure constructed in java and send it as response :
我需要以下在java中构造的结构并将其作为响应发送：
var abc = {"action":"Remove",
"datatable":[
{"userid":"userid0","username":"name0"},
{"userid":"userid1","username":"name1"},
{"userid":"userid2","username":"name2"},
{"userid":"userid3","username":"name3"}
]
,
"msgType":"success"};
I am doing:
我在做：
JSONArray jsonArray = new JSONArray();
for (loop) {
JSONObject jsonObj= new JSONObject();
jsonObj.put("srcOfPhoto", srcOfPhoto);
jsonObj.put("username", "name"+count);
jsonObj.put("userid", "userid"+count);
jsonArray .add(jsonObj.toJSONString());
}
Map paramMap = new HashMap();
paramMap.put("action", "remove");
paramMap.put("datatable", jsonArray );
paramMap.put(Constant.MSG_TYPE , Constant.SUCCESS);
getJSONMessage(paramMap);
and herer above function is converting paramMap into json string like:
上面的函数正在将 paramMap 转换为 json 字符串，例如：
public static String getJSONMessage(Map<String, String> paramMap){
if(paramMap != null && paramMap.size() > 0)
return JSONObject.toJSONString(paramMap);
else
return "";
}
but it is not creating the right structure, can anybody help me in this?
但它没有创建正确的结构，有人可以帮助我吗？
here is what I am getting output:
这是我得到的输出：
{"action":"Remove","datatable":[{\"userid\":\"userid0\",\"srcOfPhoto\":\"users\\/JMMBGTCHG.jpg\",\"username\":\"name0\"}"],"msgType":"success"}
which is not being parsed in javascript.
这不是在 javascript 中解析的。
var json = eval('(' + respText+')');
alert("contents>>"+json.datatable);
alert("contents.datatable[0]>>>"+json.datatable[0].username);
last alert showing undefined.
最后一个警报显示未定义。
ohh sorry I forgot to paste last line , here is the last line:
哦对不起我忘了粘贴最后一行，这是最后一行：
getJSONMessage(paramMap);
and above function is converting paramMap into json string:
以上函数将 paramMap 转换为 json 字符串：
public static String getJSONMessage(Map<String, String> paramMap){
if(paramMap != null && paramMap.size() > 0)
return JSONObject.toJSONString(paramMap);
else
return "";
}
回答by Gon?alo Vieira
JSONArray jsonArray = new JSONArray();
for (loop) {
JSONObject jsonObj= new JSONObject();
jsonObj.put("srcOfPhoto", srcOfPhoto);
jsonObj.put("username", "name"+count);
jsonObj.put("userid", "userid"+count);
jsonArray.put(jsonObj.valueToString());
}
JSONObject parameters = new JSONObject();
parameters.put("action", "remove");
parameters.put("datatable", jsonArray );
parameters.put(Constant.MSG_TYPE , Constant.SUCCESS);
Why were you using an Hashmap if what you wanted was to put it into a JSONObject?
如果您想要将它放入 JSONObject，为什么要使用 Hashmap？
EDIT: As per http://www.json.org/javadoc/org/json/JSONArray.html
编辑：根据http://www.json.org/javadoc/org/json/JSONArray.html
EDIT2: On the JSONObject method used, I'm following the code available at: https://github.com/stleary/JSON-java/blob/master/JSONObject.java#L2327, that method is not deprecated.
EDIT2：在使用的 JSONObject 方法上，我正在关注以下可用代码：https: //github.com/stleary/JSON-java/blob/master/JSONObject.java#L2327，该方法并未被弃用。
We're storing a string representation of the JSONObject, not the JSONObject itself
我们存储的是 JSONObject 的字符串表示，而不是 JSONObject 本身
回答by Vishnu Mari
JSONObject json = new JSONObject();
json.put("fromZIPCode","123456");
JSONObject json1 = new JSONObject();
json1.put("fromZIPCode","123456");
sList.add(json1);
sList.add(json);
System.out.println(sList);
Output will be
[{"fromZIPCode":"123456"},{"fromZIPCode":"123456"}]
回答by sagar varade
JSONArray successObject=new JSONArray();
JSONObject dataObject=new JSONObject();
successObject.put(dataObject.toString());
This works for me.
这对我有用。
回答by Nikhil
org.json.simple.JSONArray resultantJson = new org.json.simple.JSONArray();
org.json.JSONArray o1 = new org.json.JSONArray("[{\"one\":[],\"two\":\"abc\"}]");
org.json.JSONArray o2 = new org.json.JSONArray("[{\"three\":[1,2],\"four\":\"def\"}]");
resultantJson.addAll(o1.toList());
resultantJson.addAll(o2.toList());
